A317497: Triangle T(n,k) = 3*T(n-1,k) + T(n-3,k-1) for k = 0..floor(n/3) with T(0,0) = 1 and T(n,k) = 0 for n or k < 0, read by rows.
A102547 → x ↦ (1/27)x
A317497 nonnegative coefficients
Proved for all n: all roots real, in (−∞, 0] · coefficients of one sign · Hadamard kernel what this means
Rows ?
| n | x0 | x1 | x2 | Pn(1) |
|---|---|---|---|---|
| 0 | 1 | 1 | ||
| 1 | 3 | 3 | ||
| 2 | 9 | 9 | ||
| 3 | 27 | 1 | 28 | |
| 4 | 81 | 6 | 87 | |
| 5 | 243 | 27 | 270 | |
| 6 | 729 | 108 | 1 | 838 |
| 7 | 2187 | 405 | 9 | 2601 |
Generated b-files: A052541 (row sums), A317497 ?
Computed in your browser ?
Technical details
- Node id
n-a5b33928f20c14a2· revision 1 · JSON- Definition source
oeis_catalog:A317497- Fingerprint
f6-95f9e15614503e31
Observed on the stored rows ?
- Degrees: 0, 0, 0, 1, 1, 1, 2, 2, 2, 3, 3, 3, 4, 4, 4 (irregular)
- Palindromic rows: no
- γ-positive (gamma_positive): no
- Nonnegative coefficients (
nonn): yes - Only rational roots (
rr_by_factors: every nonzero row is a product of linear factors over ℚ): no
OEIS matches ?
- A317497: triangle, 45 terms agree, 15 full rows row lengths from the atlas (tabf) OEIS nonn in polytool catalog · view at the OEIS · generated b-file 1001 terms from n = 0 ?
- A052541: row sums, 15 terms agree OEIS nonn (row-sum match: finite agreement only) · view at the OEIS · generated b-file 200 terms from n = 0 ?
A generated b-file is computed from the node's definition along the row alignment of its OEIS link and starts at the entry's offset. It is an identification on a finite prefix, not a proof that the node and the OEIS entry agree for every n.
OEIS submission text ?
Fields to paste into an OEIS submission: the example %e, the formula
%F and programs %t (Mathematica) and %o (PARI/GP) that list the same rows.
For an OEIS link the row numbers, the offset and the orientation are those of the entry, as matched;
the matched terms were compared with the published ones, which identifies the node with the entry on a
finite prefix, not for every n. The PARI/GP program is not machine-checked here.
The atlas's own rows: n = 0, …, ascending powers of x
%e ExampleTriangle begins: 0: 1; 1: 3; 2: 9; 3: 27, 1; 4: 81, 6; 5: 243, 27; 6: 729, 108, 1; 7: 2187, 405, 9; 8: 6561, 1458, 54; 9: 19683, 5103, 270, 1;
%F FormulaThe row polynomials satisfy P(n,x) = 3*P(n-1,x) + x*P(n-3,x) for n >= 3, with P(0,x) = 1, P(1,x) = 3, P(2,x) = 9.
%t MathematicaP[0, x_] := 1;
P[1, x_] := 3;
P[2, x_] := 9;
P[n_, x_] := P[n, x] = Expand[3*P[n - 1, x] + x*P[n - 3, x]];
Table[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten%o PARI/GPP(N) = {my(v = vector(N + 1)); v[1] = 1; v[2] = 3; v[3] = 9; for(n = 3, N, my(i = n + 1); v[i] = 3*v[i - 1] + x*v[i - 3]); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)Generated with polytool c48629374597.
A317497: triangle, offset 0, from the row P0
%e ExampleTriangle begins: 0: 1; 1: 3; 2: 9; 3: 27, 1; 4: 81, 6; 5: 243, 27; 6: 729, 108, 1; 7: 2187, 405, 9; 8: 6561, 1458, 54; 9: 19683, 5103, 270, 1;
%F FormulaThe row polynomials satisfy P(n,x) = 3*P(n-1,x) + x*P(n-3,x) for n >= 3, with P(0,x) = 1, P(1,x) = 3, P(2,x) = 9.
%t MathematicaP[0, x_] := 1;
P[1, x_] := 3;
P[2, x_] := 9;
P[n_, x_] := P[n, x] = Expand[3*P[n - 1, x] + x*P[n - 3, x]];
Table[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten%o PARI/GPP(N) = {my(v = vector(N + 1)); v[1] = 1; v[2] = 3; v[3] = 9; for(n = 3, N, my(i = n + 1); v[i] = 3*v[i - 1] + x*v[i - 3]); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)Generated with polytool c48629374597.
