A359363 → reverse
palindromicγ-positivenonnegative coefficients
Proved for all n all roots real, in (−∞, 0]coefficients of one signHadamard kernel
Recurrence
\(\left(6 + 5\,n + n^{2}\right)\,P_{n}(x) = \left(6 + 5\,n - 10\,n x + n^{2} + 10\,n^{2} x\right)\,P_{n-1}(x) + \left(21\,x + 15\,x^{2} + 3\,n x - 15\,n x^{2}\right)\,P_{n-1}'(x) + \left(6\,x^{2} + 6\,x^{3}\right)\,P_{n-1}''(x)\)
\(P_{0}(x) = 1\)
Rows ?
| n | x0 | x1 | x2 | x3 | x4 | x5 | x6 | Pn(1) |
|---|---|---|---|---|---|---|---|---|
| 0 | 1 | 1 | ||||||
| 1 | 1 | 1 | ||||||
| 2 | 1 | 1 | 2 | |||||
| 3 | 1 | 4 | 1 | 6 | ||||
| 4 | 1 | 10 | 10 | 1 | 22 | |||
| 5 | 1 | 20 | 50 | 20 | 1 | 92 | ||
| 6 | 1 | 35 | 175 | 175 | 35 | 1 | 422 | |
| 7 | 1 | 56 | 490 | 980 | 490 | 56 | 1 | 2074 |
Compute more
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Technical details
- Node id
n-978bdc86d94d4dda· revision 0 · JSON- Definition source
derived:reversal- Fingerprint
f6-509399d8a74ba170
Observed on the stored rows ?
- Degrees: 0, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13 (irregular)
- Palindromic rows: yes
- γ-positive (gamma_positive): yes
- Nonnegative coefficients (
nonn): yes - Only rational roots (
rr_by_factors: every nonzero row is a product of linear factors over ℚ): no
Matches ?
No OEIS matches.
Submission text ?
Atlas rows n = 0, …, ascending powers of x
%e ExampleTriangle begins: 0: 1; 1: 1; 2: 1, 1; 3: 1, 4, 1; 4: 1, 10, 10, 1; 5: 1, 20, 50, 20, 1; 6: 1, 35, 175, 175, 35, 1; 7: 1, 56, 490, 980, 490, 56, 1; 8: 1, 84, 1176, 4116, 4116, 1176, 84, 1; 9: 1, 120, 2520, 14112, 24696, 14112, 2520, 120, 1;
%F FormulaThe row polynomials satisfy (n^2+5*n+6)*P(n,x) = (n^2+5*n+6+(10*n^2-10*n)*x)*P(n-1,x) + ((3*n+21)*x-(15*n-15)*x^2)*d/dx P(n-1,x) + (6*x^2+6*x^3)*d^2/dx^2 P(n-1,x) for n >= 1, with P(0,x) = 1.
%t MathematicaP[0, x_] := 1;
P[n_, x_] := P[n, x] = Expand[Together[((n^2 + 5*n + 6 + (10*n^2 - 10*n)*x)*P[n - 1, x] + ((3*n + 21)*x - (15*n - 15)*x^2)*D[P[n - 1, x], x] + (6*x^2 + 6*x^3)*D[P[n - 1, x], {x, 2}])/(n^2 + 5*n + 6)]];
Table[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten%o PARI/GPP(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = ((n^2 + 5*n + 6 + (10*n^2 - 10*n)*x)*v[i - 1] + ((3*n + 21)*x - (15*n - 15)*x^2)*deriv(v[i - 1], x) + (6*x^2 + 6*x^3)*deriv(deriv(v[i - 1], x), x))/(n^2 + 5*n + 6)); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)polytool c48629374597
Properties
- Real-rooted? Every row P_n, n ≥ 0, is zero or real-rooted with all roots in (−∞, 0]
- Coefficients of one sign? Every nonzero row, n ≥ 0: the coefficients of P_n have one sign
- Hadamard kernel (Malo)? Rows P_n, n ≥ 0, are Hadamard kernels (preserve real-rootedness)
Proof chains ? JSON
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Affine, reversal and Möbius substitutions (elementary) polytool ? step ›
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from
Triangle read by rows. The coefficients of the Baxter polynomials p(0, x) = 1 and p(n, x) = x*hypergeom([-1 - n, -n, 1 …?
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Row-hypergeometric rows (multiplier sequences) [SP14; Bra15, Thm 7.1 of arXiv:1410.6601] polytool RealRooted RealRooted.isPFMultiplierSequence_eval_of_roots_nonpos RealRooted RealRooted.isPFMultiplierSequence_inv_ascPochhammer RealRooted RealRooted.IsPFMultiplierSequence.mul ? step › direct check
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from
Triangle read by rows. The coefficients of the Baxter polynomials p(0, x) = 1 and p(n, x) = x*hypergeom([-1 - n, -n, 1 …?
Related ?
Same fingerprint ?
- A359363: Triangle read by rows. The coefficients of the Baxter polynomials p(0, x) = 1 and p(n, x) = x*hypergeom([-1 - …
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- Triangular array: T(n,k) = sqrt(C(n-1,k-1)*C(n-1,k)*C(n,k+1)* C(n+1,k+1)*C(n+1,k)*C(n,k-1)), where C(n,k) = binomial(n,…
References
- [Bra15] Petter Brändén. Unimodality, log-concavity, real-rootedness and beyond. Handbook of enumerative combinatorics, :437–483, March 2015. doi:10.1201/b18255-10
- [SP14] J Schur and G Polya. Über zwei Arten von Faktorenfolgen in der Theorie der algebraischen Gleichungen. J. Reine Angew. Math., 1914.