A053117 → x ↦ x+1 → x ↦ x+1
nonnegative coefficients
Proved for all n all roots real, in (−3, −1)coefficients of one signHadamard kernelinterlacing (weak)
Recurrence
\(\left(-1 + n\right)\,P_{n}(x) = \left(2\,n + n x\right)\,P_{n-1}(x) + \left(3 + 4\,x + x^{2}\right)\,P_{n-1}'(x)\)
\(P_{1}(x) = 1\)
Rows ?
| n | x0 | x1 | x2 | x3 | x4 | x5 | x6 | x7 | Pn(1) |
|---|---|---|---|---|---|---|---|---|---|
| 1 | 1 | 1 | |||||||
| 2 | 4 | 2 | 6 | ||||||
| 3 | 15 | 16 | 4 | 35 | |||||
| 4 | 56 | 92 | 48 | 8 | 204 | ||||
| 5 | 209 | 464 | 372 | 128 | 16 | 1189 | |||
| 6 | 780 | 2182 | 2368 | 1248 | 320 | 32 | 6930 | ||
| 7 | 2911 | 9824 | 13464 | 9600 | 3760 | 768 | 64 | 40391 | |
| 8 | 10864 | 42936 | 71136 | 64080 | 33920 | 10560 | 1792 | 128 | 235416 |
Compute more
?
Other recurrences
Image under the basis map A013609 · proved equal for all n (proof step)
\(P_{n}(x) = \left(-1\right)\,P_{n-2}(x) + \left(4 + 2\,x\right)\,P_{n-1}(x)\)
\(P_{1}(x) = 1\)
\(P_{2}(x) = 4 + 2\,x\)
Technical details
- Node id
n-5c55f31aa1da8314· revision 0 · JSON- Definition source
derived:shift_x_plus_onederived:basis_map_A013609(equal bye-e29e2a5899c4b62d)- Fingerprint
f6-c761722d499074dd
Observed on the stored rows ?
- Degrees: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 (affine: slope 1, intercept -1)
- Palindromic rows: no
- γ-positive (gamma_positive): no
- Nonnegative coefficients (
nonn): yes - Only rational roots (
rr_by_factors: every nonzero row is a product of linear factors over ℚ): no
Matches ?
No OEIS matches.
Submission text ?
Atlas rows n = 1, …, ascending powers of x
%e ExampleTriangle begins: 1: 1; 2: 4, 2; 3: 15, 16, 4; 4: 56, 92, 48, 8; 5: 209, 464, 372, 128, 16; 6: 780, 2182, 2368, 1248, 320, 32; 7: 2911, 9824, 13464, 9600, 3760, 768, 64; 8: 10864, 42936, 71136, 64080, 33920, 10560, 1792, 128; 9: 40545, 183648, 356952, 388992, 260080, 109312, 28224, 4096, 256; 10: 151316, 772746, 1723968, 2205792, 1784384, 946848, 329728, 72704, 9216, 512;
%F FormulaThe row polynomials satisfy (n-1)*P(n,x) = (2*n+n*x)*P(n-1,x) + (3+4*x+x^2)*d/dx P(n-1,x) for n >= 2, with P(1,x) = 1.
%t MathematicaP[1, x_] := 1;
P[n_, x_] := P[n, x] = Expand[Together[((2*n + n*x)*P[n - 1, x] + (3 + 4*x + x^2)*D[P[n - 1, x], x])/(n - 1)]];
Table[CoefficientList[P[n, x], x], {n, 1, 10}] // Flatten%o PARI/GPP(N) = {my(v = vector(N)); v[1] = 1; for(n = 2, N, my(i = n); v[i] = ((2*n + n*x)*v[i - 1] + (3 + 4*x + x^2)*deriv(v[i - 1], x))/(n - 1)); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i, v[i])))};
T(10)polytool c48629374597
Properties
- Real-rooted? Every row P_n, n ≥ 1, is zero or real-rooted with all roots in (-3, -1)
- Coefficients of one sign? Every nonzero row, n ≥ 1: the coefficients of P_n have one sign
- Hadamard kernel (Malo)? Rows P_n, n ≥ 1, are Hadamard kernels (preserve real-rootedness)
- Interlacing of consecutive rows? Rows P_(m-1), P_m interlace (weak, unordered) for every m ≥ 2
- Real-rooted? Every row P_n, n ≥ 1, is zero or real-rooted with all roots in (−∞, 0]
Proof chains ? JSON
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Geometric basis map (elementary) polytool ? step ›
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from
basis_map_A007318 of Triangle read by rows: T(n, k) = binomial(n+k-1, 2*k-1).?
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Geometric basis map (elementary) polytool ? step ›
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from
basis_map_A007318 of Triangle read by rows: T(n, k) = binomial(n+k-1, 2*k-1).?
Related ?
Same fingerprint ?
References
- [Fav35] Jean Favard. Sur les polynômes de tchebicheff. C. R. Acad. Sci. Paris, 200:2052–2053, 1935.
- [LW07] Lily L. Liu and Yi Wang. A unified approach to polynomial sequences with only real zeros. Advances in Applied Mathematics, 38(4):542–560, May 2007. doi:10.1016/j.aam.2006.02.003
- [Sze39] G. Szegő. Orthogonal Polynomials. Colloquium publications, American Mathematical Society, 1939. doi:10.1090/coll/023