A111125 → basis A013610 → reverse
nonnegative coefficients
Proved for all n all roots real, in (−∞, 0]coefficients of one signHadamard kernel
Recurrence
\(\left(-9 + 6\,n\right)\,P_{n}(x) = \left(-27 - 42\,x - 10\,x^{2} + 18\,n + 27\,n x + 5\,n x^{2}\right)\,P_{n-1}(x) + \left(-9\,x - 18\,x^{2} - 5\,x^{3}\right)\,P_{n-1}'(x)\)
\(P_{1}(x) = 1\)
Rows ?
| n | x0 | x1 | x2 | x3 | x4 | x5 | x6 | x7 | Pn(1) |
|---|---|---|---|---|---|---|---|---|---|
| 1 | 1 | 1 | |||||||
| 2 | 3 | 4 | 7 | ||||||
| 3 | 9 | 21 | 11 | 41 | |||||
| 4 | 27 | 90 | 93 | 29 | 239 | ||||
| 5 | 81 | 351 | 540 | 345 | 76 | 1393 | |||
| 6 | 243 | 1296 | 2646 | 2565 | 1170 | 199 | 8119 | ||
| 7 | 729 | 4617 | 11745 | 15282 | 10665 | 3762 | 521 | 47321 | |
| 8 | 2187 | 16038 | 48843 | 79785 | 75195 | 40716 | 11679 | 1364 | 275807 |
Compute more
?
Technical details
- Node id
n-f85b64126b6a6cdc· revision 0 · JSON- Definition source
derived:reversal- Fingerprint
f6-90d3cb4b1288c73a
Observed on the stored rows ?
- Degrees: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 (affine: slope 1, intercept -1)
- Palindromic rows: no
- γ-positive (gamma_positive): no
- Nonnegative coefficients (
nonn): yes - Only rational roots (
rr_by_factors: every nonzero row is a product of linear factors over ℚ): no
Matches ?
No OEIS matches.
Submission text ?
Atlas rows n = 1, …, ascending powers of x
%e ExampleTriangle begins: 1: 1; 2: 3, 4; 3: 9, 21, 11; 4: 27, 90, 93, 29; 5: 81, 351, 540, 345, 76; 6: 243, 1296, 2646, 2565, 1170, 199; 7: 729, 4617, 11745, 15282, 10665, 3762, 521; 8: 2187, 16038, 48843, 79785, 75195, 40716, 11679, 1364; 9: 6561, 54675, 193914, 381267, 453195, 332451, 146520, 35367, 3571; 10: 19683, 183708, 743580, 1709505, 2454543, 2277153, 1361718, 504945, 105135, 9349;
%F FormulaThe row polynomials satisfy (6*n-9)*P(n,x) = (18*n-27+(27*n-42)*x+(5*n-10)*x^2)*P(n-1,x) - (9*x+18*x^2+5*x^3)*d/dx P(n-1,x) for n >= 2, with P(1,x) = 1.
%t MathematicaP[1, x_] := 1;
P[n_, x_] := P[n, x] = Expand[Together[((18*n - 27 + (27*n - 42)*x + (5*n - 10)*x^2)*P[n - 1, x] - (9*x + 18*x^2 + 5*x^3)*D[P[n - 1, x], x])/(6*n - 9)]];
Table[CoefficientList[P[n, x], x], {n, 1, 10}] // Flatten%o PARI/GPP(N) = {my(v = vector(N)); v[1] = 1; for(n = 2, N, my(i = n); v[i] = ((18*n - 27 + (27*n - 42)*x + (5*n - 10)*x^2)*v[i - 1] - (9*x + 18*x^2 + 5*x^3)*deriv(v[i - 1], x))/(6*n - 9)); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i, v[i])))};
T(10)polytool c48629374597
Properties
- Real-rooted? Every row P_n, n ≥ 1, is zero or real-rooted with all roots in (−∞, 0]
- Coefficients of one sign? Every nonzero row, n ≥ 1: the coefficients of P_n have one sign
- Hadamard kernel (Malo)? Rows P_n, n ≥ 1, are Hadamard kernels (preserve real-rootedness)
Proof chains ? JSON
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Affine, reversal and Möbius substitutions (elementary) polytool ? step ›
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from
basis_map_A013610 of Triangle read by rows: T(k,s) = ((2*k+1)/(2*s+1))*binomial(k+s,2*s), 0 <= s <= k.?
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Geometric basis map (elementary) polytool ? step ›
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from
Triangle read by rows: T(k,s) = ((2*k+1)/(2*s+1))*binomial(k+s,2*s), 0 <= s <= k.?
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Affine, reversal and Möbius substitutions (elementary) polytool ? step ›
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from
Triangle read by rows: T(k,s) = ((2*k+1)/(2*s+1))*binomial(k+s,2*s), 0 <= s <= k.?
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from
basis_map_A013610 of Triangle read by rows: T(k,s) = ((2*k+1)/(2*s+1))*binomial(k+s,2*s), 0 <= s <= k.?
Related ?
Same fingerprint ?
References
- [Fav35] Jean Favard. Sur les polynômes de tchebicheff. C. R. Acad. Sci. Paris, 200:2052–2053, 1935.
- [LW07] Lily L. Liu and Yi Wang. A unified approach to polynomial sequences with only real zeros. Advances in Applied Mathematics, 38(4):542–560, May 2007. doi:10.1016/j.aam.2006.02.003
- [Sze39] G. Szegő. Orthogonal Polynomials. Colloquium publications, American Mathematical Society, 1939. doi:10.1090/coll/023