A345013: Triangle read by rows, related to clusters of type D.

A062196 → x ↦ x+1

A345013 nonnegative coefficients

Proved for all n: all roots real, in (−∞, −1] · coefficients of one sign · interlacing (weak) · Hadamard kernel what this means

Recurrence from OEIS A345013
\(\left(2\,n + n^{2}\right)\,P_{n}(x) = \left(2 + 2\,x + 6\,n + 4\,n x + 4\,n^{2} + 3\,n^{2} x\right)\,P_{n-1}(x) + \left(-2\,x - 2\,x^{2} - 2\,n x - 2\,n x^{2}\right)\,P_{n-1}'(x)\)
\(P_{0}(x) = 1\)

Rows ?

nx0x1x2x3x4x5x6x7Pn(1)
011
1437
21520641
3561056010231
4210504420140151289
5792231025201260280217183
630031029613860924031505042840081
71144045045720726006027720693084036224143

Generated b-files: A026002 (row sums), A345013 ?

Computed in your browser ?

Technical details
Node id
n-5aa52e3acf29a627 · revision 2 · JSON
Definition source
oeis_catalog:A345013
Fingerprint
f6-3961bf8dfc4504b6

Observed on the stored rows ?

  • Degrees: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 (affine: slope 1, intercept 0)
  • Palindromic rows: no
  • γ-positive (gamma_positive): no
  • Nonnegative coefficients (nonn): yes
  • Only rational roots (rr_by_factors: every nonzero row is a product of linear factors over ℚ): no

OEIS matches ?

A generated b-file is computed from the node's definition along the row alignment of its OEIS link and starts at the entry's offset. It is an identification on a finite prefix, not a proof that the node and the OEIS entry agree for every n.

OEIS submission text ?

Fields to paste into an OEIS submission: the example %e, the formula %F and programs %t (Mathematica) and %o (PARI/GP) that list the same rows. For an OEIS link the row numbers, the offset and the orientation are those of the entry, as matched; the matched terms were compared with the published ones, which identifies the node with the entry on a finite prefix, not for every n. The PARI/GP program is not machine-checked here.

The atlas's own rows: n = 0, …, ascending powers of x
%e Example
Triangle begins:
  0:      1;
  1:      4,      3;
  2:     15,     20,       6;
  3:     56,    105,      60,      10;
  4:    210,    504,     420,     140,      15;
  5:    792,   2310,    2520,    1260,     280,     21;
  6:   3003,  10296,   13860,    9240,    3150,    504,     28;
  7:  11440,  45045,   72072,   60060,   27720,   6930,    840,    36;
  8:  43758, 194480,  360360,  360360,  210210,  72072,  13860,  1320,   45;
  9: 167960, 831402, 1750320, 2042040, 1441440, 630630, 168168, 25740, 1980, 55;
%F Formula
The row polynomials satisfy (n^2+2*n)*P(n,x) = (4*n^2+6*n+2+(3*n^2+4*n+2)*x)*P(n-1,x) - ((2*n+2)*x+(2*n+2)*x^2)*d/dx P(n-1,x) for n >= 1, with P(0,x) = 1.
%t Mathematica
P[0, x_] := 1;
P[n_, x_] := P[n, x] = Expand[Together[((4*n^2 + 6*n + 2 + (3*n^2 + 4*n + 2)*x)*P[n - 1, x] - ((2*n + 2)*x + (2*n + 2)*x^2)*D[P[n - 1, x], x])/(n^2 + 2*n)]];
Table[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten
%o PARI/GP
P(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = ((4*n^2 + 6*n + 2 + (3*n^2 + 4*n + 2)*x)*v[i - 1] - ((2*n + 2)*x + (2*n + 2)*x^2)*deriv(v[i - 1], x))/(n^2 + 2*n)); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)

Generated with polytool c48629374597.

A345013: triangle, offset 1, from the row P0
%e Example
Triangle begins:
   1:      1;
   2:      4,      3;
   3:     15,     20,       6;
   4:     56,    105,      60,      10;
   5:    210,    504,     420,     140,      15;
   6:    792,   2310,    2520,    1260,     280,     21;
   7:   3003,  10296,   13860,    9240,    3150,    504,     28;
   8:  11440,  45045,   72072,   60060,   27720,   6930,    840,    36;
   9:  43758, 194480,  360360,  360360,  210210,  72072,  13860,  1320,   45;
  10: 167960, 831402, 1750320, 2042040, 1441440, 630630, 168168, 25740, 1980, 55;
%F Formula
The row polynomials satisfy (n^2-1)*P(n,x) = (4*n^2-2*n+(3*n^2-2*n+1)*x)*P(n-1,x) - (2*n*x+2*n*x^2)*d/dx P(n-1,x) for n >= 2, with P(1,x) = 1.
%t Mathematica
P[1, x_] := 1;
P[n_, x_] := P[n, x] = Expand[Together[((4*n^2 - 2*n + (3*n^2 - 2*n + 1)*x)*P[n - 1, x] - (2*n*x + 2*n*x^2)*D[P[n - 1, x], x])/(n^2 - 1)]];
Table[PadRight[CoefficientList[P[n, x], x], n], {n, 1, 10}] // Flatten
%o PARI/GP
P(N) = {my(v = vector(N)); v[1] = 1; for(n = 2, N, my(i = n); v[i] = ((4*n^2 - 2*n + (3*n^2 - 2*n + 1)*x)*v[i - 1] - (2*n*x + 2*n*x^2)*deriv(v[i - 1], x))/(n^2 - 1)); v};
row(n, p) = {my(c = Vecrev(p)); c = concat(c, vector(n - #c)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i, v[i])))};
T(10)

Generated with polytool c48629374597.

Proved properties

  • Real-rooted. Every row P_n, n >= 0, is zero or real-rooted with all roots in (-inf, -1]
    Every polynomial of the sequence has only real roots, inside the stated interval.
    by the cited steps: e-2ae8453bca041506, e-6f314a2e7485472a
  • Coefficients of one sign. Every nonzero row, n >= 0: the coefficients of P_n have one sign
    All coefficients of each polynomial have the same sign (after x -> -x when alternating).
    derived from the cited steps by a stated theorem: e-2ae8453bca041506, e-6f314a2e7485472a
  • Hadamard kernel (Malo). Rows P_n, n >= 0, are Hadamard kernels (preserve real-rootedness)
    Multiplying the coefficients of any real-rooted polynomial termwise by those of a row (Hadamard product) gives a real-rooted polynomial again.
    derived from the cited steps by a stated theorem: e-2ae8453bca041506, e-6f314a2e7485472a
  • Interlacing of consecutive rows. Rows P_(m-1), P_m interlace (weak, unordered) for every m >= 1
    The roots of consecutive polynomials alternate on the real line.
    by the cited steps: e-2ae8453bca041506, e-6f314a2e7485472a

Proof chains

2 incoming proof steps. Each step is expanded back to the roots of the proof DAG, the theorem checks of a node's own rule. JSON

No candidate equalities or related sequences.

References

  1. [LW07] Lily L. Liu and Yi Wang. A unified approach to polynomial sequences with only real zeros. Advances in Applied Mathematics, 38(4):542–560, May 2007. doi:10.1016/j.aam.2006.02.003