basis-map coefficients of A297191, shifted → θ+1 → D+1

nonnegative coefficientsonly rational roots

Proved for all n all roots real, in (−∞, 0]coefficients of one signHadamard kernel

Recurrence

\(\left(2 - x - 6\,n + 2\,n x + 4\,n^{2}\right)\,P_{n}(x) = \left(x^{3} + 2\,n x^{2} + 2\,n x^{3} + 4\,n^{2} x^{2}\right)\,P_{n-1}(x)\)
\(P_{0}(x) = 1\)

Rows ?

nx0x1x2x3x4x5x6x7x8x9x10x11x12x13x14x15x16x17x18x19x20x21x22x23x24x25x26x27x28Pn(1)
011
10639
200020525
30000042749
4000000072981
500000000011011121
60000000000015613169
7000000000000021015225
800000000000000027217289
90000000000000000034219361
10000000000000000000042021441
1100000000000000000000050623529
120000000000000000000000060025625
13000000000000000000000000070227729
1400000000000000000000000000081229841
Technical details
Node id
n-bba94d317225399f · revision 0 · JSON
Definition source
derived:one_plus_derivative
Fingerprint
f6-b43ca45c584c54a9

Observed on the stored rows ?

  • Degrees: 0, 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28 (affine: slope 2, intercept 0)
  • Palindromic rows: no
  • γ-positive (gamma_positive): no
  • Nonnegative coefficients (nonn): yes
  • Only rational roots (rr_by_factors: every nonzero row is a product of linear factors over ℚ): yes

Matches ?

No OEIS matches.

Submission text ?

Atlas rows n = 0, …, ascending powers of x
%e Example
Triangle begins:
  0: 1;
  1: 0, 6, 3;
  2: 0, 0, 0, 20, 5;
  3: 0, 0, 0,  0, 0, 42, 7;
  4: 0, 0, 0,  0, 0,  0, 0, 72, 9;
  5: 0, 0, 0,  0, 0,  0, 0,  0, 0, 110, 11;
  6: 0, 0, 0,  0, 0,  0, 0,  0, 0,   0,  0, 156, 13;
  7: 0, 0, 0,  0, 0,  0, 0,  0, 0,   0,  0,   0,  0, 210, 15;
  8: 0, 0, 0,  0, 0,  0, 0,  0, 0,   0,  0,   0,  0,   0,  0, 272, 17;
  9: 0, 0, 0,  0, 0,  0, 0,  0, 0,   0,  0,   0,  0,   0,  0,   0,  0, 342, 19;
%F Formula
The row polynomials satisfy (4*n^2-6*n+2+(2*n-1)*x)*P(n,x) = ((4*n^2+2*n)*x^2+(2*n+1)*x^3)*P(n-1,x) for n >= 1, with P(0,x) = 1.
%t Mathematica
P[0, x_] := 1;
P[n_, x_] := P[n, x] = Expand[Together[(((4*n^2 + 2*n)*x^2 + (2*n + 1)*x^3)*P[n - 1, x])/(4*n^2 - 6*n + 2 + (2*n - 1)*x)]];
Table[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten
%o PARI/GP
P(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = (((4*n^2 + 2*n)*x^2 + (2*n + 1)*x^3)*v[i - 1])/(4*n^2 - 6*n + 2 + (2*n - 1)*x)); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)

polytool c48629374597

Properties

Proof chains ? JSON

Same fingerprint ?

References

  1. [Bra06] Petter Brändén. On linear transformations preserving the Pólya frequency property. Transactions of the American Mathematical Society, 358(8):3697–3716, February 2006. doi:10.1090/s0002-9947-06-03856-6
  2. [Bra15] Petter Brändén. Unimodality, log-concavity, real-rootedness and beyond. Handbook of enumerative combinatorics, :437–483, March 2015. doi:10.1201/b18255-10
  3. [SP14] J Schur and G Polya. Über zwei Arten von Faktorenfolgen in der Theorie der algebraischen Gleichungen. J. Reine Angew. Math., 1914.