basis-map coefficients of Triangle read by rows: row n consists of n-1 zeros followed by Fibonacci(n).

palindromicγ-positivenonnegative coefficientsonly rational roots

Proved for all n all roots real, in (−∞, 0)coefficients of one signHadamard kernel

Recurrence

\(P_{n}(x) = \left(1 + x\right)\,P_{n-1}(x) + \left(1 + 2\,x + x^{2}\right)\,P_{n-2}(x)\)
\(P_{0}(x) = 1\)
\(P_{1}(x) = 1 + x\)

Rows ?

nx0x1x2x3x4x5x6x7x8x9x10x11x12x13x14Pn(1)
011
1112
22428
3399324
45203020580
58408080408256
613781952601957813832
721147441735735441147212688
834272952190423801904952272348704
9554951980462069306930462019804955528160
10898904005106801869022428186901068040058908991136
111441584792023760475206652866528475202376079201584144294912
122332796153785126011533518453621529218453611533551260153782796233954368
133774901294061078222695554851996469326469324851992695551078222940649013773088384
14610854055510222040610610122122018318302093520183183012212206106102220405551085406109994240
Technical details
Node id
n-ed81f100961f7473 · revision 0 · JSON
Definition source
derived:basis_map_coefficients_of:oeis_catalog:A127647
Fingerprint
f6-77a7ed3b1d5f257e

Observed on the stored rows ?

  • Degrees: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 (affine: slope 1, intercept 0)
  • Palindromic rows: yes
  • γ-positive (gamma_positive): yes
  • Nonnegative coefficients (nonn): yes
  • Only rational roots (rr_by_factors: every nonzero row is a product of linear factors over ℚ): yes

Matches ?

Row sums ? A085449, A063727

Submission text ?

Atlas rows n = 0, …, ascending powers of x
%e Example
Triangle begins:
  0:  1;
  1:  1,   1;
  2:  2,   4,    2;
  3:  3,   9,    9,    3;
  4:  5,  20,   30,   20,    5;
  5:  8,  40,   80,   80,   40,    8;
  6: 13,  78,  195,  260,  195,   78,   13;
  7: 21, 147,  441,  735,  735,  441,  147,   21;
  8: 34, 272,  952, 1904, 2380, 1904,  952,  272,  34;
  9: 55, 495, 1980, 4620, 6930, 6930, 4620, 1980, 495, 55;
%F Formula
The row polynomials satisfy P(n,x) = (1+x)*P(n-1,x) + (1+2*x+x^2)*P(n-2,x) for n >= 2, with P(0,x) = 1, P(1,x) = 1 + x.
%t Mathematica
P[0, x_] := 1;
P[1, x_] := 1 + x;
P[n_, x_] := P[n, x] = Expand[(1 + x)*P[n - 1, x] + (1 + 2*x + x^2)*P[n - 2, x]];
Table[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten
%o PARI/GP
P(N) = {my(v = vector(N + 1)); v[1] = 1; v[2] = 1 + x; for(n = 2, N, my(i = n + 1); v[i] = (1 + x)*v[i - 1] + (1 + 2*x + x^2)*v[i - 2]); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)

polytool c48629374597

A016095 triangle, offset 0, from P0
%e Example
Triangle begins:
  0:  1;
  1:  1,   1;
  2:  2,   4,    2;
  3:  3,   9,    9,    3;
  4:  5,  20,   30,   20,    5;
  5:  8,  40,   80,   80,   40,    8;
  6: 13,  78,  195,  260,  195,   78,   13;
  7: 21, 147,  441,  735,  735,  441,  147,   21;
  8: 34, 272,  952, 1904, 2380, 1904,  952,  272,  34;
  9: 55, 495, 1980, 4620, 6930, 6930, 4620, 1980, 495, 55;
%F Formula
The row polynomials satisfy P(n,x) = (1+x)*P(n-1,x) + (1+2*x+x^2)*P(n-2,x) for n >= 2, with P(0,x) = 1, P(1,x) = 1 + x.
%t Mathematica
P[0, x_] := 1;
P[1, x_] := 1 + x;
P[n_, x_] := P[n, x] = Expand[(1 + x)*P[n - 1, x] + (1 + 2*x + x^2)*P[n - 2, x]];
Table[PadRight[CoefficientList[P[n, x], x], n + 1], {n, 0, 9}] // Flatten
%o PARI/GP
P(N) = {my(v = vector(N + 1)); v[1] = 1; v[2] = 1 + x; for(n = 2, N, my(i = n + 1); v[i] = (1 + x)*v[i - 1] + (1 + 2*x + x^2)*v[i - 2]); v};
row(n, p) = {my(c = Vecrev(p)); c = concat(c, vector(n + 1 - #c)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)

polytool c48629374597

A016095 reversed triangle, offset 0, from P0
%e Example
Triangle begins:
  0:  1;
  1:  1,   1;
  2:  2,   4,    2;
  3:  3,   9,    9,    3;
  4:  5,  20,   30,   20,    5;
  5:  8,  40,   80,   80,   40,    8;
  6: 13,  78,  195,  260,  195,   78,   13;
  7: 21, 147,  441,  735,  735,  441,  147,   21;
  8: 34, 272,  952, 1904, 2380, 1904,  952,  272,  34;
  9: 55, 495, 1980, 4620, 6930, 6930, 4620, 1980, 495, 55;
%F Formula
Row n lists the coefficients of P(n,x) in descending powers of x, where P(n,x) = (1+x)*P(n-1,x) + (1+2*x+x^2)*P(n-2,x) for n >= 2, with P(0,x) = 1, P(1,x) = 1 + x.
%t Mathematica
P[0, x_] := 1;
P[1, x_] := 1 + x;
P[n_, x_] := P[n, x] = Expand[(1 + x)*P[n - 1, x] + (1 + 2*x + x^2)*P[n - 2, x]];
Table[Reverse[PadRight[CoefficientList[P[n, x], x], n + 1]], {n, 0, 9}] // Flatten
%o PARI/GP
P(N) = {my(v = vector(N + 1)); v[1] = 1; v[2] = 1 + x; for(n = 2, N, my(i = n + 1); v[i] = (1 + x)*v[i - 1] + (1 + 2*x + x^2)*v[i - 2]); v};
row(n, p) = {my(c = Vecrev(p)); c = concat(c, vector(n + 1 - #c)); c = Vecrev(c); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)

polytool c48629374597

Properties

Proof chains ? JSON

Same fingerprint ?

References

  1. [Bra15] Petter Brändén. Unimodality, log-concavity, real-rootedness and beyond. Handbook of enumerative combinatorics, :437–483, March 2015. doi:10.1201/b18255-10
  2. [SP14] J Schur and G Polya. Über zwei Arten von Faktorenfolgen in der Theorie der algebraischen Gleichungen. J. Reine Angew. Math., 1914.