A153518: Triangular T(n,k) = T(n-1, k) + T(n-1, k-1) + 5*T(n-2, k-1), read by rows.

A153518 ↗ palindromicγ-positivenonnegative coefficients

Proved for all n all roots real, in (−∞, 0)coefficients of one signHadamard kernelinterlacinginterlacing (weak)

Recurrence from A153518

\(\left(-3 + n\right)\,P_{n}(x) = \left(-3 - 3\,x + n + n x\right)\,P_{n-1}(x) + \left(-15\,x + 5\,n x\right)\,P_{n-2}(x)\)
\(P_{0}(x) = 2\)
\(P_{1}(x) = 5 + 5\,x\)
\(P_{2}(x) = 2 + 46\,x + 2\,x^{2}\)
\(P_{3}(x) = 2 + 123\,x + 123\,x^{2} + 2\,x^{3}\)

Rows ?

nx0x1x2x3x4x5x6x7x8x9x10x11x12x13x14Pn(1)
022
15510
2246250
321231232250
421354761352750
521471226122614722750
6215920484832204815929250
72171294213010130102942171232250
82183390826192501802619239081832110750
921954946448101414221414224481049461952382750
10220760566929631719253374431719269296605620721319250
112219723810008261053815580461558046610538100082723821924552250
1222318492137600105710037545445784812375454410571001376008492231215700750
1322439818182282169511078643341732958617329586786433416951101822829818243254162750
14225511216234560256539214844944439666406358323243966640148449442565392234560112162552186829250
Technical details
Node id
n-a44eea8c1f4cf4e5 · revision 0 · JSON
Definition source
oeis_catalog:A153518
Fingerprint
f6-e3edd843f2595689

Observed on the stored rows ?

  • Degrees: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 (affine: slope 1, intercept 0)
  • Palindromic rows: yes
  • γ-positive (gamma_positive): yes
  • Nonnegative coefficients (nonn): yes
  • Only rational roots (rr_by_factors: every nonzero row is a product of linear factors over ℚ): no

Matches ?

  • A153518 reversed triangle 55 terms, 10 rows · tabl · nonn · catalog b-file?
  • A153518 triangle 55 terms, 10 rows · tabl · nonn · catalog b-file?

Submission text ?

Atlas rows n = 0, …, ascending powers of x
%e Example
Triangle begins:
  0: 2;
  1: 5,   5;
  2: 2,  46,    2;
  3: 2, 123,  123,     2;
  4: 2, 135,  476,   135,      2;
  5: 2, 147, 1226,  1226,    147,      2;
  6: 2, 159, 2048,  4832,   2048,    159,     2;
  7: 2, 171, 2942, 13010,  13010,   2942,   171,    2;
  8: 2, 183, 3908, 26192,  50180,  26192,  3908,  183,   2;
  9: 2, 195, 4946, 44810, 141422, 141422, 44810, 4946, 195, 2;
%F Formula
The row polynomials satisfy (n-3)*P(n,x) = (n-3+(n-3)*x)*P(n-1,x) + (5*n-15)*x*P(n-2,x) for n >= 4, with P(0,x) = 2, P(1,x) = 5 + 5*x, P(2,x) = 2 + 46*x + 2*x^2, P(3,x) = 2 + 123*x + 123*x^2 + 2*x^3.
%t Mathematica
P[0, x_] := 2;
P[1, x_] := 5 + 5*x;
P[2, x_] := 2 + 46*x + 2*x^2;
P[3, x_] := 2 + 123*x + 123*x^2 + 2*x^3;
P[n_, x_] := P[n, x] = Expand[Together[((n - 3 + (n - 3)*x)*P[n - 1, x] + (5*n - 15)*x*P[n - 2, x])/(n - 3)]];
Table[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten
%o PARI/GP
P(N) = {my(v = vector(N + 1)); v[1] = 2; v[2] = 5 + 5*x; v[3] = 2 + 46*x + 2*x^2; v[4] = 2 + 123*x + 123*x^2 + 2*x^3; for(n = 4, N, my(i = n + 1); v[i] = ((n - 3 + (n - 3)*x)*v[i - 1] + (5*n - 15)*x*v[i - 2])/(n - 3)); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)

