A142075 → x ↦ x/(x+1)
nonnegative coefficients
Proved for all n all roots real, in [−1, 0]coefficients of one signHadamard kernel
Recurrence
\(\left(1 + 2\,x + x^{2}\right)\,P_{n}(x) = \left(1 + 3\,x + x^{2} - 3\,x^{3} - 2\,x^{4} + n x + 3\,n x^{2} + 3\,n x^{3} + n x^{4}\right)\,P_{n-1}(x) + \left(x + 2\,x^{2} - 2\,x^{4} - x^{5}\right)\,P_{n-1}'(x)\)
\(P_{1}(x) = 1\)
Rows ?
| n | x0 | x1 | x2 | x3 | x4 | x5 | x6 | x7 | Pn(1) |
|---|---|---|---|---|---|---|---|---|---|
| 1 | 1 | 1 | |||||||
| 2 | 1 | 3 | 4 | ||||||
| 3 | 1 | 10 | 13 | 24 | |||||
| 4 | 1 | 25 | 91 | 75 | 192 | ||||
| 5 | 1 | 56 | 426 | 896 | 541 | 1920 | |||
| 6 | 1 | 119 | 1674 | 6734 | 9829 | 4683 | 23040 | ||
| 7 | 1 | 246 | 5979 | 40804 | 108039 | 120198 | 47293 | 322560 | |
| 8 | 1 | 501 | 20157 | 218257 | 931347 | 1815951 | 1628911 | 545835 | 5160960 |
Compute more
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Technical details
- Node id
n-d38ac1988a9f3660· revision 0 · JSON- Definition source
derived:mobius_x_over_x_plus_one- Fingerprint
f6-31922ed48acb43c6
Observed on the stored rows ?
- Degrees: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 (affine: slope 1, intercept -1)
- Palindromic rows: no
- γ-positive (gamma_positive): no
- Nonnegative coefficients (
nonn): yes - Only rational roots (
rr_by_factors: every nonzero row is a product of linear factors over ℚ): no
Matches ?
No OEIS matches.
Submission text ?
Atlas rows n = 1, …, ascending powers of x
%e ExampleTriangle begins: 1: 1; 2: 1, 3; 3: 1, 10, 13; 4: 1, 25, 91, 75; 5: 1, 56, 426, 896, 541; 6: 1, 119, 1674, 6734, 9829, 4683; 7: 1, 246, 5979, 40804, 108039, 120198, 47293; 8: 1, 501, 20157, 218257, 931347, 1815951, 1628911, 545835; 9: 1, 1012, 65488, 1077604, 6940090, 21082204, 32355928, 24287692, 7087261; 10: 1, 2035, 207604, 5037868, 46947022, 208222234, 486156100, 613463356, 395661817, 102247563;
%F FormulaThe row polynomials satisfy (1+2*x+x^2)*P(n,x) = (1+(n+3)*x+(3*n+1)*x^2+(3*n-3)*x^3+(n-2)*x^4)*P(n-1,x) + (x+2*x^2-2*x^4-x^5)*d/dx P(n-1,x) for n >= 2, with P(1,x) = 1.
%t MathematicaP[1, x_] := 1;
P[n_, x_] := P[n, x] = Expand[Together[((1 + (n + 3)*x + (3*n + 1)*x^2 + (3*n - 3)*x^3 + (n - 2)*x^4)*P[n - 1, x] + (x + 2*x^2 - 2*x^4 - x^5)*D[P[n - 1, x], x])/(1 + 2*x + x^2)]];
Table[CoefficientList[P[n, x], x], {n, 1, 10}] // Flatten%o PARI/GPP(N) = {my(v = vector(N)); v[1] = 1; for(n = 2, N, my(i = n); v[i] = ((1 + (n + 3)*x + (3*n + 1)*x^2 + (3*n - 3)*x^3 + (n - 2)*x^4)*v[i - 1] + (x + 2*x^2 - 2*x^4 - x^5)*deriv(v[i - 1], x))/(1 + 2*x + x^2)); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i, v[i])))};
T(10)polytool c48629374597
Properties
- Real-rooted? Every row P_n, n ≥ 1, is zero or real-rooted with all roots in [-1, 0]
- Coefficients of one sign? Every nonzero row, n ≥ 1: the coefficients of P_n have one sign
- Hadamard kernel (Malo)? Rows P_n, n ≥ 1, are Hadamard kernels (preserve real-rootedness)
Proof chains ? JSON
Related ?
Same fingerprint ?
References
- [LW07] Lily L. Liu and Yi Wang. A unified approach to polynomial sequences with only real zeros. Advances in Applied Mathematics, 38(4):542–560, May 2007. doi:10.1016/j.aam.2006.02.003