A173018 → reverse (shift +1) → x ↦ x/(x+1)
nonnegative coefficients
Proved for all n: all roots real, in [−1, 0] · coefficients of one sign · Hadamard kernel what this means
Rows ?
| n | x0 | x1 | x2 | x3 | x4 | x5 | x6 | x7 | x8 | x9 | x10 | x11 | x12 | x13 | x14 | Pn(1) |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 0 | 1 | 1 | ||||||||||||||
| 1 | 0 | 1 | 1 | |||||||||||||
| 2 | 0 | 1 | 2 | 3 | ||||||||||||
| 3 | 0 | 1 | 6 | 6 | 13 | |||||||||||
| 4 | 0 | 1 | 14 | 36 | 24 | 75 | ||||||||||
| 5 | 0 | 1 | 30 | 150 | 240 | 120 | 541 | |||||||||
| 6 | 0 | 1 | 62 | 540 | 1560 | 1800 | 720 | 4683 | ||||||||
| 7 | 0 | 1 | 126 | 1806 | 8400 | 16800 | 15120 | 5040 | 47293 | |||||||
| 8 | 0 | 1 | 254 | 5796 | 40824 | 126000 | 191520 | 141120 | 40320 | 545835 | ||||||
| 9 | 0 | 1 | 510 | 18150 | 186480 | 834120 | 1905120 | 2328480 | 1451520 | 362880 | 7087261 | |||||
| 10 | 0 | 1 | 1022 | 55980 | 818520 | 5103000 | 16435440 | 29635200 | 30240000 | 16329600 | 3628800 | 102247563 | ||||
| 11 | 0 | 1 | 2046 | 171006 | 3498000 | 29607600 | 129230640 | 322494480 | 479001600 | 419126400 | 199584000 | 39916800 | 1622632573 | |||
| 12 | 0 | 1 | 4094 | 519156 | 14676024 | 165528000 | 953029440 | 3162075840 | 6411968640 | 8083152000 | 6187104000 | 2634508800 | 479001600 | 28091567595 | ||
| 13 | 0 | 1 | 8190 | 1569750 | 60780720 | 901020120 | 6711344640 | 28805736960 | 76592355840 | 130456085760 | 142702560000 | 97037740800 | 37362124800 | 6227020800 | 526858348381 | |
| 14 | 0 | 1 | 16382 | 4733820 | 249401880 | 4809004200 | 45674188560 | 248619571200 | 843184742400 | 1863435974400 | 2731586457600 | 2637143308800 | 1612798387200 | 566658892800 | 87178291200 | 10641342970443 |
Generated b-files: A000670 (row sums), A019538, A090582 (reversed triangle), A131689 ?
Computed in your browser ?
Technical details
- Node id
n-c9bb7a76ea8cdc0d· revision 1 · JSON- Definition source
derived:mobius_x_over_x_plus_one- Fingerprint
f6-a83eeccfb5efd735
Observed on the stored rows ?
- Degrees: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 (affine: slope 1, intercept 0)
- Palindromic rows: no
- γ-positive (gamma_positive): no
- Nonnegative coefficients (
nonn): yes - Only rational roots (
rr_by_factors: every nonzero row is a product of linear factors over ℚ): no
OEIS matches ?
- A000670: row sums, 15 terms agree OEIS nonn (row-sum match: finite agreement only) · view at the OEIS · generated b-file 200 terms from n = 0 ?
- A090582: reversed triangle, 55 terms agree, 10 full rows row-aligned (tabl) OEIS nonn in polytool catalog · view at the OEIS · generated b-file 990 terms from n = 1 ?
- A019538: triangle, 55 terms agree, 10 full rows row-aligned (tabl) OEIS nonn in polytool catalog · view at the OEIS · generated b-file 990 terms from n = 1 ?
- A131689: triangle, 55 terms agree, 10 full rows row-aligned (tabl) OEIS nonn in polytool catalog · view at the OEIS · generated b-file 990 terms from n = 0 ?
- A034172: row sums, 15 terms agree OEIS nonn (row-sum match: finite agreement only) · view at the OEIS
A generated b-file is computed from the node's definition along the row alignment of its OEIS link and starts at the entry's offset. It is an identification on a finite prefix, not a proof that the node and the OEIS entry agree for every n.
OEIS submission text ?
Fields to paste into an OEIS submission: the example %e, the formula
%F and programs %t (Mathematica) and %o (PARI/GP) that list the same rows.
For an OEIS link the row numbers, the offset and the orientation are those of the entry, as matched;
the matched terms were compared with the published ones, which identifies the node with the entry on a
finite prefix, not for every n. The PARI/GP program is not machine-checked here.
