A111125 → basis A013611 → reverse
nonnegative coefficients
Proved for all n all roots real, in (−∞, 0]coefficients of one signHadamard kernel
Recurrence
\(\left(-12 + 8\,n\right)\,P_{n}(x) = \left(-48 - 56\,x - 10\,x^{2} + 32\,n + 36\,n x + 5\,n x^{2}\right)\,P_{n-1}(x) + \left(-16\,x - 24\,x^{2} - 5\,x^{3}\right)\,P_{n-1}'(x)\)
\(P_{1}(x) = 1\)
Rows ?
| n | x0 | x1 | x2 | x3 | x4 | x5 | x6 | x7 | Pn(1) |
|---|---|---|---|---|---|---|---|---|---|
| 1 | 1 | 1 | |||||||
| 2 | 4 | 4 | 8 | ||||||
| 3 | 16 | 28 | 11 | 55 | |||||
| 4 | 64 | 160 | 124 | 29 | 377 | ||||
| 5 | 256 | 832 | 960 | 460 | 76 | 2584 | |||
| 6 | 1024 | 4096 | 6272 | 4560 | 1560 | 199 | 17711 | ||
| 7 | 4096 | 19456 | 37120 | 36224 | 18960 | 5016 | 521 | 121393 | |
| 8 | 16384 | 90112 | 205824 | 252160 | 178240 | 72384 | 15572 | 1364 | 832040 |
Compute more
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Technical details
- Node id
n-95cc8af35ee1eba1· revision 0 · JSON- Definition source
derived:reversal- Fingerprint
f6-8805e6f0a07b591c
Observed on the stored rows ?
- Degrees: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 (affine: slope 1, intercept -1)
- Palindromic rows: no
- γ-positive (gamma_positive): no
- Nonnegative coefficients (
nonn): yes - Only rational roots (
rr_by_factors: every nonzero row is a product of linear factors over ℚ): no
Matches ?
No OEIS matches.
Submission text ?
Atlas rows n = 1, …, ascending powers of x
%e ExampleTriangle begins: 1: 1; 2: 4, 4; 3: 16, 28, 11; 4: 64, 160, 124, 29; 5: 256, 832, 960, 460, 76; 6: 1024, 4096, 6272, 4560, 1560, 199; 7: 4096, 19456, 37120, 36224, 18960, 5016, 521; 8: 16384, 90112, 205824, 252160, 178240, 72384, 15572, 1364; 9: 65536, 409600, 1089536, 1606656, 1432320, 788032, 260480, 47156, 3571; 10: 262144, 1835008, 5570560, 9605120, 10343424, 7196928, 3227776, 897680, 140180, 9349;
%F FormulaThe row polynomials satisfy (8*n-12)*P(n,x) = (32*n-48+(36*n-56)*x+(5*n-10)*x^2)*P(n-1,x) - (16*x+24*x^2+5*x^3)*d/dx P(n-1,x) for n >= 2, with P(1,x) = 1.
%t MathematicaP[1, x_] := 1;
P[n_, x_] := P[n, x] = Expand[Together[((32*n - 48 + (36*n - 56)*x + (5*n - 10)*x^2)*P[n - 1, x] - (16*x + 24*x^2 + 5*x^3)*D[P[n - 1, x], x])/(8*n - 12)]];
Table[CoefficientList[P[n, x], x], {n, 1, 10}] // Flatten%o PARI/GPP(N) = {my(v = vector(N)); v[1] = 1; for(n = 2, N, my(i = n); v[i] = ((32*n - 48 + (36*n - 56)*x + (5*n - 10)*x^2)*v[i - 1] - (16*x + 24*x^2 + 5*x^3)*deriv(v[i - 1], x))/(8*n - 12)); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i, v[i])))};
T(10)polytool c48629374597
Properties
- Real-rooted? Every row P_n, n ≥ 1, is zero or real-rooted with all roots in (−∞, 0]
- Coefficients of one sign? Every nonzero row, n ≥ 1: the coefficients of P_n have one sign
- Hadamard kernel (Malo)? Rows P_n, n ≥ 1, are Hadamard kernels (preserve real-rootedness)
Proof chains ? JSON
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Affine, reversal and Möbius substitutions (elementary) polytool ? step ›
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from
basis_map_A013611 of Triangle read by rows: T(k,s) = ((2*k+1)/(2*s+1))*binomial(k+s,2*s), 0 <= s <= k.?
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Geometric basis map (elementary) polytool ? step ›
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from
Triangle read by rows: T(k,s) = ((2*k+1)/(2*s+1))*binomial(k+s,2*s), 0 <= s <= k.?
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Affine, reversal and Möbius substitutions (elementary) polytool ? step ›
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from
Triangle read by rows: T(k,s) = ((2*k+1)/(2*s+1))*binomial(k+s,2*s), 0 <= s <= k.?
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from
basis_map_A013611 of Triangle read by rows: T(k,s) = ((2*k+1)/(2*s+1))*binomial(k+s,2*s), 0 <= s <= k.?
Related ?
Same fingerprint ?
References
- [Fav35] Jean Favard. Sur les polynômes de tchebicheff. C. R. Acad. Sci. Paris, 200:2052–2053, 1935.
- [LW07] Lily L. Liu and Yi Wang. A unified approach to polynomial sequences with only real zeros. Advances in Applied Mathematics, 38(4):542–560, May 2007. doi:10.1016/j.aam.2006.02.003
- [Sze39] G. Szegő. Orthogonal Polynomials. Colloquium publications, American Mathematical Society, 1939. doi:10.1090/coll/023