hadamard_factor parent of Triangle read by rows: t(n,m) = binomial(2*n,2*m) * binomial(n,m).

palindromicγ-positivenonnegative coefficients

Proved for all n all roots real, in (−∞, 0)coefficients of one signHadamard kernelinterlacinginterlacing (weak)

Recurrence

\(P_{n}(x) = \left(2 + 2\,x\right)\,P_{n-1}(x) + \left(-1 + 2\,x - x^{2}\right)\,P_{n-2}(x)\)
\(P_{1}(x) = 1 + 6\,x + x^{2}\)
\(P_{2}(x) = 1 + 15\,x + 15\,x^{2} + x^{3}\)

Rows ?

nx0x1x2x3x4x5x6x7x8x9Pn(1)
11618
211515132
312870281128
4145210210451512
51664959244956612048
619110013003300310019118192
71120182080081287080081820120132768
8115330601856443758437581856430601531131072

Other recurrences

Reversed rows · proved equal for all n (proof step)

\(\left(n\right)\,P_{n}(x) = \left(n + 3\,n x\right)\,P_{n-1}(x) + \left(2\,x - 2\,x^{2}\right)\,P_{n-1}'(x)\)
\(P_{1}(x) = 1 + 6\,x + x^{2}\)
Technical details
Node id
n-dbc23e13bb290987 · revision 1 · JSON
Definition source
derived:hadamard_factor_parent_of:oeis_catalog:A155495
derived:reversal (equal by e-e04d6ef53c0359bc)
Fingerprint
f6-3b37e384e5c5a5b6

Observed on the stored rows ?

  • Degrees: 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16 (affine: slope 1, intercept 1)
  • Palindromic rows: yes
  • γ-positive (gamma_positive): yes
  • Nonnegative coefficients (nonn): yes
  • Only rational roots (rr_by_factors: every nonzero row is a product of linear factors over ℚ): no

Matches ?

Row sums ? A081294, A004171, A081654

Submission text ?

Atlas rows n = 1, …, ascending powers of x
%e Example
Triangle begins:
   1: 1,   6,    1;
   2: 1,  15,   15,     1;
   3: 1,  28,   70,    28,      1;
   4: 1,  45,  210,   210,     45,      1;
   5: 1,  66,  495,   924,    495,     66,      1;
   6: 1,  91, 1001,  3003,   3003,   1001,     91,      1;
   7: 1, 120, 1820,  8008,  12870,   8008,   1820,    120,     1;
   8: 1, 153, 3060, 18564,  43758,  43758,  18564,   3060,   153,    1;
   9: 1, 190, 4845, 38760, 125970, 184756, 125970,  38760,  4845,  190,   1;
  10: 1, 231, 7315, 74613, 319770, 646646, 646646, 319770, 74613, 7315, 231, 1;
%F Formula
The row polynomials satisfy P(n,x) = (2+2*x)*P(n-1,x) - (1-2*x+x^2)*P(n-2,x) for n >= 3, with P(1,x) = 1 + 6*x + x^2, P(2,x) = 1 + 15*x + 15*x^2 + x^3.
%t Mathematica
P[1, x_] := 1 + 6*x + x^2;
P[2, x_] := 1 + 15*x + 15*x^2 + x^3;
P[n_, x_] := P[n, x] = Expand[(2 + 2*x)*P[n - 1, x] - (1 - 2*x + x^2)*P[n - 2, x]];
Table[CoefficientList[P[n, x], x], {n, 1, 10}] // Flatten
%o PARI/GP
P(N) = {my(v = vector(N)); v[1] = 1 + 6*x + x^2; v[2] = 1 + 15*x + 15*x^2 + x^3; for(n = 3, N, my(i = n); v[i] = (2 + 2*x)*v[i - 1] - (1 - 2*x + x^2)*v[i - 2]); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i, v[i])))};
T(10)

polytool c48629374597

Properties

Proof chains ? JSON

Used in 13

5 more

Same fingerprint ?

References

  1. [Fav35] Jean Favard. Sur les polynômes de tchebicheff. C. R. Acad. Sci. Paris, 200:2052–2053, 1935.
  2. [LW07] Lily L. Liu and Yi Wang. A unified approach to polynomial sequences with only real zeros. Advances in Applied Mathematics, 38(4):542–560, May 2007. doi:10.1016/j.aam.2006.02.003
  3. [Sze39] G. Szegő. Orthogonal Polynomials. Colloquium publications, American Mathematical Society, 1939. doi:10.1090/coll/023