A153518 → basis A007318
nonnegative coefficients
Proved for all n all roots real, in (−∞, 0]coefficients of one signHadamard kernelinterlacing (weak)
Recurrence
\(\left(-3 + n\right)\,P_{n}(x) = \left(-15 - 15\,x + 5\,n + 5\,n x\right)\,P_{n-2}(x) + \left(-6 - 3\,x + 2\,n + n x\right)\,P_{n-1}(x)\)
\(P_{0}(x) = 2\)
\(P_{1}(x) = 10 + 5\,x\)
\(P_{2}(x) = 50 + 50\,x + 2\,x^{2}\)
\(P_{3}(x) = 250 + 375\,x + 129\,x^{2} + 2\,x^{3}\)
Rows ?
| n | x0 | x1 | x2 | x3 | x4 | x5 | x6 | x7 | Pn(1) |
|---|---|---|---|---|---|---|---|---|---|
| 0 | 2 | 2 | |||||||
| 1 | 10 | 5 | 15 | ||||||
| 2 | 50 | 50 | 2 | 102 | |||||
| 3 | 250 | 375 | 129 | 2 | 756 | ||||
| 4 | 750 | 1500 | 893 | 143 | 2 | 3288 | |||
| 5 | 2750 | 6875 | 5806 | 1834 | 157 | 2 | 17424 | ||
| 6 | 9250 | 27750 | 30452 | 14654 | 2873 | 171 | 2 | 85152 | |
| 7 | 32250 | 112875 | 152059 | 97960 | 30355 | 4010 | 185 | 2 | 429696 |
Compute more
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Technical details
- Node id
n-66e9d524a577c885· revision 0 · JSON- Definition source
derived:basis_map_A007318- Fingerprint
f6-98d6195e3aed088b
Observed on the stored rows ?
- Degrees: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 (affine: slope 1, intercept 0)
- Palindromic rows: no
- γ-positive (gamma_positive): no
- Nonnegative coefficients (
nonn): yes - Only rational roots (
rr_by_factors: every nonzero row is a product of linear factors over ℚ): no
Matches ?
No OEIS matches.
Submission text ?
Atlas rows n = 0, …, ascending powers of x
%e ExampleTriangle begins: 0: 2; 1: 10, 5; 2: 50, 50, 2; 3: 250, 375, 129, 2; 4: 750, 1500, 893, 143, 2; 5: 2750, 6875, 5806, 1834, 157, 2; 6: 9250, 27750, 30452, 14654, 2873, 171, 2; 7: 32250, 112875, 152059, 97960, 30355, 4010, 185, 2; 8: 110750, 443000, 708003, 573509, 246305, 53595, 5245, 199, 2; 9: 382750, 1722375, 3183676, 3105116, 1707694, 525320, 85060, 6578, 213, 2;
%F FormulaThe row polynomials satisfy (n-3)*P(n,x) = (5*n-15+(5*n-15)*x)*P(n-2,x) + (2*n-6+(n-3)*x)*P(n-1,x) for n >= 4, with P(0,x) = 2, P(1,x) = 10 + 5*x, P(2,x) = 50 + 50*x + 2*x^2, P(3,x) = 250 + 375*x + 129*x^2 + 2*x^3.
%t MathematicaP[0, x_] := 2;
P[1, x_] := 10 + 5*x;
P[2, x_] := 50 + 50*x + 2*x^2;
P[3, x_] := 250 + 375*x + 129*x^2 + 2*x^3;
P[n_, x_] := P[n, x] = Expand[Together[((5*n - 15 + (5*n - 15)*x)*P[n - 2, x] + (2*n - 6 + (n - 3)*x)*P[n - 1, x])/(n - 3)]];
Table[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten%o PARI/GPP(N) = {my(v = vector(N + 1)); v[1] = 2; v[2] = 10 + 5*x; v[3] = 50 + 50*x + 2*x^2; v[4] = 250 + 375*x + 129*x^2 + 2*x^3; for(n = 4, N, my(i = n + 1); v[i] = ((5*n - 15 + (5*n - 15)*x)*v[i - 2] + (2*n - 6 + (n - 3)*x)*v[i - 1])/(n - 3)); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)polytool c48629374597
Properties
- Real-rooted? Every row P_n, n ≥ 0, is zero or real-rooted with all roots in (−∞, 0]
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Coefficients of one sign?
Every nonzero row, n ≥ 0: the coefficients of P_n have one sign
derived from Geometric basis map (elementary)
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Hadamard kernel (Malo)?
Rows P_n, n ≥ 0, are Hadamard kernels (preserve real-rootedness)
derived from Geometric basis map (elementary)
- Interlacing of consecutive rows? Rows P_(m-1), P_m interlace (weak, unordered) for every m ≥ 3
Proof chains ? JSON
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Geometric basis map (elementary) polytool ? step ›
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from
Triangular T(n,k) = T(n-1, k) + T(n-1, k-1) + 5*T(n-2, k-1), read by rows.?
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Liu–Wang theorem with a lag row [LW07, Thm 2.1] RealRooted ? step › direct check
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from
Triangular T(n,k) = T(n-1, k) + T(n-1, k-1) + 5*T(n-2, k-1), read by rows.?
References
- [LW07] Lily L. Liu and Yi Wang. A unified approach to polynomial sequences with only real zeros. Advances in Applied Mathematics, 38(4):542–560, May 2007. doi:10.1016/j.aam.2006.02.003