A257620: Triangle read by rows: T(n, k) = t(n-k, k), where t(0,0) = 1, t(n,m) = 0 if n < 0 or m < 0, else t(n,m) = f(m)*t(n-1,m) + f(n)*t(n,m-1), and f(n) = 3*n + 3.
A257620 palindromic γ-positive nonnegative coefficients
Proved for all n: all roots real, in (−∞, 0) · coefficients of one sign · interlacing (weak) · Hadamard kernel what this means
Rows ?
| n | x0 | x1 | x2 | x3 | x4 | x5 | x6 | x7 | Pn(1) |
|---|---|---|---|---|---|---|---|---|---|
| 0 | 1 | 1 | |||||||
| 1 | 3 | 3 | 6 | ||||||
| 2 | 9 | 36 | 9 | 54 | |||||
| 3 | 27 | 297 | 297 | 27 | 648 | ||||
| 4 | 81 | 2106 | 5346 | 2106 | 81 | 9720 | |||
| 5 | 243 | 13851 | 73386 | 73386 | 13851 | 243 | 174960 | ||
| 6 | 729 | 87480 | 868239 | 1761264 | 868239 | 87480 | 729 | 3674160 | |
| 7 | 2187 | 540189 | 9388791 | 34158753 | 34158753 | 9388791 | 540189 | 2187 | 88179840 |
Generated b-files: A034001 (row sums), A257620, A257620 (reversed triangle) ?
Computed in your browser ?
Technical details
- Node id
n-dfedc6a36c97eba4· revision 1 · JSON- Definition source
oeis_catalog:A257620- Fingerprint
f6-605cb6decd8257f5
Observed on the stored rows ?
- Degrees: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 (affine: slope 1, intercept 0)
- Palindromic rows: yes
- γ-positive (gamma_positive): yes
- Nonnegative coefficients (
nonn): yes - Only rational roots (
rr_by_factors: every nonzero row is a product of linear factors over ℚ): no
OEIS matches ?
- A034001: row sums, 15 terms agree OEIS nonn (row-sum match: finite agreement only) · view at the OEIS · generated b-file 200 terms from n = 1 ?
- A257620: reversed triangle, 45 terms agree, 9 full rows row-aligned (tabl) OEIS nonn in polytool catalog · view at the OEIS · generated b-file 990 terms from n = 0 ?
- A257620: triangle, 45 terms agree, 9 full rows row-aligned (tabl) OEIS nonn in polytool catalog · view at the OEIS · generated b-file 990 terms from n = 0 ?
- A052690: row sums, 13 terms agree OEIS nonn (row-sum match: finite agreement only) · view at the OEIS
A generated b-file is computed from the node's definition along the row alignment of its OEIS link and starts at the entry's offset. It is an identification on a finite prefix, not a proof that the node and the OEIS entry agree for every n.
OEIS submission text ?
Fields to paste into an OEIS submission: the example %e, the formula
%F and programs %t (Mathematica) and %o (PARI/GP) that list the same rows.
For an OEIS link the row numbers, the offset and the orientation are those of the entry, as matched;
the matched terms were compared with the published ones, which identifies the node with the entry on a
finite prefix, not for every n. The PARI/GP program is not machine-checked here.
The atlas's own rows: n = 0, …, ascending powers of x
%e ExampleTriangle begins: 0: 1; 1: 3, 3; 2: 9, 36, 9; 3: 27, 297, 297, 27; 4: 81, 2106, 5346, 2106, 81; 5: 243, 13851, 73386, 73386, 13851, 243; 6: 729, 87480, 868239, 1761264, 868239, 87480, 729; 7: 2187, 540189, 9388791, 34158753, 34158753, 9388791, 540189, 2187; 8: 6561, 3293622, 95843088, 578903274, 1024762590, 578903274, 95843088, 3293622, 6561; 9: 19683, 19938879, 941634720, 8959544136, 25791697782, 25791697782, 8959544136, 941634720, 19938879, 19683;
%F FormulaThe row polynomials satisfy P(n,x) = (3+3*n*x)*P(n-1,x) + (3*x-3*x^2)*d/dx P(n-1,x) for n >= 1, with P(0,x) = 1.
%t MathematicaP[0, x_] := 1;
P[n_, x_] := P[n, x] = Expand[(3 + 3*n*x)*P[n - 1, x] + (3*x - 3*x^2)*D[P[n - 1, x], x]];
Table[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten%o PARI/GPP(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = (3 + 3*n*x)*v[i - 1] + (3*x - 3*x^2)*deriv(v[i - 1], x)); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)Generated with polytool c48629374597.
A257620: triangle, offset 0, from the row P0
%e ExampleTriangle begins: 0: 1; 1: 3, 3; 2: 9, 36, 9; 3: 27, 297, 297, 27; 4: 81, 2106, 5346, 2106, 81; 5: 243, 13851, 73386, 73386, 13851, 243; 6: 729, 87480, 868239, 1761264, 868239, 87480, 729; 7: 2187, 540189, 9388791, 34158753, 34158753, 9388791, 540189, 2187; 8: 6561, 3293622, 95843088, 578903274, 1024762590, 578903274, 95843088, 3293622, 6561; 9: 19683, 19938879, 941634720, 8959544136, 25791697782, 25791697782, 8959544136, 941634720, 19938879, 19683;
%F FormulaThe row polynomials satisfy P(n,x) = (3+3*n*x)*P(n-1,x) + (3*x-3*x^2)*d/dx P(n-1,x) for n >= 1, with P(0,x) = 1.
