A121574 → reverse

nonnegative coefficients

Proved for all n: all roots real, in (−∞, 0] · coefficients of one sign · Hadamard kernel what this means

Recurrence
\(\left(n\right)\,P_{n}(x) = \left(4\,x^{2} + n - n x - 4\,n x^{2} + 3\,n^{2} x\right)\,P_{n-1}(x) + \left(12\,x^{2} + 12\,x^{3} - n x - 8\,n x^{2} - 4\,n x^{3}\right)\,P_{n-1}'(x) + \left(x^{2} + 8\,x^{3} + 4\,x^{4}\right)\,P_{n-1}''(x)\)
\(P_{0}(x) = 1\)

Rows ?

nx0x1x2x3x4x5x6x7Pn(1)
011
1123
215410
31816833
4111374416109
51146713411232360
6117106305424272641189
7120154584116812326401283927

Generated b-files: A020704 (row sums), A121574 (reversed triangle) ?

Computed in your browser ?

Technical details
Node id
n-a0e88202514b92bb · revision 1 · JSON
Definition source
derived:reversal
Fingerprint
f6-c8ccd205be05e7c0

Observed on the stored rows ?

  • Degrees: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 (affine: slope 1, intercept 0)
  • Palindromic rows: no
  • γ-positive (gamma_positive): no
  • Nonnegative coefficients (nonn): yes
  • Only rational roots (rr_by_factors: every nonzero row is a product of linear factors over ℚ): no

OEIS matches ?

A generated b-file is computed from the node's definition along the row alignment of its OEIS link and starts at the entry's offset. It is an identification on a finite prefix, not a proof that the node and the OEIS entry agree for every n.

OEIS submission text ?

Fields to paste into an OEIS submission: the example %e, the formula %F and programs %t (Mathematica) and %o (PARI/GP) that list the same rows. For an OEIS link the row numbers, the offset and the orientation are those of the entry, as matched; the matched terms were compared with the published ones, which identifies the node with the entry on a finite prefix, not for every n. The PARI/GP program is not machine-checked here.

The atlas's own rows: n = 0, …, ascending powers of x
%e Example
Triangle begins:
  0: 1;
  1: 1,  2;
  2: 1,  5,   4;
  3: 1,  8,  16,    8;
  4: 1, 11,  37,   44,   16;
  5: 1, 14,  67,  134,  112,    32;
  6: 1, 17, 106,  305,  424,   272,    64;
  7: 1, 20, 154,  584, 1168,  1232,   640,  128;
  8: 1, 23, 211,  998, 2641,  3992,  3376, 1472,  256;
  9: 1, 26, 277, 1574, 5221, 10442, 12592, 8864, 3328, 512;
%F Formula
The row polynomials satisfy n*P(n,x) = (n+(3*n^2-n)*x-(4*n-4)*x^2)*P(n-1,x) - (n*x+(8*n-12)*x^2+(4*n-12)*x^3)*d/dx P(n-1,x) + (x^2+8*x^3+4*x^4)*d^2/dx^2 P(n-1,x) for n >= 1, with P(0,x) = 1.
%t Mathematica
P[0, x_] := 1;
P[n_, x_] := P[n, x] = Expand[Together[((n + (3*n^2 - n)*x - (4*n - 4)*x^2)*P[n - 1, x] - (n*x + (8*n - 12)*x^2 + (4*n - 12)*x^3)*D[P[n - 1, x], x] + (x^2 + 8*x^3 + 4*x^4)*D[P[n - 1, x], {x, 2}])/(n)]];
Table[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten
%o PARI/GP
P(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = ((n + (3*n^2 - n)*x - (4*n - 4)*x^2)*v[i - 1] - (n*x + (8*n - 12)*x^2 + (4*n - 12)*x^3)*deriv(v[i - 1], x) + (x^2 + 8*x^3 + 4*x^4)*deriv(deriv(v[i - 1], x), x))/(n)); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)

Generated with polytool c48629374597.

A121574: reversed triangle, offset 0, from the row P0
%e Example
Triangle begins:
  0:   1;
  1:   2,    1;
  2:   4,    5,    1;
  3:   8,   16,    8,     1;
  4:  16,   44,   37,    11,     1;
  5:  32,  112,  134,    67,    14,    1;
  6:  64,  272,  424,   305,   106,   17,    1;
  7: 128,  640, 1232,  1168,   584,  154,   20,   1;
  8: 256, 1472, 3376,  3992,  2641,  998,  211,  23,  1;
  9: 512, 3328, 8864, 12592, 10442, 5221, 1574, 277, 26, 1;
%F Formula
Row n lists the coefficients of P(n,x) in descending powers of x, where n*P(n,x) = (n+(3*n^2-n)*x-(4*n-4)*x^2)*P(n-1,x) - (n*x+(8*n-12)*x^2+(4*n-12)*x^3)*d/dx P(n-1,x) + (x^2+8*x^3+4*x^4)*d^2/dx^2 P(n-1,x) for n >= 1, with P(0,x) = 1.
%t Mathematica
P[0, x_] := 1;
P[n_, x_] := P[n, x] = Expand[Together[((n + (3*n^2 - n)*x - (4*n - 4)*x^2)*P[n - 1, x] - (n*x + (8*n - 12)*x^2 + (4*n - 12)*x^3)*D[P[n - 1, x], x] + (x^2 + 8*x^3 + 4*x^4)*D[P[n - 1, x], {x, 2}])/(n)]];
Table[Reverse[PadRight[CoefficientList[P[n, x], x], n + 1]], {n, 0, 9}] // Flatten
%o PARI/GP
P(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = ((n + (3*n^2 - n)*x - (4*n - 4)*x^2)*v[i - 1] - (n*x + (8*n - 12)*x^2 + (4*n - 12)*x^3)*deriv(v[i - 1], x) + (x^2 + 8*x^3 + 4*x^4)*deriv(deriv(v[i - 1], x), x))/(n)); v};
row(n, p) = {my(c = Vecrev(p)); c = concat(c, vector(n + 1 - #c)); c = Vecrev(c); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)

Generated with polytool c48629374597.

Proved properties

  • Real-rooted. Every row P_n, n >= 0, is zero or real-rooted with all roots in (-inf, 0]
    Every polynomial of the sequence has only real roots, inside the stated interval.
    by the cited steps: e-635d5bcbc56b7dbf
  • Coefficients of one sign. Every nonzero row, n >= 0: the coefficients of P_n have one sign
    All coefficients of each polynomial have the same sign (after x -> -x when alternating).
    derived from the cited steps by a stated theorem: e-635d5bcbc56b7dbf
  • Hadamard kernel (Malo). Rows P_n, n >= 0, are Hadamard kernels (preserve real-rootedness)
    Multiplying the coefficients of any real-rooted polynomial termwise by those of a row (Hadamard product) gives a real-rooted polynomial again.
    derived from the cited steps by a stated theorem: e-635d5bcbc56b7dbf

Proof chains

1 incoming proof step. Each step is expanded back to the roots of the proof DAG, the theorem checks of a node's own rule. JSON

Same fingerprint (1)

Equal up to content, sign, reversal and a small index shift.

References

  1. [LW07] Lily L. Liu and Yi Wang. A unified approach to polynomial sequences with only real zeros. Advances in Applied Mathematics, 38(4):542–560, May 2007. doi:10.1016/j.aam.2006.02.003