A088996: Triangle T(n, k) read by rows: T(n, k) = Sum_{j=0..n} binomial(j, n-k) * |Stirling1(n, n-j)|.
A088996 nonnegative coefficients only rational roots
Proved for all n: all roots real, in [−1, 0] · coefficients of one sign · Hadamard kernel what this means
Rows ?
| n | x0 | x1 | x2 | x3 | x4 | x5 | x6 | x7 | Pn(1) |
|---|---|---|---|---|---|---|---|---|---|
| 0 | 1 | 1 | |||||||
| 1 | 0 | 1 | 1 | ||||||
| 2 | 0 | 1 | 2 | 3 | |||||
| 3 | 0 | 2 | 7 | 6 | 15 | ||||
| 4 | 0 | 6 | 29 | 46 | 24 | 105 | |||
| 5 | 0 | 24 | 146 | 329 | 326 | 120 | 945 | ||
| 6 | 0 | 120 | 874 | 2521 | 3604 | 2556 | 720 | 10395 | |
| 7 | 0 | 720 | 6084 | 21244 | 39271 | 40564 | 22212 | 5040 | 135135 |
Generated b-files: A001147 (row sums), A059364 (reversed triangle), A088996 ?
Computed in your browser ?
Other recurrences
X ↦ x/(x+1) substitution · proved equal for all n (proof step)
Technical details
- Node id
n-849de7332df28657· revision 2 · JSON- Definition source
oeis_catalog:A088996derived:mobius_x_over_x_plus_one(equal bye-046150b77085a263)- Fingerprint
f6-774e45ab36bcae1f
Observed on the stored rows ?
- Degrees: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 (affine: slope 1, intercept 0)
- Palindromic rows: no
- γ-positive (gamma_positive): no
- Nonnegative coefficients (
nonn): yes - Only rational roots (
rr_by_factors: every nonzero row is a product of linear factors over ℚ): yes
OEIS matches ?
- A088996: triangle, 45 terms agree, 9 full rows row-aligned (tabl) OEIS nonn in polytool catalog · view at the OEIS · generated b-file 990 terms from n = 0 ?
- A001147: row sums, 15 terms agree OEIS nonn (row-sum match: finite agreement only) · view at the OEIS · generated b-file 200 terms from n = 0 ?
- A059364: reversed triangle, 41 terms agree, 8 full rows row-aligned (tabl) OEIS nonn in polytool catalog · view at the OEIS · generated b-file 990 terms from n = 1 ?
A generated b-file is computed from the node's definition along the row alignment of its OEIS link and starts at the entry's offset. It is an identification on a finite prefix, not a proof that the node and the OEIS entry agree for every n.
OEIS submission text ?
Fields to paste into an OEIS submission: the example %e, the formula
%F and programs %t (Mathematica) and %o (PARI/GP) that list the same rows.
For an OEIS link the row numbers, the offset and the orientation are those of the entry, as matched;
the matched terms were compared with the published ones, which identifies the node with the entry on a
finite prefix, not for every n. The PARI/GP program is not machine-checked here.
The atlas's own rows: n = 0, …, ascending powers of x
%e ExampleTriangle begins: 0: 1; 1: 0, 1; 2: 0, 1, 2; 3: 0, 2, 7, 6; 4: 0, 6, 29, 46, 24; 5: 0, 24, 146, 329, 326, 120; 6: 0, 120, 874, 2521, 3604, 2556, 720; 7: 0, 720, 6084, 21244, 39271, 40564, 22212, 5040; 8: 0, 5040, 48348, 197380, 444849, 598116, 479996, 212976, 40320; 9: 0, 40320, 432144, 2014172, 5335212, 8788569, 9223012, 6023772, 2239344, 362880;
%F FormulaThe row polynomials satisfy P(n,x) = (n-1+n*x)*P(n-1,x) for n >= 1, with P(0,x) = 1.
%t MathematicaP[0, x_] := 1;
P[n_, x_] := P[n, x] = Expand[(n - 1 + n*x)*P[n - 1, x]];
Table[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten%o PARI/GPP(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = (n - 1 + n*x)*v[i - 1]); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)Generated with polytool c48629374597.
A059364: reversed triangle, offset 1, from the row P1, low zeros dropped
%e ExampleTriangle begins: 1: 1; 2: 2, 1; 3: 6, 7, 2; 4: 24, 46, 29, 6; 5: 120, 326, 329, 146, 24; 6: 720, 2556, 3604, 2521, 874, 120; 7: 5040, 22212, 40564, 39271, 21244, 6084, 720; 8: 40320, 212976, 479996, 598116, 444849, 197380, 48348, 5040; 9: 362880, 2239344, 6023772, 9223012, 8788569, 5335212, 2014172, 432144, 40320; 10: 3628800, 25659360, 80391816, 146444068, 170892798, 132449241, 68158628, 22448988, 4292496, 362880;
%F FormulaRow n lists the coefficients of P(n,x) in descending powers of x, down to the lowest nonzero coefficient, where P(n,x) = (n-1+n*x)*P(n-1,x) for n >= 2, with P(1,x) = x.