The atlas's own rows: n = 0, …, ascending powers of x
%e ExampleTriangle begins: 0: 1; 1: 0, 1; 2: 0, 1, 2; 3: 0, 1, 6, 6; 4: 0, 1, 14, 36, 24; 5: 0, 1, 30, 150, 240, 120; 6: 0, 1, 62, 540, 1560, 1800, 720; 7: 0, 1, 126, 1806, 8400, 16800, 15120, 5040; 8: 0, 1, 254, 5796, 40824, 126000, 191520, 141120, 40320; 9: 0, 1, 510, 18150, 186480, 834120, 1905120, 2328480, 1451520, 362880;
%F FormulaThe row polynomials satisfy (1+2*x+x^2)*P(n,x) = (x+2*x^2+x^3)*P(n-1,x) + (x+3*x^2+3*x^3+x^4)*d/dx P(n-1,x) for n >= 1, with P(0,x) = 1.
%t MathematicaP[0, x_] := 1;
P[n_, x_] := P[n, x] = Expand[Together[((x + 2*x^2 + x^3)*P[n - 1, x] + (x + 3*x^2 + 3*x^3 + x^4)*D[P[n - 1, x], x])/(1 + 2*x + x^2)]];
Table[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten%o PARI/GPP(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = ((x + 2*x^2 + x^3)*v[i - 1] + (x + 3*x^2 + 3*x^3 + x^4)*deriv(v[i - 1], x))/(1 + 2*x + x^2)); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)Generated with polytool c48629374597.
A019538: triangle, offset 1, from the row P1, low zeros dropped
%e ExampleTriangle begins: 1: 1; 2: 1, 2; 3: 1, 6, 6; 4: 1, 14, 36, 24; 5: 1, 30, 150, 240, 120; 6: 1, 62, 540, 1560, 1800, 720; 7: 1, 126, 1806, 8400, 16800, 15120, 5040; 8: 1, 254, 5796, 40824, 126000, 191520, 141120, 40320; 9: 1, 510, 18150, 186480, 834120, 1905120, 2328480, 1451520, 362880; 10: 1, 1022, 55980, 818520, 5103000, 16435440, 29635200, 30240000, 16329600, 3628800;
%F FormulaRow n lists the coefficients of P(n,x) in ascending powers of x, starting at the lowest nonzero coefficient, where (1+2*x+x^2)*P(n,x) = (x+2*x^2+x^3)*P(n-1,x) + (x+3*x^2+3*x^3+x^4)*d/dx P(n-1,x) for n >= 2, with P(1,x) = x.
%t MathematicaP[1, x_] := x;
P[n_, x_] := P[n, x] = Expand[Together[((x + 2*x^2 + x^3)*P[n - 1, x] + (x + 3*x^2 + 3*x^3 + x^4)*D[P[n - 1, x], x])/(1 + 2*x + x^2)]];
Table[PadRight[CoefficientList[Expand[P[n, x]/x^Exponent[P[n, x], x, Min]], x], n], {n, 1, 10}] // Flatten%o PARI/GPP(N) = {my(v = vector(N)); v[1] = x; for(n = 2, N, my(i = n); v[i] = ((x + 2*x^2 + x^3)*v[i - 1] + (x + 3*x^2 + 3*x^3 + x^4)*deriv(v[i - 1], x))/(1 + 2*x + x^2)); v};
row(n, p) = {my(c = Vecrev(p/x^valuation(p, x))); c = concat(c, vector(n - #c)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i, v[i])))};
T(10)Generated with polytool c48629374597.
A090582: reversed triangle, offset 1, from the row P1, low zeros dropped
%e ExampleTriangle begins: 1: 1; 2: 2, 1; 3: 6, 6, 1; 4: 24, 36, 14, 1; 5: 120, 240, 150, 30, 1; 6: 720, 1800, 1560, 540, 62, 1; 7: 5040, 15120, 16800, 8400, 1806, 126, 1; 8: 40320, 141120, 191520, 126000, 40824, 5796, 254, 1; 9: 362880, 1451520, 2328480, 1905120, 834120, 186480, 18150, 510, 1; 10: 3628800, 16329600, 30240000, 29635200, 16435440, 5103000, 818520, 55980, 1022, 1;
%F FormulaRow n lists the coefficients of P(n,x) in descending powers of x, down to the lowest nonzero coefficient, where (1+2*x+x^2)*P(n,x) = (x+2*x^2+x^3)*P(n-1,x) + (x+3*x^2+3*x^3+x^4)*d/dx P(n-1,x) for n >= 2, with P(1,x) = x.
%t MathematicaP[1, x_] := x;
P[n_, x_] := P[n, x] = Expand[Together[((x + 2*x^2 + x^3)*P[n - 1, x] + (x + 3*x^2 + 3*x^3 + x^4)*D[P[n - 1, x], x])/(1 + 2*x + x^2)]];
Table[Reverse[PadRight[CoefficientList[Expand[P[n, x]/x^Exponent[P[n, x], x, Min]], x], n]], {n, 1, 10}] // Flatten%o PARI/GPP(N) = {my(v = vector(N)); v[1] = x; for(n = 2, N, my(i = n); v[i] = ((x + 2*x^2 + x^3)*v[i - 1] + (x + 3*x^2 + 3*x^3 + x^4)*deriv(v[i - 1], x))/(1 + 2*x + x^2)); v};
row(n, p) = {my(c = Vecrev(p/x^valuation(p, x))); c = concat(c, vector(n - #c)); c = Vecrev(c); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i, v[i])))};
T(10)Generated with polytool c48629374597.
