A257613: Triangle read by rows: T(n,k) = t(n-k, k); t(n,m) = f(m)*t(n-1,m) + f(n)*t(n,m-1), where f(x) = 2*x + 4.
A257613 palindromic γ-positive nonnegative coefficients
Proved for all n: all roots real, in (−∞, 0) · coefficients of one sign · interlacing (weak) · Hadamard kernel what this means
Rows ?
| n | x0 | x1 | x2 | x3 | x4 | x5 | x6 | x7 | x8 | x9 | x10 | x11 | x12 | x13 | x14 | Pn(1) |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 0 | 1 | 1 | ||||||||||||||
| 1 | 4 | 4 | 8 | |||||||||||||
| 2 | 16 | 48 | 16 | 80 | ||||||||||||
| 3 | 64 | 416 | 416 | 64 | 960 | |||||||||||
| 4 | 256 | 3136 | 6656 | 3136 | 256 | 13440 | ||||||||||
| 5 | 1024 | 21888 | 84608 | 84608 | 21888 | 1024 | 215040 | |||||||||
| 6 | 4096 | 145664 | 939520 | 1692160 | 939520 | 145664 | 4096 | 3870720 | ||||||||
| 7 | 16384 | 939520 | 9555456 | 28195840 | 28195840 | 9555456 | 939520 | 16384 | 77414400 | |||||||
| 8 | 65536 | 5932032 | 91475968 | 415734784 | 676700160 | 415734784 | 91475968 | 5932032 | 65536 | 1703116800 | ||||||
| 9 | 262144 | 36902912 | 838584320 | 5620963328 | 13940688896 | 13940688896 | 5620963328 | 838584320 | 36902912 | 262144 | 40874803200 | |||||
| 10 | 1048576 | 227184640 | 7446732800 | 71304151040 | 257223680000 | 390339289088 | 257223680000 | 71304151040 | 7446732800 | 227184640 | 1048576 | 1062744883200 | ||||
| 11 | 4194304 | 1388273664 | 64571924480 | 861976166400 | 4370158878720 | 9580328927232 | 9580328927232 | 4370158878720 | 861976166400 | 64571924480 | 1388273664 | 4194304 | 29756856729600 | |||
| 12 | 16777216 | 8438693888 | 549893963776 | 10040344002560 | 69681429872640 | 212787464798208 | 306570525671424 | 212787464798208 | 69681429872640 | 10040344002560 | 549893963776 | 8438693888 | 16777216 | 892705701888000 | ||
| 13 | 67108864 | 51101925376 | 4618557751296 | 113600895156224 | 1057064726528000 | 4372653104627712 | 8735302777110528 | 8735302777110528 | 4372653104627712 | 1057064726528000 | 113600895156224 | 4618557751296 | 51101925376 | 67108864 | 28566582460416000 | |
| 14 | 268435456 | 308624818176 | 38379315920896 | 1256091453095936 | 15411198202085376 | 84472567448403968 | 227217906526322688 | 314470899975979008 | 227217906526322688 | 84472567448403968 | 15411198202085376 | 1256091453095936 | 38379315920896 | 308624818176 | 268435456 | 971263803654144000 |
Generated b-files: A051580 (row sums), A257613, A257613 (reversed triangle) ?
Computed in your browser ?
Technical details
- Node id
n-c35e92273dac3e06· revision 1 · JSON- Definition source
oeis_catalog:A257613- Fingerprint
f6-9f31c05ba8767dc5
Observed on the stored rows ?
- Degrees: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 (affine: slope 1, intercept 0)
- Palindromic rows: yes
- γ-positive (gamma_positive): yes
- Nonnegative coefficients (
nonn): yes - Only rational roots (
rr_by_factors: every nonzero row is a product of linear factors over ℚ): no
OEIS matches ?
- A257613: reversed triangle, 45 terms agree, 9 full rows row-aligned (tabl) OEIS nonn in polytool catalog · view at the OEIS · generated b-file 990 terms from n = 0 ?
- A257613: triangle, 45 terms agree, 9 full rows row-aligned (tabl) OEIS nonn in polytool catalog · view at the OEIS · generated b-file 990 terms from n = 0 ?
