A124324 → D
nonnegative coefficients
Proved for all n all roots real, in (−∞, 0]coefficients of one signHadamard kernel
Recurrence
\(\left(-2 + n\right)\,P_{n}(x) = \left(6\,x^{2} - 11\,n x^{2} + 6\,n^{2} x^{2} - n^{3} x^{2}\right)\,P_{n-4}(x) + \left(-4\,x + 6\,n x - 2\,n^{2} x\right)\,P_{n-3}(x) + \left(-2\,x^{2} + 3\,n x^{2} - n^{2} x^{2}\right)\,P_{n-3}'(x) + \left(2 + 4\,x - 2\,n - 6\,n x + 2\,n^{2} x\right)\,P_{n-2}(x) + \left(x - n x\right)\,P_{n-2}'(x) + \left(-5 + 3\,n\right)\,P_{n-1}(x) + \left(-2\,x + n x\right)\,P_{n-1}'(x)\)
\(P_{0}(x) = 0\)
\(P_{1}(x) = 0\)
\(P_{2}(x) = 1\)
\(P_{3}(x) = 4\)
Rows ?
| n | x0 | x1 | x2 | Pn(1) |
|---|---|---|---|---|
| 0 | 0 | |||
| 1 | 0 | |||
| 2 | 1 | 1 | ||
| 3 | 4 | 4 | ||
| 4 | 11 | 6 | 17 | |
| 5 | 26 | 50 | 76 | |
| 6 | 57 | 260 | 45 | 362 |
| 7 | 120 | 1092 | 630 | 1842 |
Compute more
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Technical details
- Node id
n-7368f216018f4712· revision 0 · JSON- Definition source
derived:derivative- Fingerprint
f6-a87fa6ef6c203402
Observed on the stored rows ?
- Degrees: -1, -1, 0, 0, 1, 1, 2, 2, 3, 3, 4, 4, 5, 5, 6 (half affine: slope 1, intercept -2)
- Palindromic rows: no
- γ-positive (gamma_positive): no
- Nonnegative coefficients (
nonn): yes - Only rational roots (
rr_by_factors: every nonzero row is a product of linear factors over ℚ): no
Matches ?
No OEIS matches.
Submission text ?
Atlas rows n = 0, …, ascending powers of x
%e ExampleTriangle begins: 0: 0; 1: 0; 2: 1; 3: 4; 4: 11, 6; 5: 26, 50; 6: 57, 260, 45; 7: 120, 1092, 630; 8: 247, 4074, 5250, 420; 9: 502, 14142, 34104, 8820;
%F FormulaThe row polynomials satisfy (n-2)*P(n,x) = -(n^3-6*n^2+11*n-6)*x^2*P(n-4,x) - (2*n^2-6*n+4)*x*P(n-3,x) - (n^2-3*n+2)*x^2*d/dx P(n-3,x) - (2*n-2-(2*n^2-6*n+4)*x)*P(n-2,x) - (n-1)*x*d/dx P(n-2,x) + (3*n-5)*P(n-1,x) + (n-2)*x*d/dx P(n-1,x) for n >= 4, with P(0,x) = 0, P(1,x) = 0, P(2,x) = 1, P(3,x) = 4.
%t MathematicaP[0, x_] := 0;
P[1, x_] := 0;
P[2, x_] := 1;
P[3, x_] := 4;
P[n_, x_] := P[n, x] = Expand[Together[(-(n^3 - 6*n^2 + 11*n - 6)*x^2*P[n - 4, x] - (2*n^2 - 6*n + 4)*x*P[n - 3, x] - (n^2 - 3*n + 2)*x^2*D[P[n - 3, x], x] - (2*n - 2 - (2*n^2 - 6*n + 4)*x)*P[n - 2, x] - (n - 1)*x*D[P[n - 2, x], x] + (3*n - 5)*P[n - 1, x] + (n - 2)*x*D[P[n - 1, x], x])/(n - 2)]];
Table[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten%o PARI/GPP(N) = {my(v = vector(N + 1)); v[1] = 0; v[2] = 0; v[3] = 1; v[4] = 4; for(n = 4, N, my(i = n + 1); v[i] = (-(n^3 - 6*n^2 + 11*n - 6)*x^2*v[i - 4] - (2*n^2 - 6*n + 4)*x*v[i - 3] - (n^2 - 3*n + 2)*x^2*deriv(v[i - 3], x) - (2*n - 2 - (2*n^2 - 6*n + 4)*x)*v[i - 2] - (n - 1)*x*deriv(v[i - 2], x) + (3*n - 5)*v[i - 1] + (n - 2)*x*deriv(v[i - 1], x))/(n - 2)); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)polytool c48629374597
Properties
- Real-rooted? Every row P_n, n ≥ 0, is zero or real-rooted with all roots in (−∞, 0]
-
Coefficients of one sign?
Every nonzero row, n ≥ 0: the coefficients of P_n have one sign
derived from Laguerre’s theorem on differential operators
-
Hadamard kernel (Malo)?
Rows P_n, n ≥ 0, are Hadamard kernels (preserve real-rootedness)
derived from Laguerre’s theorem on differential operators
Proof chains ? JSON
References
- [LW07] Lily L. Liu and Yi Wang. A unified approach to polynomial sequences with only real zeros. Advances in Applied Mathematics, 38(4):542–560, May 2007. doi:10.1016/j.aam.2006.02.003
- [SP14] J Schur and G Polya. Über zwei Arten von Faktorenfolgen in der Theorie der algebraischen Gleichungen. J. Reine Angew. Math., 1914.