A119308 → reverse

nonnegative coefficients

Proved for all n all roots real, in (−∞, 0]coefficients of one signHadamard kernel

Recurrence

\(\left(3 + n\right)\,P_{n}(x) = \left(-2\,x + 4\,x^{2} - 2\,x^{3} + n x - 2\,n x^{2} + n x^{3}\right)\,P_{n-3}(x) + \left(x + x^{2} - n - 3\,n x^{2}\right)\,P_{n-2}(x) + \left(3 + 4\,x + 2\,n + 3\,n x\right)\,P_{n-1}(x)\)
\(P_{0}(x) = 1\)
\(P_{1}(x) = 1 + 2\,x\)
\(P_{2}(x) = 1 + 5\,x + 3\,x^{2}\)

Rows ?

nx0x1x2x3x4x5x6x7Pn(1)
011
1123
21539
31914428
41144030590
512090125556297
61271753853159171001
7135308980127468614083432
Technical details
Node id
n-4f9b456a67845b83 · revision 0 · JSON
Definition source
derived:reversal
Fingerprint
f6-1c718f648220d69b

Observed on the stored rows ?

  • Degrees: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 (affine: slope 1, intercept 0)
  • Palindromic rows: no
  • γ-positive (gamma_positive): no
  • Nonnegative coefficients (nonn): yes
  • Only rational roots (rr_by_factors: every nonzero row is a product of linear factors over ℚ): no

Matches ?

No OEIS matches.

Submission text ?

Atlas rows n = 0, …, ascending powers of x
%e Example
Triangle begins:
  0: 1;
  1: 1,  2;
  2: 1,  5,   3;
  3: 1,  9,  14,    4;
  4: 1, 14,  40,   30,     5;
  5: 1, 20,  90,  125,    55,     6;
  6: 1, 27, 175,  385,   315,    91,    7;
  7: 1, 35, 308,  980,  1274,   686,  140,    8;
  8: 1, 44, 504, 2184,  4116,  3528, 1344,  204,   9;
  9: 1, 54, 780, 4410, 11340, 14112, 8568, 2430, 285, 10;
%F Formula
The row polynomials satisfy (n+3)*P(n,x) = ((n-2)*x-(2*n-4)*x^2+(n-2)*x^3)*P(n-3,x) - (n-x+(3*n-1)*x^2)*P(n-2,x) + (2*n+3+(3*n+4)*x)*P(n-1,x) for n >= 3, with P(0,x) = 1, P(1,x) = 1 + 2*x, P(2,x) = 1 + 5*x + 3*x^2.
%t Mathematica
P[0, x_] := 1;
P[1, x_] := 1 + 2*x;
P[2, x_] := 1 + 5*x + 3*x^2;
P[n_, x_] := P[n, x] = Expand[Together[(((n - 2)*x - (2*n - 4)*x^2 + (n - 2)*x^3)*P[n - 3, x] - (n - x + (3*n - 1)*x^2)*P[n - 2, x] + (2*n + 3 + (3*n + 4)*x)*P[n - 1, x])/(n + 3)]];
Table[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten
%o PARI/GP
P(N) = {my(v = vector(N + 1)); v[1] = 1; v[2] = 1 + 2*x; v[3] = 1 + 5*x + 3*x^2; for(n = 3, N, my(i = n + 1); v[i] = (((n - 2)*x - (2*n - 4)*x^2 + (n - 2)*x^3)*v[i - 3] - (n - x + (3*n - 1)*x^2)*v[i - 2] + (2*n + 3 + (3*n + 4)*x)*v[i - 1])/(n + 3)); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)

polytool c48629374597

Properties

Proof chains ? JSON

Same fingerprint ?

References

  1. [Bra15] Petter Brändén. Unimodality, log-concavity, real-rootedness and beyond. Handbook of enumerative combinatorics, :437–483, March 2015. doi:10.1201/b18255-10
  2. [SP14] J Schur and G Polya. Über zwei Arten von Faktorenfolgen in der Theorie der algebraischen Gleichungen. J. Reine Angew. Math., 1914.