A272867 → x ↦ x+1 → reverse

nonnegative coefficients

Proved for all n all roots real, in (−∞, 0]coefficients of one signHadamard kernel

Recurrence

\(P_{n}(x) = \left(1 + 6\,x + 6\,x^{2}\right)\,P_{n-1}(x)\)
\(P_{0}(x) = 1\)

Rows ?

nx0x1x2x3x4x5x6x7x8x9x10x11x12x13x14Pn(1)
011
116613
2112487236169
31181264327566482162197
412424012964104777686405184129628561
5130390288013320401767992010368084240388807776371293
613657654003294013737640089682425611858401166400746496279936466564826809
71427989072687963674161422792405388885367521322697614859936117573126205248195955227993662748517
Technical details
Node id
n-471eb73214f7d8e8 · revision 0 · JSON
Definition source
derived:reversal
Fingerprint
f6-84fdcc1afa65c8bf

Observed on the stored rows ?

  • Degrees: 0, 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28 (affine: slope 2, intercept 0)
  • Palindromic rows: no
  • γ-positive (gamma_positive): no
  • Nonnegative coefficients (nonn): yes
  • Only rational roots (rr_by_factors: every nonzero row is a product of linear factors over ℚ): no

Matches ?

No OEIS matches.

Submission text ?

Atlas rows n = 0, …, ascending powers of x
%e Example
Triangle begins:
  0: 1;
  1: 1,  6,    6;
  2: 1, 12,   48,    72,     36;
  3: 1, 18,  126,   432,    756,     648,     216;
  4: 1, 24,  240,  1296,   4104,    7776,    8640,     5184,      1296;
  5: 1, 30,  390,  2880,  13320,   40176,   79920,   103680,     84240,     38880,      7776;
  6: 1, 36,  576,  5400,  32940,  137376,  400896,   824256,   1185840,   1166400,    746496,     279936,      46656;
  7: 1, 42,  798,  9072,  68796,  367416, 1422792,  4053888,   8536752,  13226976,  14859936,   11757312,    6205248,    1959552,     279936;
  8: 1, 48, 1056, 14112, 128016,  834624, 4040064, 14795136,  41396832,  88770816, 145442304,  180278784,  165908736,  109734912,   49268736,  13436928,   1679616;
  9: 1, 54, 1350, 20736, 219024, 1687392, 9815904, 44043264, 154408032, 425922624, 926448192, 1585557504, 2120235264, 2186860032, 1703130624, 967458816, 377913600, 90699264, 10077696;
%F Formula
The row polynomials satisfy P(n,x) = (1+6*x+6*x^2)*P(n-1,x) for n >= 1, with P(0,x) = 1.
%t Mathematica
P[0, x_] := 1;
P[n_, x_] := P[n, x] = Expand[(1 + 6*x + 6*x^2)*P[n - 1, x]];
Table[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten
%o PARI/GP
P(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = (1 + 6*x + 6*x^2)*v[i - 1]); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)

polytool c48629374597

Properties

Proof chains ? JSON

Candidate equalities ?

Same fingerprint ?

References

  1. [Bra06] Petter Brändén. On linear transformations preserving the Pólya frequency property. Transactions of the American Mathematical Society, 358(8):3697–3716, February 2006. doi:10.1090/s0002-9947-06-03856-6
  2. [Bra15] Petter Brändén. Unimodality, log-concavity, real-rootedness and beyond. Handbook of enumerative combinatorics, :437–483, March 2015. doi:10.1201/b18255-10
  3. [SP14] J Schur and G Polya. Über zwei Arten von Faktorenfolgen in der Theorie der algebraischen Gleichungen. J. Reine Angew. Math., 1914.