A360282 → reverse
nonnegative coefficients
Proved for all n all roots real, in (−∞, 0]coefficients of one signHadamard kernel
Recurrence
\(\left(-3\,n + 2\,n^{2}\right)\,P_{n}(x) = \left(-2 + 5\,n - 2\,n^{2}\right)\,P_{n-2}(x) + \left(4 + 6\,x - 8\,n - 16\,n x + 4\,n^{2} + 8\,n^{2} x\right)\,P_{n-1}(x)\)
\(P_{0}(x) = 1\)
\(P_{1}(x) = 1\)
Rows ?
| n | x0 | x1 | x2 | x3 | x4 | x5 | x6 | Pn(1) |
|---|---|---|---|---|---|---|---|---|
| 0 | 1 | 1 | ||||||
| 1 | 1 | 1 | ||||||
| 2 | 2 | 3 | 5 | |||||
| 3 | 3 | 12 | 10 | 25 | ||||
| 4 | 4 | 30 | 60 | 35 | 129 | |||
| 5 | 5 | 60 | 210 | 280 | 126 | 681 | ||
| 6 | 6 | 105 | 560 | 1260 | 1260 | 462 | 3653 | |
| 7 | 7 | 168 | 1260 | 4200 | 6930 | 5544 | 1716 | 19825 |
Compute more
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Technical details
- Node id
n-43c5f46a251ccde6· revision 0 · JSON- Definition source
derived:reversal- Fingerprint
f6-2c1fea4a558d4e6c
Observed on the stored rows ?
- Degrees: 0, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13 (irregular)
- Palindromic rows: no
- γ-positive (gamma_positive): no
- Nonnegative coefficients (
nonn): yes - Only rational roots (
rr_by_factors: every nonzero row is a product of linear factors over ℚ): no
Matches ?
No OEIS matches.
Submission text ?
Atlas rows n = 0, …, ascending powers of x
%e ExampleTriangle begins: 0: 1; 1: 1; 2: 2, 3; 3: 3, 12, 10; 4: 4, 30, 60, 35; 5: 5, 60, 210, 280, 126; 6: 6, 105, 560, 1260, 1260, 462; 7: 7, 168, 1260, 4200, 6930, 5544, 1716; 8: 8, 252, 2520, 11550, 27720, 36036, 24024, 6435; 9: 9, 360, 4620, 27720, 90090, 168168, 180180, 102960, 24310;
%F FormulaThe row polynomials satisfy (2*n^2-3*n)*P(n,x) = -(2*n^2-5*n+2)*P(n-2,x) + (4*n^2-8*n+4+(8*n^2-16*n+6)*x)*P(n-1,x) for n >= 2, with P(0,x) = 1, P(1,x) = 1.
%t MathematicaP[0, x_] := 1;
P[1, x_] := 1;
P[n_, x_] := P[n, x] = Expand[Together[(-(2*n^2 - 5*n + 2)*P[n - 2, x] + (4*n^2 - 8*n + 4 + (8*n^2 - 16*n + 6)*x)*P[n - 1, x])/(2*n^2 - 3*n)]];
Table[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten%o PARI/GPP(N) = {my(v = vector(N + 1)); v[1] = 1; v[2] = 1; for(n = 2, N, my(i = n + 1); v[i] = (-(2*n^2 - 5*n + 2)*v[i - 2] + (4*n^2 - 8*n + 4 + (8*n^2 - 16*n + 6)*x)*v[i - 1])/(2*n^2 - 3*n)); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)polytool c48629374597
Properties
- Real-rooted? Every row P_n, n ≥ 0, is zero or real-rooted with all roots in (−∞, 0]
- Coefficients of one sign? Every nonzero row, n ≥ 0: the coefficients of P_n have one sign
- Hadamard kernel (Malo)? Rows P_n, n ≥ 0, are Hadamard kernels (preserve real-rootedness)
Proof chains ? JSON
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Affine, reversal and Möbius substitutions (elementary) polytool ? step ›
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from
Triangle read by rows. T(n, k) = (1/2) * binomial(2*(n - k + 1), n - k + 1) * binomial(2*n - k, k - 1) for n > 0, T(0, …?
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Row-hypergeometric rows (multiplier sequences) [SP14; Bra15, Thm 7.1 of arXiv:1410.6601] polytool RealRooted RealRooted.isPFMultiplierSequence_eval_of_roots_nonpos RealRooted RealRooted.isPFMultiplierSequence_inv_ascPochhammer RealRooted RealRooted.IsPFMultiplierSequence.mul ? step › direct check
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from
Triangle read by rows. T(n, k) = (1/2) * binomial(2*(n - k + 1), n - k + 1) * binomial(2*n - k, k - 1) for n > 0, T(0, …?
Related ?
Same fingerprint ?
- A253283: Triangle read by rows: coefficients of the partial fraction decomposition of [d^n/dx^n] (x/(1-x))^n/n!.
- A360282: Triangle read by rows. T(n, k) = (1/2) * binomial(2*(n - k + 1), n - k + 1) * binomial(2*n - k, k - 1) for n >…
- A001263 → θ+1 → x ↦ x+1
- A123160 → D
- A253283 → reverse
- A367270 → x ↦ x+1
References
- [Bra15] Petter Brändén. Unimodality, log-concavity, real-rootedness and beyond. Handbook of enumerative combinatorics, :437–483, March 2015. doi:10.1201/b18255-10
- [LW07] Lily L. Liu and Yi Wang. A unified approach to polynomial sequences with only real zeros. Advances in Applied Mathematics, 38(4):542–560, May 2007. doi:10.1016/j.aam.2006.02.003
- [SP14] J Schur and G Polya. Über zwei Arten von Faktorenfolgen in der Theorie der algebraischen Gleichungen. J. Reine Angew. Math., 1914.