A134346: Triangle read by rows: T(n,k) = (2^(n+1)-1)*binomial(n,k).

A134346 ↗ palindromicγ-positivenonnegative coefficientsonly rational roots

Proved for all n all roots real, in (−∞, 0)coefficients of one signHadamard kernelinterlacing (weak)

Recurrence from A134346

\(P_{n}(x) = \left(3 + 3\,x\right)\,P_{n-1}(x) + \left(-2 - 4\,x - 2\,x^{2}\right)\,P_{n-2}(x)\)
\(P_{0}(x) = 1\)
\(P_{1}(x) = 3 + 3\,x\)

Rows ?

nx0x1x2x3x4x5x6x7Pn(1)
011
1336
2714728
315454515120
43112418612431496
563315630630315632016
61277621905254019057621278128
725517855355892589255355178525532640
Technical details
Node id
n-8d96419786c3ee2a · revision 0 · JSON
Definition source
oeis_catalog:A134346
Fingerprint
f6-77a7ed3b1d5f257e

Observed on the stored rows ?

  • Degrees: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 (affine: slope 1, intercept 0)
  • Palindromic rows: yes
  • γ-positive (gamma_positive): yes
  • Nonnegative coefficients (nonn): yes
  • Only rational roots (rr_by_factors: every nonzero row is a product of linear factors over ℚ): yes

Matches ?

  • A134346 reversed triangle 45 terms, 9 rows · tabl · nonn · catalog b-file?
  • A134346 triangle 45 terms, 9 rows · tabl · nonn · catalog b-file?

Row sums ? A006516, A171496, A171476

Submission text ?

Atlas rows n = 0, …, ascending powers of x
%e Example
Triangle begins:
  0:    1;
  1:    3,    3;
  2:    7,   14,     7;
  3:   15,   45,    45,    15;
  4:   31,  124,   186,   124,     31;
  5:   63,  315,   630,   630,    315,     63;
  6:  127,  762,  1905,  2540,   1905,    762,   127;
  7:  255, 1785,  5355,  8925,   8925,   5355,  1785,   255;
  8:  511, 4088, 14308, 28616,  35770,  28616, 14308,  4088,  511;
  9: 1023, 9207, 36828, 85932, 128898, 128898, 85932, 36828, 9207, 1023;
%F Formula
The row polynomials satisfy P(n,x) = (3+3*x)*P(n-1,x) - (2+4*x+2*x^2)*P(n-2,x) for n >= 2, with P(0,x) = 1, P(1,x) = 3 + 3*x.
%t Mathematica
P[0, x_] := 1;
P[1, x_] := 3 + 3*x;
P[n_, x_] := P[n, x] = Expand[(3 + 3*x)*P[n - 1, x] - (2 + 4*x + 2*x^2)*P[n - 2, x]];
Table[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten
%o PARI/GP
P(N) = {my(v = vector(N + 1)); v[1] = 1; v[2] = 3 + 3*x; for(n = 2, N, my(i = n + 1); v[i] = (3 + 3*x)*v[i - 1] - (2 + 4*x + 2*x^2)*v[i - 2]); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)

polytool c48629374597

A134346 triangle, offset 0, from P0
%e Example
Triangle begins:
  0:    1;
  1:    3,    3;
  2:    7,   14,     7;
  3:   15,   45,    45,    15;
  4:   31,  124,   186,   124,     31;
  5:   63,  315,   630,   630,    315,     63;
  6:  127,  762,  1905,  2540,   1905,    762,   127;
  7:  255, 1785,  5355,  8925,   8925,   5355,  1785,   255;
  8:  511, 4088, 14308, 28616,  35770,  28616, 14308,  4088,  511;
  9: 1023, 9207, 36828, 85932, 128898, 128898, 85932, 36828, 9207, 1023;
%F Formula
The row polynomials satisfy P(n,x) = (3+3*x)*P(n-1,x) - (2+4*x+2*x^2)*P(n-2,x) for n >= 2, with P(0,x) = 1, P(1,x) = 3 + 3*x.
%t Mathematica
P[0, x_] := 1;
P[1, x_] := 3 + 3*x;
P[n_, x_] := P[n, x] = Expand[(3 + 3*x)*P[n - 1, x] - (2 + 4*x + 2*x^2)*P[n - 2, x]];
Table[PadRight[CoefficientList[P[n, x], x], n + 1], {n, 0, 9}] // Flatten
%o PARI/GP
P(N) = {my(v = vector(N + 1)); v[1] = 1; v[2] = 3 + 3*x; for(n = 2, N, my(i = n + 1); v[i] = (3 + 3*x)*v[i - 1] - (2 + 4*x + 2*x^2)*v[i - 2]); v};
row(n, p) = {my(c = Vecrev(p)); c = concat(c, vector(n + 1 - #c)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)

polytool c48629374597

A134346 reversed triangle, offset 0, from P0
%e Example
Triangle begins:
  0:    1;
  1:    3,    3;
  2:    7,   14,     7;
  3:   15,   45,    45,    15;
  4:   31,  124,   186,   124,     31;
  5:   63,  315,   630,   630,    315,     63;
  6:  127,  762,  1905,  2540,   1905,    762,   127;
  7:  255, 1785,  5355,  8925,   8925,   5355,  1785,   255;
  8:  511, 4088, 14308, 28616,  35770,  28616, 14308,  4088,  511;
  9: 1023, 9207, 36828, 85932, 128898, 128898, 85932, 36828, 9207, 1023;
%F Formula
Row n lists the coefficients of P(n,x) in descending powers of x, where P(n,x) = (3+3*x)*P(n-1,x) - (2+4*x+2*x^2)*P(n-2,x) for n >= 2, with P(0,x) = 1, P(1,x) = 3 + 3*x.
%t Mathematica
P[0, x_] := 1;
P[1, x_] := 3 + 3*x;
P[n_, x_] := P[n, x] = Expand[(3 + 3*x)*P[n - 1, x] - (2 + 4*x + 2*x^2)*P[n - 2, x]];
Table[Reverse[PadRight[CoefficientList[P[n, x], x], n + 1]], {n, 0, 9}] // Flatten
%o PARI/GP
P(N) = {my(v = vector(N + 1)); v[1] = 1; v[2] = 3 + 3*x; for(n = 2, N, my(i = n + 1); v[i] = (3 + 3*x)*v[i - 1] - (2 + 4*x + 2*x^2)*v[i - 2]); v};
row(n, p) = {my(c = Vecrev(p)); c = concat(c, vector(n + 1 - #c)); c = Vecrev(c); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)

polytool c48629374597

Properties

Proof chains ? JSON

  • Liu–Wang theorem for three-term recurrences [LW07, Thm 2.1, Thm 2.3, Cor 2.4, Prop 3.3] polytool ? step › direct check

Same fingerprint ?

References

  1. [LW07] Lily L. Liu and Yi Wang. A unified approach to polynomial sequences with only real zeros. Advances in Applied Mathematics, 38(4):542–560, May 2007. doi:10.1016/j.aam.2006.02.003