A102547: Triangle read by rows, formed from antidiagonals of the antidiagonals (A011973) of Pascal's triangle (A007318).
A102547 nonnegative coefficients
Proved for all n: all roots real, in (−∞, 0] · coefficients of one sign · interlacing (weak) · Hadamard kernel what this means
Rows ?
| n | x0 | x1 | x2 | Pn(1) |
|---|---|---|---|---|
| 0 | 1 | 1 | ||
| 1 | 1 | 1 | ||
| 2 | 1 | 1 | ||
| 3 | 1 | 1 | 2 | |
| 4 | 1 | 2 | 3 | |
| 5 | 1 | 3 | 4 | |
| 6 | 1 | 4 | 1 | 6 |
| 7 | 1 | 5 | 3 | 9 |
Generated b-files: A000930 (row sums), A068921 (row sums), A102547 ?
Computed in your browser ?
Other recurrences
Reversed rows · proved equal for all n (proof step)
Technical details
- Node id
n-0d55e0bb3c384646· revision 2 · JSON- Definition source
oeis_catalog:A102547derived:reversal(equal bye-9288ac896b9000e4)- Fingerprint
f6-00788a960ffaf339
Observed on the stored rows ?
- Degrees: 0, 0, 0, 1, 1, 1, 2, 2, 2, 3, 3, 3, 4, 4, 4 (irregular)
- Palindromic rows: no
- γ-positive (gamma_positive): no
- Nonnegative coefficients (
nonn): yes - Only rational roots (
rr_by_factors: every nonzero row is a product of linear factors over ℚ): no
OEIS matches ?
- A102547: triangle, 45 terms agree, 15 full rows row lengths from the atlas (tabf) OEIS nonn in polytool catalog · view at the OEIS · generated b-file 1001 terms from n = 0 ?
- A000930: row sums, 15 terms agree OEIS nonn (row-sum match: finite agreement only) · view at the OEIS · generated b-file 200 terms from n = 0 ?
- A078012: row sums, 15 terms agree OEIS nonn (row-sum match: finite agreement only) · view at the OEIS
- A068921: row sums, 14 terms agree OEIS nonn (row-sum match: finite agreement only) · view at the OEIS · generated b-file 200 terms from n = 0 ?
A generated b-file is computed from the node's definition along the row alignment of its OEIS link and starts at the entry's offset. It is an identification on a finite prefix, not a proof that the node and the OEIS entry agree for every n.
OEIS submission text ?
Fields to paste into an OEIS submission: the example %e, the formula
%F and programs %t (Mathematica) and %o (PARI/GP) that list the same rows.
For an OEIS link the row numbers, the offset and the orientation are those of the entry, as matched;
the matched terms were compared with the published ones, which identifies the node with the entry on a
finite prefix, not for every n. The PARI/GP program is not machine-checked here.
The atlas's own rows: n = 0, …, ascending powers of x
%e ExampleTriangle begins: 0: 1; 1: 1; 2: 1; 3: 1, 1; 4: 1, 2; 5: 1, 3; 6: 1, 4, 1; 7: 1, 5, 3; 8: 1, 6, 6; 9: 1, 7, 10, 1;
%F FormulaThe row polynomials satisfy P(n,x) = P(n-1,x) + x*P(n-3,x) for n >= 3, with P(0,x) = 1, P(1,x) = 1, P(2,x) = 1.
%t MathematicaP[0, x_] := 1;
P[1, x_] := 1;
P[2, x_] := 1;
P[n_, x_] := P[n, x] = Expand[P[n - 1, x] + x*P[n - 3, x]];
Table[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten%o PARI/GPP(N) = {my(v = vector(N + 1)); v[1] = 1; v[2] = 1; v[3] = 1; for(n = 3, N, my(i = n + 1); v[i] = v[i - 1] + x*v[i - 3]); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)Generated with polytool c48629374597.
A102547: triangle, offset 0, from the row P0
%e ExampleTriangle begins: 0: 1; 1: 1; 2: 1; 3: 1, 1; 4: 1, 2; 5: 1, 3; 6: 1, 4, 1; 7: 1, 5, 3; 8: 1, 6, 6; 9: 1, 7, 10, 1;
%F FormulaThe row polynomials satisfy P(n,x) = P(n-1,x) + x*P(n-3,x) for n >= 3, with P(0,x) = 1, P(1,x) = 1, P(2,x) = 1.