Proved properties
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Real-rooted. Every row P_n, n >= 0, is zero or real-rooted with all roots in (-inf, 0]
Every polynomial of the sequence has only real roots, inside the stated interval.by the cited steps:
e-b8d37b5fe37403cf -
Coefficients of one sign. Every nonzero row, n >= 0: the coefficients of P_n have one sign
All coefficients of each polynomial have the same sign (after x -> -x when alternating).derived from the cited steps by a stated theorem:
e-b8d37b5fe37403cf -
Hadamard kernel (Malo). Rows P_n, n >= 0, are Hadamard kernels (preserve real-rootedness)
Multiplying the coefficients of any real-rooted polynomial termwise by those of a row (Hadamard product) gives a real-rooted polynomial again.derived from the cited steps by a stated theorem:
e-b8d37b5fe37403cf
Proof chains
1 incoming proof step. Each step is expanded back to the roots of the proof DAG, the theorem checks of a node's own rule. JSON
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preserver_image affine, shift 0
e-b8d37b5fe37403cfAffine, reversal and Möbius substitutions (elementary) polytool ?
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premise (sequence):
Triangle read by rows, formed from antidiagonals of the antidiagonals (A011973) of Pascal's triangle (A007318).
uses: Every row P_n, n >= 0, is zero or real-rooted with all roots in (-inf, 0]
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preserver_image reversal, shift 0
e-9cfbf7a52f4ba322Affine, reversal and Möbius substitutions (elementary) polytool ?
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premise (sequence):
Square array read by antidiagonals downwards: T(n,k), n>=0, k>=0, in which column 0 is equal to A057427: 0, 1, 1, 1, ..…
uses: Every row P_n, n >= 0, is zero or real-rooted with all roots in (-inf, 0]
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preserver_image reversal, shift 0
e-0e9e334768ea0a35Affine, reversal and Möbius substitutions (elementary) polytool ?
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premise (sequence):
Triangle read by rows, formed from antidiagonals of the antidiagonals (A011973) of Pascal's triangle (A007318).
uses: Every row P_n, n >= 0, is zero or real-rooted with all roots in (-inf, 0]
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parent_provers paper_theorem
e-eef18680cd27a7c9root: theorem checkParent-row provers of polytool polytool ?
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premise (sequence):
Triangle read by rows, formed from antidiagonals of the antidiagonals (A011973) of Pascal's triangle (A007318).
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premise (sequence):
Square array read by antidiagonals downwards: T(n,k), n>=0, k>=0, in which column 0 is equal to A057427: 0, 1, 1, 1, ..…
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↵ parent_provers paper_theorem
e-eef18680cd27a7c9(expanded above)
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premise (sequence):
Triangle read by rows, formed from antidiagonals of the antidiagonals (A011973) of Pascal's triangle (A007318).
Used in 6 proof steps
e-5c7adb912ab9816bbasis_map (A013610) → basis_map_A013610 of Triangle T(n,k) = 3*T(n-1,k) + T(n-3,k-1) for k = 0..floor(n/3) wit…e-5c9cfcdf7ca38f64basis_map (A013611) → basis_map_A013611 of Triangle T(n,k) = 3*T(n-1,k) + T(n-3,k-1) for k = 0..floor(n/3) wit…e-5de7e20fcf013a10basis_map (A013609) → basis_map_A013609 of Triangle T(n,k) = 3*T(n-1,k) + T(n-3,k-1) for k = 0..floor(n/3) wit…e-f7cac2f9abe8b6c3basis_map (A008277) → basis_map_A008277 of Triangle T(n,k) = 3*T(n-1,k) + T(n-3,k-1) for k = 0..floor(n/3) wit…e-fceaef6be0a1a1afbasis_map (A007318) → basis_map_A007318 of Triangle T(n,k) = 3*T(n-1,k) + T(n-3,k-1) for k = 0..floor(n/3) wit…e-57eb4960abae2cc5preserver_image (affine, shift 0) → basis_map_A007318 of Triangle T(n,k) = 3*T(n-1,k) + T(n-3,k-1) for k = 0..floor(n/3) wit…
Related sequences ?
No candidate equalities or related sequences.