A118933 → basis A008277
nonnegative coefficients
Proved for all n: all roots real, in (−∞, 0] · coefficients of one sign · Hadamard kernel what this means
Rows ?
| n | x0 | x1 | Pn(1) |
|---|---|---|---|
| 0 | 1 | 1 | |
| 1 | 1 | 1 | |
| 2 | 1 | 1 | |
| 3 | 1 | 1 | |
| 4 | 7 | 6 | 13 |
| 5 | 31 | 30 | 61 |
| 6 | 91 | 90 | 181 |
| 7 | 211 | 210 | 421 |
Computed in your browser ?
Technical details
- Node id
n-ff283d31b1efde95· revision 1 · JSON- Definition source
derived:basis_map_A008277- Fingerprint
f6-f60f31b5a675bca5
Observed on the stored rows ?
- Degrees: 0, 0, 0, 0, 1, 1, 1, 1, 2, 2, 2, 2, 3, 3, 3 (irregular)
- Palindromic rows: no
- γ-positive (gamma_positive): no
- Nonnegative coefficients (
nonn): yes - Only rational roots (
rr_by_factors: every nonzero row is a product of linear factors over ℚ): no
OEIS matches ?
No OEIS matches.
OEIS submission text ?
Fields to paste into an OEIS submission: the example %e, the formula
%F and programs %t (Mathematica) and %o (PARI/GP) that list the same rows.
For an OEIS link the row numbers, the offset and the orientation are those of the entry, as matched;
the matched terms were compared with the published ones, which identifies the node with the entry on a
finite prefix, not for every n. The PARI/GP program is not machine-checked here.
The atlas's own rows: n = 0, …, ascending powers of x
%e ExampleTriangle begins: 0: 1; 1: 1; 2: 1; 3: 1; 4: 7, 6; 5: 31, 30; 6: 91, 90; 7: 211, 210; 8: 1681, 4200, 1260; 9: 12097, 34776, 11340;
%F FormulaThe row polynomials satisfy P(n,x) = (n^3-6*n^2+11*n-6+(n^3-6*n^2+11*n-6)*x)*P(n-4,x) + (n^3-6*n^2+11*n-6)*x*d/dx P(n-4,x) + P(n-1,x) for n >= 4, with P(0,x) = 1, P(1,x) = 1, P(2,x) = 1, P(3,x) = 1.
%t MathematicaP[0, x_] := 1;
P[1, x_] := 1;
P[2, x_] := 1;
P[3, x_] := 1;
P[n_, x_] := P[n, x] = Expand[(n^3 - 6*n^2 + 11*n - 6 + (n^3 - 6*n^2 + 11*n - 6)*x)*P[n - 4, x] + (n^3 - 6*n^2 + 11*n - 6)*x*D[P[n - 4, x], x] + P[n - 1, x]];
Table[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten%o PARI/GPP(N) = {my(v = vector(N + 1)); v[1] = 1; v[2] = 1; v[3] = 1; v[4] = 1; for(n = 4, N, my(i = n + 1); v[i] = (n^3 - 6*n^2 + 11*n - 6 + (n^3 - 6*n^2 + 11*n - 6)*x)*v[i - 4] + (n^3 - 6*n^2 + 11*n - 6)*x*deriv(v[i - 4], x) + v[i - 1]); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)Generated with polytool c48629374597.
Proved properties
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Real-rooted. Every row P_n, n >= 0, is zero or real-rooted with all roots in (-inf, 0]
Every polynomial of the sequence has only real roots, inside the stated interval.by the cited steps:
e-510f97d2d65daac7 -
Coefficients of one sign. Every nonzero row, n >= 0: the coefficients of P_n have one sign
All coefficients of each polynomial have the same sign (after x -> -x when alternating).derived from the cited steps by a stated theorem:
e-510f97d2d65daac7 -
Hadamard kernel (Malo). Rows P_n, n >= 0, are Hadamard kernels (preserve real-rootedness)
Multiplying the coefficients of any real-rooted polynomial termwise by those of a row (Hadamard product) gives a real-rooted polynomial again.derived from the cited steps by a stated theorem:
e-510f97d2d65daac7
Proof chains
1 incoming proof step. Each step is expanded back to the roots of the proof DAG, the theorem checks of a node's own rule. JSON
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basis_map A008277
e-510f97d2d65daac7Ray basis map theorem [MW08, Thm 2] polytool RealRooted rayBasisMap_maps_realRootedIn_iff ?
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premise (sequence):
Triangle, read by rows, where T(n,k) = n!/(k!*(n-4*k)!*4^k) for n>=4*k>=0.
uses: Every row P_n, n >= 0, is zero or real-rooted with all roots in (-inf, 0]
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parent_provers paper_theorem
e-281e0bfa773c0053root: theorem checkParent-row provers of polytool polytool ?
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premise (sequence):
Triangle, read by rows, where T(n,k) = n!/(k!*(n-4*k)!*4^k) for n>=4*k>=0.
Related sequences ?
No candidate equalities or related sequences.
References
- [MW08] Shi-Mei Ma and Yi Wang. q-Eulerian polynomials and polynomials with only real zeros. The Electronic Journal of Combinatorics, 15(1):Research Paper 17, January 2008. doi:10.37236/741