A334218 → D → x ↦ x+1
nonnegative coefficients
Proved for all n all roots real, in (−∞, −1]coefficients of one signHadamard kernel
Recurrence
\(\left(6 - 5\,n + n^{2}\right)\,P_{n}(x) = \left(-16 - 32\,x - 16\,x^{2} + 36\,n + 72\,n x + 36\,n x^{2} - 28\,n^{2} - 56\,n^{2} x - 28\,n^{2} x^{2} + 9\,n^{3} + 18\,n^{3} x + 9\,n^{3} x^{2} - n^{4} - 2\,n^{4} x - n^{4} x^{2}\right)\,P_{n-2}(x) + \left(-4\,x - 8\,x^{2} - 4\,x^{3} + 8\,n x + 16\,n x^{2} + 8\,n x^{3} - 5\,n^{2} x - 10\,n^{2} x^{2} - 5\,n^{2} x^{3} + n^{3} x + 2\,n^{3} x^{2} + n^{3} x^{3}\right)\,P_{n-2}'(x) + \left(-15 - 18\,x + 26\,n + 30\,n x - 13\,n^{2} - 14\,n^{2} x + 2\,n^{3} + 2\,n^{3} x\right)\,P_{n-1}(x) + \left(-3\,x - 3\,x^{2} + 4\,n x + 4\,n x^{2} - n^{2} x - n^{2} x^{2}\right)\,P_{n-1}'(x)\)
\(P_{1}(x) = 0\)
\(P_{2}(x) = 0\)
\(P_{3}(x) = 2\)
Rows ?
| n | x0 | x1 | x2 | x3 | x4 | x5 | x6 | x7 | x8 | x9 | x10 | x11 | x12 | Pn(1) |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 1 | 0 | |||||||||||||
| 2 | 0 | |||||||||||||
| 3 | 2 | 2 | ||||||||||||
| 4 | 9 | 6 | 15 | |||||||||||
| 5 | 48 | 56 | 12 | 116 | ||||||||||
| 6 | 300 | 500 | 225 | 20 | 1045 | |||||||||
| 7 | 2160 | 4680 | 3240 | 744 | 30 | 10854 | ||||||||
| 8 | 17640 | 47040 | 44100 | 16856 | 2205 | 42 | 127883 | |||||||
| 9 | 161280 | 510720 | 604800 | 326592 | 77280 | 6096 | 56 | 1686824 | ||||||
| 10 | 1632960 | 5987520 | 8573040 | 6005664 | 2097900 | 326700 | 16065 | 72 | 24639921 | |||||
| 11 | 18144000 | 75600000 | 127008000 | 109569600 | 51030000 | 12277800 | 1306200 | 40880 | 90 | 394976570 | ||||
| 12 | 219542400 | 1024531200 | 1975881600 | 2027108160 | 1184614200 | 390820320 | 67336500 | 5016176 | 101277 | 110 | 6894951943 | |||
| 13 | 2874009600 | 14849049600 | 32332608000 | 38471811840 | 27103507200 | 11436353280 | 2780870400 | 352224576 | 18689616 | 245640 | 132 | 130219369884 | ||
| 14 | 40475635200 | 229361932800 | 556539984000 | 753746273280 | 622312891200 | 320978211840 | 101788727040 | 18741218496 | 1777836060 | 68022500 | 585585 | 156 | 2645791318157 | |
| 15 | 610248038400 | 3763196236800 | 10069092633600 | 15296884162560 | 14493390912000 | 8853439795200 | 3480673996800 | 852584853120 | 121186905840 | 8729065800 | 243002760 | 1376088 | 182 | 57549670979150 |
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Technical details
- Node id
n-f232d2f66d74f533· revision 0 · JSON- Definition source
derived:shift_x_plus_one- Fingerprint
f6-ef5562416e43169f
Observed on the stored rows ?
- Degrees: -1, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 (affine: slope 1, intercept -3)
- Palindromic rows: no
- γ-positive (gamma_positive): no
- Nonnegative coefficients (
nonn): yes - Only rational roots (
rr_by_factors: every nonzero row is a product of linear factors over ℚ): no
Matches ?
No OEIS matches.
Submission text ?
