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v[1] = 2; v[2] = 5 + 5*x; v[3] = 2 + 46*x + 2*x^2; v[4] = 2 + 123*x + 123*x^2 + 2*x^3; for(n = 5, N, my(i = n); v[i] = ((n - 4 + (n - 4)*x)*v[i - 1] + (5*n - 20)*x*v[i - 2])/(n - 4)); v};\nrow(n, p) = {my(c = Vecrev(p)); c = concat(c, vector(n - #c)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i, v[i])))};\nT(10)","reading":{"first_row":0,"offset":1,"reversed":false,"trim_zeros":"none","regular_triangle":true}},{"oeis_id":"A153518","target":"reversed_triangle","first_row":0,"oeis_offset":1,"reversed":true,"trim_zeros":"none","regular_triangle":true,"rows_shown":10,"polytool_commit":"c48629374597092cc41ef4d6273f37991516f984","triangle_example":"Triangle begins:\n   1: 2;\n   2: 5,   5;\n   3: 2,  46,    2;\n   4: 2, 123,  123,     2;\n   5: 2, 135,  476,   135,      2;\n   6: 2, 147, 1226,  1226,    147,      2;\n   7: 2, 159, 2048,  4832,   2048,    159,     2;\n   8: 2, 171, 2942, 13010,  13010,   2942,   171,    2;\n   9: 2, 183, 3908, 26192,  50180,  26192,  3908,  183,   2;\n  10: 2, 195, 4946, 44810, 141422, 141422, 44810, 4946, 195, 2;\n","recurrence_sentence":"Row n lists the coefficients of P(n,x) in descending powers of x, where (n-4)*P(n,x) = (n-4+(n-4)*x)*P(n-1,x) + (5*n-20)*x*P(n-2,x) for n >= 5, with P(1,x) = 2, P(2,x) = 5 + 5*x, P(3,x) = 2 + 46*x + 2*x^2, P(4,x) = 2 + 123*x + 123*x^2 + 2*x^3.","mathematica":"P[1, x_] := 2;\nP[2, x_] := 5 + 5*x;\nP[3, x_] := 2 + 46*x + 2*x^2;\nP[4, x_] := 2 + 123*x + 123*x^2 + 2*x^3;\nP[n_, x_] := P[n, x] = Expand[Together[((n - 4 + (n - 4)*x)*P[n - 1, x] + (5*n - 20)*x*P[n - 2, x])/(n - 4)]];\nTable[Reverse[PadRight[CoefficientList[P[n, x], x], n]], {n, 1, 10}] // Flatten","pari":"P(N) = {my(v = vector(N)); 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