%t MathematicaP[1, x_] := x;
P[n_, x_] := P[n, x] = Expand[(n - 1 + n*x)*P[n - 1, x]];
Table[Reverse[PadRight[CoefficientList[Expand[P[n, x]/x^Exponent[P[n, x], x, Min]], x], n]], {n, 1, 10}] // Flatten%o PARI/GPP(N) = {my(v = vector(N)); v[1] = x; for(n = 2, N, my(i = n); v[i] = (n - 1 + n*x)*v[i - 1]); v};
row(n, p) = {my(c = Vecrev(p/x^valuation(p, x))); c = concat(c, vector(n - #c)); c = Vecrev(c); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i, v[i])))};
T(10)Generated with polytool c48629374597.
A088996: triangle, offset 0, from the row P0
%e ExampleTriangle begins: 0: 1; 1: 0, 1; 2: 0, 1, 2; 3: 0, 2, 7, 6; 4: 0, 6, 29, 46, 24; 5: 0, 24, 146, 329, 326, 120; 6: 0, 120, 874, 2521, 3604, 2556, 720; 7: 0, 720, 6084, 21244, 39271, 40564, 22212, 5040; 8: 0, 5040, 48348, 197380, 444849, 598116, 479996, 212976, 40320; 9: 0, 40320, 432144, 2014172, 5335212, 8788569, 9223012, 6023772, 2239344, 362880;
%F FormulaThe row polynomials satisfy P(n,x) = (n-1+n*x)*P(n-1,x) for n >= 1, with P(0,x) = 1.
%t MathematicaP[0, x_] := 1;
P[n_, x_] := P[n, x] = Expand[(n - 1 + n*x)*P[n - 1, x]];
Table[PadRight[CoefficientList[P[n, x], x], n + 1], {n, 0, 9}] // Flatten%o PARI/GPP(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = (n - 1 + n*x)*v[i - 1]); v};
row(n, p) = {my(c = Vecrev(p)); c = concat(c, vector(n + 1 - #c)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)Generated with polytool c48629374597.
Proved properties
-
Real-rooted. Every row P_n, n >= 0, is zero or real-rooted with all roots in (-inf, 0]
Every polynomial of the sequence has only real roots, inside the stated interval.by the cited steps:
e-4c0875826685c298 -
Coefficients of one sign. Every nonzero row, n >= 0: the coefficients of P_n have one sign
All coefficients of each polynomial have the same sign (after x -> -x when alternating).derived from the cited steps by a stated theorem:
e-4c0875826685c298,e-e5c0b6618046e013 -
Hadamard kernel (Malo). Rows P_n, n >= 0, are Hadamard kernels (preserve real-rootedness)
Multiplying the coefficients of any real-rooted polynomial termwise by those of a row (Hadamard product) gives a real-rooted polynomial again.derived from the cited steps by a stated theorem:
e-4c0875826685c298,e-e5c0b6618046e013 -
Real-rooted. Every row P_n, n >= 0, is zero or real-rooted with all roots in [-1, 0]
Every polynomial of the sequence has only real roots, inside the stated interval.by the cited steps:
e-e5c0b6618046e013
Proof chains
3 incoming proof steps. Each step is expanded back to the roots of the proof DAG, the theorem checks of a node's own rule. JSON
-
definition_equality
e-046150b77085a263root: theorem checkOre-algebra identity of two definitions polytool ?
-
parent_provers root_domain
e-4c0875826685c298root: theorem checkParent-row provers of polytool polytool ?
-
preserver_image mobius, shift 0
e-e5c0b6618046e013Affine, reversal and Möbius substitutions (elementary) polytool ?
-
premise (sequence):
Triangle of unsigned Stirling numbers of the first kind (see A048994), read by rows, T(n,k) for 0 <= k <= n.
uses: Every row P_n, n >= 0, is zero or real-rooted with all roots in (-inf, 0]
-
parent_provers root_domain
e-edbf92ee2e446027root: theorem checkParent-row provers of polytool polytool ?
-
-
premise (sequence):
Triangle of unsigned Stirling numbers of the first kind (see A048994), read by rows, T(n,k) for 0 <= k <= n.
Used in 5 proof steps
e-0f361da4a6c0f5b4basis_map (A013609) → basis_map_A013609 of Triangle T(n, k) read by rows: T(n, k) = Sum_{j=0..n} binomial(j, n-…e-2164c90874641e81basis_map (A008277) → basis_map_A008277 of Triangle T(n, k) read by rows: T(n, k) = Sum_{j=0..n} binomial(j, n-…e-5ca25d3c8ee8ed44basis_map (A007318) → basis_map_A007318 of Triangle T(n, k) read by rows: T(n, k) = Sum_{j=0..n} binomial(j, n-…e-7cf3813b520dd535basis_map (A013610) → basis_map_A013610 of Triangle T(n, k) read by rows: T(n, k) = Sum_{j=0..n} binomial(j, n-…e-e6ead7ccbecb2d32basis_map (A013611) → basis_map_A013611 of Triangle T(n, k) read by rows: T(n, k) = Sum_{j=0..n} binomial(j, n-…
Related sequences ?
Same fingerprint (2)
Equal up to content, sign, reversal and a small index shift.