%t MathematicaP[0, x_] := 1;
P[n_, x_] := P[n, x] = Expand[(3 + 3*n*x)*P[n - 1, x] + (3*x - 3*x^2)*D[P[n - 1, x], x]];
Table[PadRight[CoefficientList[P[n, x], x], n + 1], {n, 0, 9}] // Flatten%o PARI/GPP(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = (3 + 3*n*x)*v[i - 1] + (3*x - 3*x^2)*deriv(v[i - 1], x)); v};
row(n, p) = {my(c = Vecrev(p)); c = concat(c, vector(n + 1 - #c)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)Generated with polytool c48629374597.
A257620: reversed triangle, offset 0, from the row P0
%e ExampleTriangle begins: 0: 1; 1: 3, 3; 2: 9, 36, 9; 3: 27, 297, 297, 27; 4: 81, 2106, 5346, 2106, 81; 5: 243, 13851, 73386, 73386, 13851, 243; 6: 729, 87480, 868239, 1761264, 868239, 87480, 729; 7: 2187, 540189, 9388791, 34158753, 34158753, 9388791, 540189, 2187; 8: 6561, 3293622, 95843088, 578903274, 1024762590, 578903274, 95843088, 3293622, 6561; 9: 19683, 19938879, 941634720, 8959544136, 25791697782, 25791697782, 8959544136, 941634720, 19938879, 19683;
%F FormulaRow n lists the coefficients of P(n,x) in descending powers of x, where P(n,x) = (3+3*n*x)*P(n-1,x) + (3*x-3*x^2)*d/dx P(n-1,x) for n >= 1, with P(0,x) = 1.
%t MathematicaP[0, x_] := 1;
P[n_, x_] := P[n, x] = Expand[(3 + 3*n*x)*P[n - 1, x] + (3*x - 3*x^2)*D[P[n - 1, x], x]];
Table[Reverse[PadRight[CoefficientList[P[n, x], x], n + 1]], {n, 0, 9}] // Flatten%o PARI/GPP(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = (3 + 3*n*x)*v[i - 1] + (3*x - 3*x^2)*deriv(v[i - 1], x)); v};
row(n, p) = {my(c = Vecrev(p)); c = concat(c, vector(n + 1 - #c)); c = Vecrev(c); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)Generated with polytool c48629374597.
Proved properties
-
Real-rooted. Every row P_n, n >= 0, is zero or real-rooted with all roots in (-inf, 0)
Every polynomial of the sequence has only real roots, inside the stated interval.by the cited steps:
e-563d8c95cca8fabd -
Coefficients of one sign. Every nonzero row, n >= 0: the coefficients of P_n have one sign
All coefficients of each polynomial have the same sign (after x -> -x when alternating).derived from the cited steps by a stated theorem:
e-563d8c95cca8fabd,e-f71cdfb9d254d483 -
Hadamard kernel (Malo). Rows P_n, n >= 0, are Hadamard kernels (preserve real-rootedness)
Multiplying the coefficients of any real-rooted polynomial termwise by those of a row (Hadamard product) gives a real-rooted polynomial again.derived from the cited steps by a stated theorem:
e-563d8c95cca8fabd,e-f71cdfb9d254d483 -
Interlacing of consecutive rows. Rows P_(m-1), P_m interlace (weak, previous interlaces next) for every m >= 1
The roots of consecutive polynomials alternate on the real line.by the cited steps:
e-563d8c95cca8fabd -
Real-rooted. Every row P_n, n >= 0, is zero or real-rooted with all roots in (-inf, 0]
Every polynomial of the sequence has only real roots, inside the stated interval.by the cited steps:
e-f71cdfb9d254d483
Proof chains
2 incoming proof steps. Each step is expanded back to the roots of the proof DAG, the theorem checks of a node's own rule. JSON
-
parent_provers root_domain
e-f71cdfb9d254d483root: theorem checkParent-row provers of polytool polytool ?
-
theorem_check liu_wang
e-563d8c95cca8fabdroot: theorem checkLiu–Wang theorem [LW07, Thm 2.1, Cor 2.4] ?
Used in 3 proof steps
e-184795b7aaceffecgamma_polynomial (scale 1, shift 0) → gamma_polynomial of Triangle read by rows: T(n, k) = t(n-k, k), where t(0,0) = 1, t(n,m) …e-9a566c54793e3e13obreschkoff_combination → obreschkoff_combination of Triangle read by rows: T(n, k) = t(n-k, k), where t(0,0) = 1, …e-9a566c54793e3e13obreschkoff_combination → obreschkoff_combination of Triangle read by rows: T(n, k) = t(n-k, k), where t(0,0) = 1, …
Related sequences ?
Same fingerprint (6)
Equal up to content, sign, reversal and a small index shift.
- A123125: Triangle of Eulerian numbers T(n,k), 0 <= k <= n, read by rows.
- A257609: Triangle read by rows: T(n,k) = t(n-k, k); t(n,m) = f(m)*t(n-1,m) + f(n)*t(n,m-1), where f(x) = 2*x + 2.
- A173018: Euler's triangle: triangle of Eulerian numbers T(n,k) (n>=0, 0 <= k <= n) read by rows.
- A173018 → reverse (shift +1) → reverse
- A008292: Eulerian
- A334218: Triangle read by rows: T(n,k) is the number of permutations of 1..n arranged in a circle with exactly k descen…
References
- [LW07] Lily L. Liu and Yi Wang. A unified approach to polynomial sequences with only real zeros. Advances in Applied Mathematics, 38(4):542–560, May 2007. doi:10.1016/j.aam.2006.02.003