- A051580: row sums, 15 terms agree OEIS nonn (row-sum match: finite agreement only) · view at the OEIS · generated b-file 200 terms from n = 0 ?
A generated b-file is computed from the node's definition along the row alignment of its OEIS link and starts at the entry's offset. It is an identification on a finite prefix, not a proof that the node and the OEIS entry agree for every n.
OEIS submission text ?
Fields to paste into an OEIS submission: the example %e, the formula
%F and programs %t (Mathematica) and %o (PARI/GP) that list the same rows.
For an OEIS link the row numbers, the offset and the orientation are those of the entry, as matched;
the matched terms were compared with the published ones, which identifies the node with the entry on a
finite prefix, not for every n. The PARI/GP program is not machine-checked here.
The atlas's own rows: n = 0, …, ascending powers of x
%e ExampleTriangle begins: 0: 1; 1: 4, 4; 2: 16, 48, 16; 3: 64, 416, 416, 64; 4: 256, 3136, 6656, 3136, 256; 5: 1024, 21888, 84608, 84608, 21888, 1024; 6: 4096, 145664, 939520, 1692160, 939520, 145664, 4096; 7: 16384, 939520, 9555456, 28195840, 28195840, 9555456, 939520, 16384; 8: 65536, 5932032, 91475968, 415734784, 676700160, 415734784, 91475968, 5932032, 65536; 9: 262144, 36902912, 838584320, 5620963328, 13940688896, 13940688896, 5620963328, 838584320, 36902912, 262144;
%F FormulaThe row polynomials satisfy P(n,x) = (4+(2*n+2)*x)*P(n-1,x) + (2*x-2*x^2)*d/dx P(n-1,x) for n >= 1, with P(0,x) = 1.
%t MathematicaP[0, x_] := 1;
P[n_, x_] := P[n, x] = Expand[(4 + (2*n + 2)*x)*P[n - 1, x] + (2*x - 2*x^2)*D[P[n - 1, x], x]];
Table[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten%o PARI/GPP(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = (4 + (2*n + 2)*x)*v[i - 1] + (2*x - 2*x^2)*deriv(v[i - 1], x)); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)Generated with polytool c48629374597.
A257613: triangle, offset 0, from the row P0
%e ExampleTriangle begins: 0: 1; 1: 4, 4; 2: 16, 48, 16; 3: 64, 416, 416, 64; 4: 256, 3136, 6656, 3136, 256; 5: 1024, 21888, 84608, 84608, 21888, 1024; 6: 4096, 145664, 939520, 1692160, 939520, 145664, 4096; 7: 16384, 939520, 9555456, 28195840, 28195840, 9555456, 939520, 16384; 8: 65536, 5932032, 91475968, 415734784, 676700160, 415734784, 91475968, 5932032, 65536; 9: 262144, 36902912, 838584320, 5620963328, 13940688896, 13940688896, 5620963328, 838584320, 36902912, 262144;
%F FormulaThe row polynomials satisfy P(n,x) = (4+(2*n+2)*x)*P(n-1,x) + (2*x-2*x^2)*d/dx P(n-1,x) for n >= 1, with P(0,x) = 1.
%t MathematicaP[0, x_] := 1;
P[n_, x_] := P[n, x] = Expand[(4 + (2*n + 2)*x)*P[n - 1, x] + (2*x - 2*x^2)*D[P[n - 1, x], x]];
Table[PadRight[CoefficientList[P[n, x], x], n + 1], {n, 0, 9}] // Flatten%o PARI/GPP(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = (4 + (2*n + 2)*x)*v[i - 1] + (2*x - 2*x^2)*deriv(v[i - 1], x)); v};
row(n, p) = {my(c = Vecrev(p)); c = concat(c, vector(n + 1 - #c)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)Generated with polytool c48629374597.