polytool c48629374597

A153518 triangle, offset 1, from P0
%e Example
Triangle begins:
   1: 2;
   2: 5,   5;
   3: 2,  46,    2;
   4: 2, 123,  123,     2;
   5: 2, 135,  476,   135,      2;
   6: 2, 147, 1226,  1226,    147,      2;
   7: 2, 159, 2048,  4832,   2048,    159,     2;
   8: 2, 171, 2942, 13010,  13010,   2942,   171,    2;
   9: 2, 183, 3908, 26192,  50180,  26192,  3908,  183,   2;
  10: 2, 195, 4946, 44810, 141422, 141422, 44810, 4946, 195, 2;
%F Formula
The row polynomials satisfy (n-4)*P(n,x) = (n-4+(n-4)*x)*P(n-1,x) + (5*n-20)*x*P(n-2,x) for n >= 5, with P(1,x) = 2, P(2,x) = 5 + 5*x, P(3,x) = 2 + 46*x + 2*x^2, P(4,x) = 2 + 123*x + 123*x^2 + 2*x^3.
%t Mathematica
P[1, x_] := 2;
P[2, x_] := 5 + 5*x;
P[3, x_] := 2 + 46*x + 2*x^2;
P[4, x_] := 2 + 123*x + 123*x^2 + 2*x^3;
P[n_, x_] := P[n, x] = Expand[Together[((n - 4 + (n - 4)*x)*P[n - 1, x] + (5*n - 20)*x*P[n - 2, x])/(n - 4)]];
Table[PadRight[CoefficientList[P[n, x], x], n], {n, 1, 10}] // Flatten
%o PARI/GP
P(N) = {my(v = vector(N)); v[1] = 2; v[2] = 5 + 5*x; v[3] = 2 + 46*x + 2*x^2; v[4] = 2 + 123*x + 123*x^2 + 2*x^3; for(n = 5, N, my(i = n); v[i] = ((n - 4 + (n - 4)*x)*v[i - 1] + (5*n - 20)*x*v[i - 2])/(n - 4)); v};
row(n, p) = {my(c = Vecrev(p)); c = concat(c, vector(n - #c)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i, v[i])))};
T(10)

polytool c48629374597

A153518 reversed triangle, offset 1, from P0
%e Example
Triangle begins:
   1: 2;
   2: 5,   5;
   3: 2,  46,    2;
   4: 2, 123,  123,     2;
   5: 2, 135,  476,   135,      2;
   6: 2, 147, 1226,  1226,    147,      2;
   7: 2, 159, 2048,  4832,   2048,    159,     2;
   8: 2, 171, 2942, 13010,  13010,   2942,   171,    2;
   9: 2, 183, 3908, 26192,  50180,  26192,  3908,  183,   2;
  10: 2, 195, 4946, 44810, 141422, 141422, 44810, 4946, 195, 2;
%F Formula
Row n lists the coefficients of P(n,x) in descending powers of x, where (n-4)*P(n,x) = (n-4+(n-4)*x)*P(n-1,x) + (5*n-20)*x*P(n-2,x) for n >= 5, with P(1,x) = 2, P(2,x) = 5 + 5*x, P(3,x) = 2 + 46*x + 2*x^2, P(4,x) = 2 + 123*x + 123*x^2 + 2*x^3.
%t Mathematica
P[1, x_] := 2;
P[2, x_] := 5 + 5*x;
P[3, x_] := 2 + 46*x + 2*x^2;
P[4, x_] := 2 + 123*x + 123*x^2 + 2*x^3;
P[n_, x_] := P[n, x] = Expand[Together[((n - 4 + (n - 4)*x)*P[n - 1, x] + (5*n - 20)*x*P[n - 2, x])/(n - 4)]];
Table[Reverse[PadRight[CoefficientList[P[n, x], x], n]], {n, 1, 10}] // Flatten
%o PARI/GP
P(N) = {my(v = vector(N)); v[1] = 2; v[2] = 5 + 5*x; v[3] = 2 + 46*x + 2*x^2; v[4] = 2 + 123*x + 123*x^2 + 2*x^3; for(n = 5, N, my(i = n); v[i] = ((n - 4 + (n - 4)*x)*v[i - 1] + (5*n - 20)*x*v[i - 2])/(n - 4)); v};
row(n, p) = {my(c = Vecrev(p)); c = concat(c, vector(n - #c)); c = Vecrev(c); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i, v[i])))};
T(10)

polytool c48629374597

Properties

Proof chains ? JSON

Used in 5

References

  1. [LW07] Lily L. Liu and Yi Wang. A unified approach to polynomial sequences with only real zeros. Advances in Applied Mathematics, 38(4):542–560, May 2007. doi:10.1016/j.aam.2006.02.003