%t MathematicaP[0, x_] := 1;
P[1, x_] := 1;
P[2, x_] := 1;
P[n_, x_] := P[n, x] = Expand[P[n - 1, x] + x*P[n - 3, x]];
Table[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten%o PARI/GPP(N) = {my(v = vector(N + 1)); v[1] = 1; v[2] = 1; v[3] = 1; for(n = 3, N, my(i = n + 1); v[i] = v[i - 1] + x*v[i - 3]); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)Generated with polytool c48629374597.
Proved properties
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Real-rooted. Every row P_n, n >= 0, is zero or real-rooted with all roots in (-inf, 0]
Every polynomial of the sequence has only real roots, inside the stated interval.by the cited steps:
e-9cfbf7a52f4ba322,e-eef18680cd27a7c9 -
Coefficients of one sign. Every nonzero row, n >= 0: the coefficients of P_n have one sign
All coefficients of each polynomial have the same sign (after x -> -x when alternating).derived from the cited steps by a stated theorem:
e-9cfbf7a52f4ba322,e-eef18680cd27a7c9 -
Hadamard kernel (Malo). Rows P_n, n >= 0, are Hadamard kernels (preserve real-rootedness)
Multiplying the coefficients of any real-rooted polynomial termwise by those of a row (Hadamard product) gives a real-rooted polynomial again.derived from the cited steps by a stated theorem:
e-9cfbf7a52f4ba322,e-eef18680cd27a7c9 -
Interlacing of consecutive rows. Rows P_(m-1), P_m interlace (weak, previous interlaces next) for every m >= 1
The roots of consecutive polynomials alternate on the real line.by the cited steps:
e-eef18680cd27a7c9
Proof chains
3 incoming proof steps. Each step is expanded back to the roots of the proof DAG, the theorem checks of a node's own rule. JSON
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definition_equality
e-9288ac896b9000e4root: theorem checkOre-algebra identity of two definitions polytool ?
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parent_provers paper_theorem
e-eef18680cd27a7c9root: theorem checkParent-row provers of polytool polytool ?
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preserver_image reversal, shift 0
e-9cfbf7a52f4ba322Affine, reversal and Möbius substitutions (elementary) polytool ?
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premise (sequence):
Square array read by antidiagonals downwards: T(n,k), n>=0, k>=0, in which column 0 is equal to A057427: 0, 1, 1, 1, ..…
uses: Every row P_n, n >= 0, is zero or real-rooted with all roots in (-inf, 0]
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preserver_image reversal, shift 0
e-0e9e334768ea0a35Affine, reversal and Möbius substitutions (elementary) polytool ?
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premise (sequence):
Triangle read by rows, formed from antidiagonals of the antidiagonals (A011973) of Pascal's triangle (A007318).
uses: Every row P_n, n >= 0, is zero or real-rooted with all roots in (-inf, 0]
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premise (sequence):
Triangle read by rows, formed from antidiagonals of the antidiagonals (A011973) of Pascal's triangle (A007318).
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premise (sequence):
Square array read by antidiagonals downwards: T(n,k), n>=0, k>=0, in which column 0 is equal to A057427: 0, 1, 1, 1, ..…
Used in 9 proof steps
e-2461a7f1545a7610basis_map (A008277) → basis_map_A008277 of Triangle read by rows, formed from antidiagonals of the antidiagonal…e-82b4d7baf7961b16basis_map (A013609) → basis_map_A013609 of Triangle read by rows, formed from antidiagonals of the antidiagonal…e-ac961eccb8b6d01bbasis_map (A007318) → shift_x_plus_one of Triangle read by rows, formed from antidiagonals of the antidiagonals…e-f413e745ff3e72cbbasis_map (A013610) → basis_map_A013610 of Triangle read by rows, formed from antidiagonals of the antidiagonal…e-f9ff31509ec6911fbasis_map (A013611) → basis_map_A013611 of Triangle read by rows, formed from antidiagonals of the antidiagonal…e-0e9e334768ea0a35preserver_image (reversal, shift 0) → Square array read by antidiagonals downwards: T(n,k), n>=0, k>=0, in which column 0 is eq…e-726c0b03589eafe2preserver_image (affine, shift 0) → Triangle read by rows: T(n,k) is the number of binary sequences of length n containing k …e-8e4f8cf0a7ba3e7cpreserver_image (affine, shift 0) → shift_x_plus_one of Triangle read by rows, formed from antidiagonals of the antidiagonals…e-b8d37b5fe37403cfpreserver_image (affine, shift 0) → Triangle T(n,k) = 3*T(n-1,k) + T(n-3,k-1) for k = 0..floor(n/3) with T(0,0) = 1 and T(n,…
Related sequences ?
Same fingerprint (1)
Equal up to content, sign, reversal and a small index shift.