A081580 → basis A007318 → reverse
nonnegative coefficients
Proved for all n all roots real, in (−∞, 0]coefficients of one signHadamard kernel
Recurrence
\(\left(n\right)\,P_{n}(x) = \left(36\,x^{2} + 48\,x^{3} + n - 5\,n x - 60\,n x^{2} - 72\,n x^{3} + 7\,n^{2} x + 24\,n^{2} x^{2} + 24\,n^{2} x^{3}\right)\,P_{n-1}(x) + \left(37\,x^{2} + 132\,x^{3} + 96\,x^{4} - n x - 26\,n x^{2} - 72\,n x^{3} - 48\,n x^{4}\right)\,P_{n-1}'(x) + \left(x^{2} + 25\,x^{3} + 48\,x^{4} + 24\,x^{5}\right)\,P_{n-1}''(x)\)
\(P_{0}(x) = 1\)
Rows ?
| n | x0 | x1 | x2 | x3 | x4 | x5 | x6 | x7 | Pn(1) |
|---|---|---|---|---|---|---|---|---|---|
| 0 | 1 | 1 | |||||||
| 1 | 1 | 2 | 3 | ||||||
| 2 | 1 | 9 | 9 | 19 | |||||
| 3 | 1 | 16 | 42 | 28 | 87 | ||||
| 4 | 1 | 23 | 124 | 202 | 101 | 451 | |||
| 5 | 1 | 30 | 255 | 740 | 855 | 342 | 2223 | ||
| 6 | 1 | 37 | 435 | 1985 | 3965 | 3567 | 1189 | 11179 | |
| 7 | 1 | 44 | 664 | 4280 | 12910 | 19472 | 14308 | 4088 | 55767 |
Compute more
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Technical details
- Node id
n-a4508f583538f67c· revision 0 · JSON- Definition source
derived:reversal- Fingerprint
f6-b123934b80f387c2
Observed on the stored rows ?
- Degrees: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 (affine: slope 1, intercept 0)
- Palindromic rows: no
- γ-positive (gamma_positive): no
- Nonnegative coefficients (
nonn): yes - Only rational roots (
rr_by_factors: every nonzero row is a product of linear factors over ℚ): no
Matches ?
No OEIS matches.
Submission text ?
Atlas rows n = 0, …, ascending powers of x
%e ExampleTriangle begins: 0: 1; 1: 1, 2; 2: 1, 9, 9; 3: 1, 16, 42, 28; 4: 1, 23, 124, 202, 101; 5: 1, 30, 255, 740, 855, 342; 6: 1, 37, 435, 1985, 3965, 3567, 1189; 7: 1, 44, 664, 4280, 12910, 19472, 14308, 4088; 8: 1, 51, 942, 7968, 33570, 75042, 90912, 56484, 14121; 9: 1, 58, 1269, 13392, 74226, 228132, 402906, 407208, 219069, 48682;
%F FormulaThe row polynomials satisfy n*P(n,x) = (n+(7*n^2-5*n)*x+(24*n^2-60*n+36)*x^2+(24*n^2-72*n+48)*x^3)*P(n-1,x) - (n*x+(26*n-37)*x^2+(72*n-132)*x^3+(48*n-96)*x^4)*d/dx P(n-1,x) + (x^2+25*x^3+48*x^4+24*x^5)*d^2/dx^2 P(n-1,x) for n >= 1, with P(0,x) = 1.
%t MathematicaP[0, x_] := 1;
P[n_, x_] := P[n, x] = Expand[Together[((n + (7*n^2 - 5*n)*x + (24*n^2 - 60*n + 36)*x^2 + (24*n^2 - 72*n + 48)*x^3)*P[n - 1, x] - (n*x + (26*n - 37)*x^2 + (72*n - 132)*x^3 + (48*n - 96)*x^4)*D[P[n - 1, x], x] + (x^2 + 25*x^3 + 48*x^4 + 24*x^5)*D[P[n - 1, x], {x, 2}])/(n)]];
Table[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten%o PARI/GPP(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = ((n + (7*n^2 - 5*n)*x + (24*n^2 - 60*n + 36)*x^2 + (24*n^2 - 72*n + 48)*x^3)*v[i - 1] - (n*x + (26*n - 37)*x^2 + (72*n - 132)*x^3 + (48*n - 96)*x^4)*deriv(v[i - 1], x) + (x^2 + 25*x^3 + 48*x^4 + 24*x^5)*deriv(deriv(v[i - 1], x), x))/(n)); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)polytool c48629374597
Properties
- Real-rooted? Every row P_n, n ≥ 0, is zero or real-rooted with all roots in (−∞, 0]
- Coefficients of one sign? Every nonzero row, n ≥ 0: the coefficients of P_n have one sign
- Hadamard kernel (Malo)? Rows P_n, n ≥ 0, are Hadamard kernels (preserve real-rootedness)
Proof chains ? JSON
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Affine, reversal and Möbius substitutions (elementary) polytool ? step ›
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from
basis_map_A007318 of Pascal-(1,5,1) array.?
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Geometric basis map (elementary) polytool ? step ›
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from
Pascal-(1,5,1) array.?
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Liu–Wang theorem with a lag row [LW07, Thm 2.1] RealRooted ? step › direct check
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Affine, reversal and Möbius substitutions (elementary) polytool ? step ›
- ↑ Affine, reversal and Möbius substitutions (elementary) (above)
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from
Pascal-(1,5,1) array.?
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from
basis_map_A007318 of Pascal-(1,5,1) array.?
Related ?
Candidate equalities ?
- A081580 → x ↦ x/(x+1) 15 rows; no all-index equality certificate was found
Same fingerprint ?
References
- [LW07] Lily L. Liu and Yi Wang. A unified approach to polynomial sequences with only real zeros. Advances in Applied Mathematics, 38(4):542–560, May 2007. doi:10.1016/j.aam.2006.02.003