Atlas rows n = 1, …, ascending powers of x
%e ExampleTriangle begins: 1: 0; 2: 0; 3: 2; 4: 9, 6; 5: 48, 56, 12; 6: 300, 500, 225, 20; 7: 2160, 4680, 3240, 744, 30; 8: 17640, 47040, 44100, 16856, 2205, 42; 9: 161280, 510720, 604800, 326592, 77280, 6096, 56; 10: 1632960, 5987520, 8573040, 6005664, 2097900, 326700, 16065, 72;
%F FormulaThe row polynomials satisfy (n^2-5*n+6)*P(n,x) = -(n^4-9*n^3+28*n^2-36*n+16+(2*n^4-18*n^3+56*n^2-72*n+32)*x+(n^4-9*n^3+28*n^2-36*n+16)*x^2)*P(n-2,x) + ((n^3-5*n^2+8*n-4)*x+(2*n^3-10*n^2+16*n-8)*x^2+(n^3-5*n^2+8*n-4)*x^3)*d/dx P(n-2,x) + (2*n^3-13*n^2+26*n-15+(2*n^3-14*n^2+30*n-18)*x)*P(n-1,x) - ((n^2-4*n+3)*x+(n^2-4*n+3)*x^2)*d/dx P(n-1,x) for n >= 4, with P(1,x) = 0, P(2,x) = 0, P(3,x) = 2.
%t MathematicaP[1, x_] := 0;
P[2, x_] := 0;
P[3, x_] := 2;
P[n_, x_] := P[n, x] = Expand[Together[(-(n^4 - 9*n^3 + 28*n^2 - 36*n + 16 + (2*n^4 - 18*n^3 + 56*n^2 - 72*n + 32)*x + (n^4 - 9*n^3 + 28*n^2 - 36*n + 16)*x^2)*P[n - 2, x] + ((n^3 - 5*n^2 + 8*n - 4)*x + (2*n^3 - 10*n^2 + 16*n - 8)*x^2 + (n^3 - 5*n^2 + 8*n - 4)*x^3)*D[P[n - 2, x], x] + (2*n^3 - 13*n^2 + 26*n - 15 + (2*n^3 - 14*n^2 + 30*n - 18)*x)*P[n - 1, x] - ((n^2 - 4*n + 3)*x + (n^2 - 4*n + 3)*x^2)*D[P[n - 1, x], x])/(n^2 - 5*n + 6)]];
Table[CoefficientList[P[n, x], x], {n, 1, 10}] // Flatten%o PARI/GPP(N) = {my(v = vector(N)); v[1] = 0; v[2] = 0; v[3] = 2; for(n = 4, N, my(i = n); v[i] = (-(n^4 - 9*n^3 + 28*n^2 - 36*n + 16 + (2*n^4 - 18*n^3 + 56*n^2 - 72*n + 32)*x + (n^4 - 9*n^3 + 28*n^2 - 36*n + 16)*x^2)*v[i - 2] + ((n^3 - 5*n^2 + 8*n - 4)*x + (2*n^3 - 10*n^2 + 16*n - 8)*x^2 + (n^3 - 5*n^2 + 8*n - 4)*x^3)*deriv(v[i - 2], x) + (2*n^3 - 13*n^2 + 26*n - 15 + (2*n^3 - 14*n^2 + 30*n - 18)*x)*v[i - 1] - ((n^2 - 4*n + 3)*x + (n^2 - 4*n + 3)*x^2)*deriv(v[i - 1], x))/(n^2 - 5*n + 6)); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i, v[i])))};
T(10)polytool c48629374597
Properties
- Real-rooted? Every row P_n, n ≥ 1, is zero or real-rooted with all roots in (−∞, -1]
- Coefficients of one sign? Every nonzero row, n ≥ 1: the coefficients of P_n have one sign
- Hadamard kernel (Malo)? Rows P_n, n ≥ 1, are Hadamard kernels (preserve real-rootedness)
Proof chains ? JSON
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Affine, reversal and Möbius substitutions (elementary) polytool ? step ›
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derivative of Triangle read by rows: T(n,k) is the number of permutations of 1..n arranged in a circle with exactly k d…?
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Laguerre’s theorem on differential operators [SP14] polytool ? step ›
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Triangle read by rows: T(n,k) is the number of permutations of 1..n arranged in a circle with exactly k descents.?
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Liu–Wang theorem with a lag row [LW07, Thm 2.1] RealRooted ? step › direct check
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Triangle read by rows: T(n,k) is the number of permutations of 1..n arranged in a circle with exactly k descents.?
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derivative of Triangle read by rows: T(n,k) is the number of permutations of 1..n arranged in a circle with exactly k d…?
Related ?
Same fingerprint ?
References
- [LW07] Lily L. Liu and Yi Wang. A unified approach to polynomial sequences with only real zeros. Advances in Applied Mathematics, 38(4):542–560, May 2007. doi:10.1016/j.aam.2006.02.003
- [SP14] J Schur and G Polya. Über zwei Arten von Faktorenfolgen in der Theorie der algebraischen Gleichungen. J. Reine Angew. Math., 1914.