A257613: reversed triangle, offset 0, from the row P0
%e ExampleTriangle begins: 0: 1; 1: 4, 4; 2: 16, 48, 16; 3: 64, 416, 416, 64; 4: 256, 3136, 6656, 3136, 256; 5: 1024, 21888, 84608, 84608, 21888, 1024; 6: 4096, 145664, 939520, 1692160, 939520, 145664, 4096; 7: 16384, 939520, 9555456, 28195840, 28195840, 9555456, 939520, 16384; 8: 65536, 5932032, 91475968, 415734784, 676700160, 415734784, 91475968, 5932032, 65536; 9: 262144, 36902912, 838584320, 5620963328, 13940688896, 13940688896, 5620963328, 838584320, 36902912, 262144;
%F FormulaRow n lists the coefficients of P(n,x) in descending powers of x, where P(n,x) = (4+(2*n+2)*x)*P(n-1,x) + (2*x-2*x^2)*d/dx P(n-1,x) for n >= 1, with P(0,x) = 1.
%t MathematicaP[0, x_] := 1;
P[n_, x_] := P[n, x] = Expand[(4 + (2*n + 2)*x)*P[n - 1, x] + (2*x - 2*x^2)*D[P[n - 1, x], x]];
Table[Reverse[PadRight[CoefficientList[P[n, x], x], n + 1]], {n, 0, 9}] // Flatten%o PARI/GPP(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = (4 + (2*n + 2)*x)*v[i - 1] + (2*x - 2*x^2)*deriv(v[i - 1], x)); v};
row(n, p) = {my(c = Vecrev(p)); c = concat(c, vector(n + 1 - #c)); c = Vecrev(c); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)Generated with polytool c48629374597.
Proved properties
-
Real-rooted. Every row P_n, n >= 0, is zero or real-rooted with all roots in (-inf, 0)
Every polynomial of the sequence has only real roots, inside the stated interval.by the cited steps:
e-5e8558eb5869f0da -
Coefficients of one sign. Every nonzero row, n >= 0: the coefficients of P_n have one sign
All coefficients of each polynomial have the same sign (after x -> -x when alternating).derived from the cited steps by a stated theorem:
e-5e8558eb5869f0da -
Hadamard kernel (Malo). Rows P_n, n >= 0, are Hadamard kernels (preserve real-rootedness)
Multiplying the coefficients of any real-rooted polynomial termwise by those of a row (Hadamard product) gives a real-rooted polynomial again.derived from the cited steps by a stated theorem:
e-5e8558eb5869f0da -
Interlacing of consecutive rows. Rows P_(m-1), P_m interlace (weak, previous interlaces next) for every m >= 1
The roots of consecutive polynomials alternate on the real line.by the cited steps:
e-5e8558eb5869f0da
Proof chains
1 incoming proof step. Each step is expanded back to the roots of the proof DAG, the theorem checks of a node's own rule. JSON
-
theorem_check liu_wang
e-5e8558eb5869f0daroot: theorem checkLiu–Wang theorem [LW07, Thm 2.1, Cor 2.4] ?
Used in 3 proof steps
e-9ebbae09ad25fd6cgamma_polynomial (scale 1, shift 0) → gamma_polynomial of Triangle read by rows: T(n,k) = t(n-k, k); t(n,m) = f(m)*t(n-1,m) + f…e-2b0de764d6dd6b90obreschkoff_combination → obreschkoff_combination of Triangle read by rows: T(n,k) = t(n-k, k); t(n,m) = f(m)*t(n-1…e-2b0de764d6dd6b90obreschkoff_combination → obreschkoff_combination of Triangle read by rows: T(n,k) = t(n-k, k); t(n,m) = f(m)*t(n-1…
Related sequences ?
Same fingerprint (2)
Equal up to content, sign, reversal and a small index shift.
- A257626: Triangle read by rows: T(n,k) = t(n-k, k); t(n,m) = f(m)*t(n-1,m) + f(n)*t(n,m-1), where f(x) = 3*x + 6.
- Triangle T(n,k) = t(n-k, k); t(n,m) = f(m)*t(n-1,m) + f(n)*t(n,m-1), where f(x) = x + 2.
References
- [LW07] Lily L. Liu and Yi Wang. A unified approach to polynomial sequences with only real zeros. Advances in Applied Mathematics, 38(4):542–560, May 2007. doi:10.1016/j.aam.2006.02.003