A272867 → basis A013610

nonnegative coefficients

Proved for all n: all roots real, in (−∞, 0] · coefficients of one sign · Hadamard kernel what this means

Recurrence
\(P_{n}(x) = \left(6 + 18\,x + 9\,x^{2}\right)\,P_{n-1}(x)\)
\(P_{0}(x) = 1\)

Rows ?

nx0x1x2x3x4x5x6x7x8x9x10x11x12x13x14Pn(1)
011
1618933
236216432324811089
3216194468041166410206437472935937
4129615552777602099523324243149281749605248865611185921
577761166407581602799360647352097627689710280629856025587905904905904939135393
646656839808671846431492800960530402002942082922531843004413122161193401062882003401222463772925314411291467969
72799365878656558472323174474241203654816321415516862232922088865853056933493831272318491284062335004160707758442408991866961566478296942618442977

Generated b-files: A009977 (row sums) ?

Computed in your browser ?

Technical details
Node id
n-c4fd821a14172d5f · revision 1 · JSON
Definition source
derived:basis_map_A013610
Fingerprint
f6-3c4a6b4bc3495597

Observed on the stored rows ?

  • Degrees: 0, 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28 (affine: slope 2, intercept 0)
  • Palindromic rows: no
  • γ-positive (gamma_positive): no
  • Nonnegative coefficients (nonn): yes
  • Only rational roots (rr_by_factors: every nonzero row is a product of linear factors over ℚ): no

OEIS matches ?

A generated b-file is computed from the node's definition along the row alignment of its OEIS link and starts at the entry's offset. It is an identification on a finite prefix, not a proof that the node and the OEIS entry agree for every n.

OEIS submission text ?

Fields to paste into an OEIS submission: the example %e, the formula %F and programs %t (Mathematica) and %o (PARI/GP) that list the same rows. For an OEIS link the row numbers, the offset and the orientation are those of the entry, as matched; the matched terms were compared with the published ones, which identifies the node with the entry on a finite prefix, not for every n. The PARI/GP program is not machine-checked here.

The atlas's own rows: n = 0, …, ascending powers of x
%e Example
Triangle begins:
  0:        1;
  1:        6,        18,          9;
  2:       36,       216,        432,         324,           81;
  3:      216,      1944,       6804,       11664,        10206,         4374,           729;
  4:     1296,     15552,      77760,      209952,       332424,       314928,        174960,         52488,          6561;
  5:     7776,    116640,     758160,     2799360,      6473520,      9762768,       9710280,       6298560,       2558790,        590490,         59049;
  6:    46656,    839808,    6718464,    31492800,     96053040,    200294208,     292253184,     300441312,     216119340,     106288200,      34012224,       6377292,        531441;
  7:   279936,   5878656,   55847232,   317447424,   1203654816,   3214155168,    6223292208,    8865853056,    9334938312,    7231849128,    4062335004,    1607077584,     424089918,      66961566,       4782969;
  8:  1679616,  40310784,  443418624,  2962842624,  13438607616,  43807744512,  106027439616,  194141774592,  271604614752,  291212661888,  238561739136,  147851137728,   68032951056,   22499086176,    5050815264,    688747536,    43046721;
  9: 10077696, 272097792, 3401222400, 26121388032, 137953580544, 531406987776, 1545651507456, 3467614261248, 6078426587712, 8383435008192, 9117639881568, 7802132087808, 5216573837664, 2690247875616, 1047585002256, 297538935552, 58113073350, 6973568802, 387420489;
%F Formula
The row polynomials satisfy P(n,x) = (6+18*x+9*x^2)*P(n-1,x) for n >= 1, with P(0,x) = 1.
%t Mathematica
P[0, x_] := 1;
P[n_, x_] := P[n, x] = Expand[(6 + 18*x + 9*x^2)*P[n - 1, x]];
Table[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten
%o PARI/GP
P(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = (6 + 18*x + 9*x^2)*v[i - 1]); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)

Generated with polytool c48629374597.

Proved properties

  • Real-rooted. Every row P_n, n >= 0, is zero or real-rooted with all roots in (-inf, 0]
    Every polynomial of the sequence has only real roots, inside the stated interval.
    by the cited steps: e-0f2bf5edb3121755
  • Coefficients of one sign. Every nonzero row, n >= 0: the coefficients of P_n have one sign
    All coefficients of each polynomial have the same sign (after x -> -x when alternating).
    derived from the cited steps by a stated theorem: e-0f2bf5edb3121755
  • Hadamard kernel (Malo). Rows P_n, n >= 0, are Hadamard kernels (preserve real-rootedness)
    Multiplying the coefficients of any real-rooted polynomial termwise by those of a row (Hadamard product) gives a real-rooted polynomial again.
    derived from the cited steps by a stated theorem: e-0f2bf5edb3121755

Proof chains

1 incoming proof step. Each step is expanded back to the roots of the proof DAG, the theorem checks of a node's own rule. JSON

Same fingerprint (1)

Equal up to content, sign, reversal and a small index shift.