A131689: triangle, offset 0, from the row P0
%e ExampleTriangle begins: 0: 1; 1: 0, 1; 2: 0, 1, 2; 3: 0, 1, 6, 6; 4: 0, 1, 14, 36, 24; 5: 0, 1, 30, 150, 240, 120; 6: 0, 1, 62, 540, 1560, 1800, 720; 7: 0, 1, 126, 1806, 8400, 16800, 15120, 5040; 8: 0, 1, 254, 5796, 40824, 126000, 191520, 141120, 40320; 9: 0, 1, 510, 18150, 186480, 834120, 1905120, 2328480, 1451520, 362880;
%F FormulaThe row polynomials satisfy (1+2*x+x^2)*P(n,x) = (x+2*x^2+x^3)*P(n-1,x) + (x+3*x^2+3*x^3+x^4)*d/dx P(n-1,x) for n >= 1, with P(0,x) = 1.
%t MathematicaP[0, x_] := 1;
P[n_, x_] := P[n, x] = Expand[Together[((x + 2*x^2 + x^3)*P[n - 1, x] + (x + 3*x^2 + 3*x^3 + x^4)*D[P[n - 1, x], x])/(1 + 2*x + x^2)]];
Table[PadRight[CoefficientList[P[n, x], x], n + 1], {n, 0, 9}] // Flatten%o PARI/GPP(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = ((x + 2*x^2 + x^3)*v[i - 1] + (x + 3*x^2 + 3*x^3 + x^4)*deriv(v[i - 1], x))/(1 + 2*x + x^2)); v};
row(n, p) = {my(c = Vecrev(p)); c = concat(c, vector(n + 1 - #c)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)Generated with polytool c48629374597.
Proved properties
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Real-rooted. Every row P_n, n >= 0, is zero or real-rooted with all roots in [-1, 0]
Every polynomial of the sequence has only real roots, inside the stated interval.by the cited steps:
e-e273b6c51200d112 -
Coefficients of one sign. Every nonzero row, n >= 0: the coefficients of P_n have one sign
All coefficients of each polynomial have the same sign (after x -> -x when alternating).derived from the cited steps by a stated theorem:
e-e273b6c51200d112 -
Hadamard kernel (Malo). Rows P_n, n >= 0, are Hadamard kernels (preserve real-rootedness)
Multiplying the coefficients of any real-rooted polynomial termwise by those of a row (Hadamard product) gives a real-rooted polynomial again.derived from the cited steps by a stated theorem:
e-e273b6c51200d112
Proof chains
1 incoming proof step. Each step is expanded back to the roots of the proof DAG, the theorem checks of a node's own rule. JSON
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preserver_image mobius, shift 0
e-e273b6c51200d112Affine, reversal and Möbius substitutions (elementary) polytool ?
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premise (sequence):
Triangle of Eulerian numbers T(n,k), 0 <= k <= n, read by rows.
uses: Every row P_n, n >= 0, is zero or real-rooted with all roots in (-inf, 0]
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preserver_image reversal, shift 1
e-61bc78adfe1eb25aAffine, reversal and Möbius substitutions (elementary) polytool ?
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premise (sequence):
Euler's triangle: triangle of Eulerian numbers T(n,k) (n>=0, 0 <= k <= n) read by rows.
uses: Every row P_n, n >= 1, is zero or real-rooted with all roots in (-inf, 0]
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theorem_check liu_wang
e-083b494dcfd2f637root: theorem checkLiu–Wang theorem [LW07, Thm 2.1, Cor 2.4] ?
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parent_provers root_domain
e-ffc8a9fffd6e96cbroot: theorem checkParent-row provers of polytool polytool ?
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premise (sequence):
Euler's triangle: triangle of Eulerian numbers T(n,k) (n>=0, 0 <= k <= n) read by rows.
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premise (sequence):
Triangle of Eulerian numbers T(n,k), 0 <= k <= n, read by rows.
Related sequences ?
Same fingerprint (5)
Equal up to content, sign, reversal and a small index shift.
- A008292 → x ↦ x+1
- A131689 → reverse
- A090582: T(n, k) = Sum_{j=0..n-k} (-1)^j*binomial(n - k + 1, j)*(n - k + 1 - j)^n. Triangle read by rows, T(n, k) for 1…
- A131689: Triangle of numbers T(n,k) = k!*Stirling2(n,k) = A000142(k)*A048993(n,k) read by rows, T(n, k) for 0 <= k <= n.
- A019538: Triangle of numbers T(n,k) = k!*Stirling2(n,k) read by rows (n >= 1, 1 <= k <= n).
References
- [LW07] Lily L. Liu and Yi Wang. A unified approach to polynomial sequences with only real zeros. Advances in Applied Mathematics, 38(4):542–560, May 2007. doi:10.1016/j.aam.2006.02.003