A062190 → reverse

nonnegative coefficients

Proved for all n: all roots real, in (−∞, 0] · coefficients of one sign · Hadamard kernel what this means

Recurrence
\(\left(5\,n + n^{2}\right)\,P_{n}(x) = \left(25 - 5\,x + 10\,n + 8\,n x + n^{2} + 3\,n^{2} x\right)\,P_{n-1}(x) + \left(5\,x - 5\,x^{2} + 2\,n x - 2\,n x^{2}\right)\,P_{n-1}'(x)\)
\(P_{0}(x) = 1\)

Rows ?

nx0x1x2x3x4x5x6x7Pn(1)
011
1617
22114136
35684241165
4126336216361715
5252105012004505013003
646227724950330082566112376
7792646816632173257700138684150388

Generated b-files: A003516 (row sums), A062190 (reversed triangle) ?

Computed in your browser ?

Technical details
Node id
n-817c504263a54deb · revision 1 · JSON
Definition source
derived:reversal
Fingerprint
f6-09fed58a54c64e77

Observed on the stored rows ?

  • Degrees: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 (affine: slope 1, intercept 0)
  • Palindromic rows: no
  • γ-positive (gamma_positive): no
  • Nonnegative coefficients (nonn): yes
  • Only rational roots (rr_by_factors: every nonzero row is a product of linear factors over ℚ): no

OEIS matches ?

A generated b-file is computed from the node's definition along the row alignment of its OEIS link and starts at the entry's offset. It is an identification on a finite prefix, not a proof that the node and the OEIS entry agree for every n.

OEIS submission text ?

Fields to paste into an OEIS submission: the example %e, the formula %F and programs %t (Mathematica) and %o (PARI/GP) that list the same rows. For an OEIS link the row numbers, the offset and the orientation are those of the entry, as matched; the matched terms were compared with the published ones, which identifies the node with the entry on a finite prefix, not for every n. The PARI/GP program is not machine-checked here.

The atlas's own rows: n = 0, …, ascending powers of x
%e Example
Triangle begins:
  0:    1;
  1:    6,     1;
  2:   21,    14,      1;
  3:   56,    84,     24,      1;
  4:  126,   336,    216,     36,      1;
  5:  252,  1050,   1200,    450,     50,      1;
  6:  462,  2772,   4950,   3300,    825,     66,     1;
  7:  792,  6468,  16632,  17325,   7700,   1386,    84,    1;
  8: 1287, 13728,  48048,  72072,  50050,  16016,  2184,  104,   1;
  9: 2002, 27027, 123552, 252252, 252252, 126126, 30576, 3276, 126, 1;
%F Formula
The row polynomials satisfy (n^2+5*n)*P(n,x) = (n^2+10*n+25+(3*n^2+8*n-5)*x)*P(n-1,x) + ((2*n+5)*x-(2*n+5)*x^2)*d/dx P(n-1,x) for n >= 1, with P(0,x) = 1.
%t Mathematica
P[0, x_] := 1;
P[n_, x_] := P[n, x] = Expand[Together[((n^2 + 10*n + 25 + (3*n^2 + 8*n - 5)*x)*P[n - 1, x] + ((2*n + 5)*x - (2*n + 5)*x^2)*D[P[n - 1, x], x])/(n^2 + 5*n)]];
Table[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten
%o PARI/GP
P(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = ((n^2 + 10*n + 25 + (3*n^2 + 8*n - 5)*x)*v[i - 1] + ((2*n + 5)*x - (2*n + 5)*x^2)*deriv(v[i - 1], x))/(n^2 + 5*n)); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)

Generated with polytool c48629374597.

A062190: reversed triangle, offset 0, from the row P0
%e Example
Triangle begins:
  0: 1;
  1: 1,   6;
  2: 1,  14,   21;
  3: 1,  24,   84,    56;
  4: 1,  36,  216,   336,    126;
  5: 1,  50,  450,  1200,   1050,    252;
  6: 1,  66,  825,  3300,   4950,   2772,    462;
  7: 1,  84, 1386,  7700,  17325,  16632,   6468,    792;
  8: 1, 104, 2184, 16016,  50050,  72072,  48048,  13728,  1287;
  9: 1, 126, 3276, 30576, 126126, 252252, 252252, 123552, 27027, 2002;
%F Formula
Row n lists the coefficients of P(n,x) in descending powers of x, where (n^2+5*n)*P(n,x) = (n^2+10*n+25+(3*n^2+8*n-5)*x)*P(n-1,x) + ((2*n+5)*x-(2*n+5)*x^2)*d/dx P(n-1,x) for n >= 1, with P(0,x) = 1.
%t Mathematica
P[0, x_] := 1;
P[n_, x_] := P[n, x] = Expand[Together[((n^2 + 10*n + 25 + (3*n^2 + 8*n - 5)*x)*P[n - 1, x] + ((2*n + 5)*x - (2*n + 5)*x^2)*D[P[n - 1, x], x])/(n^2 + 5*n)]];
Table[Reverse[PadRight[CoefficientList[P[n, x], x], n + 1]], {n, 0, 9}] // Flatten
%o PARI/GP
P(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = ((n^2 + 10*n + 25 + (3*n^2 + 8*n - 5)*x)*v[i - 1] + ((2*n + 5)*x - (2*n + 5)*x^2)*deriv(v[i - 1], x))/(n^2 + 5*n)); v};
row(n, p) = {my(c = Vecrev(p)); c = concat(c, vector(n + 1 - #c)); c = Vecrev(c); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)

Generated with polytool c48629374597.

Proved properties

  • Real-rooted. Every row P_n, n >= 0, is zero or real-rooted with all roots in (-inf, 0]
    Every polynomial of the sequence has only real roots, inside the stated interval.
    by the cited steps: e-888afb9e2aff2a08
  • Coefficients of one sign. Every nonzero row, n >= 0: the coefficients of P_n have one sign
    All coefficients of each polynomial have the same sign (after x -> -x when alternating).
    derived from the cited steps by a stated theorem: e-888afb9e2aff2a08
  • Hadamard kernel (Malo). Rows P_n, n >= 0, are Hadamard kernels (preserve real-rootedness)
    Multiplying the coefficients of any real-rooted polynomial termwise by those of a row (Hadamard product) gives a real-rooted polynomial again.
    derived from the cited steps by a stated theorem: e-888afb9e2aff2a08

Proof chains

1 incoming proof step. Each step is expanded back to the roots of the proof DAG, the theorem checks of a node's own rule. JSON

Same fingerprint (1)

Equal up to content, sign, reversal and a small index shift.

References

  1. [LW07] Lily L. Liu and Yi Wang. A unified approach to polynomial sequences with only real zeros. Advances in Applied Mathematics, 38(4):542–560, May 2007. doi:10.1016/j.aam.2006.02.003