A111125 → basis A013610 → basis A013609
nonnegative coefficients
Proved for all n all roots real, in (−∞, 0]coefficients of one signHadamard kernelinterlacing (weak)
Recurrence
\(P_{n}(x) = \left(-1\right)\,P_{n-2}(x) + \left(6 + 6\,x\right)\,P_{n-1}(x)\)
\(P_{1}(x) = 1\)
\(P_{2}(x) = 7 + 6\,x\)
Rows ?
| n | x0 | x1 | x2 | x3 | x4 | x5 | x6 | x7 | Pn(1) |
|---|---|---|---|---|---|---|---|---|---|
| 1 | 1 | 1 | |||||||
| 2 | 7 | 6 | 13 | ||||||
| 3 | 41 | 78 | 36 | 155 | |||||
| 4 | 239 | 708 | 684 | 216 | 1847 | ||||
| 5 | 1393 | 5604 | 8316 | 5400 | 1296 | 22009 | |||
| 6 | 8119 | 41274 | 82836 | 82080 | 40176 | 7776 | 262261 | ||
| 7 | 47321 | 290754 | 736344 | 984096 | 732240 | 287712 | 46656 | 3125123 | |
| 8 | 275807 | 1987176 | 6079752 | 10240560 | 10257840 | 6111936 | 2006208 | 279936 | 37239215 |
Compute more
?
Technical details
- Node id
n-37b72160314f4b8f· revision 0 · JSON- Definition source
derived:basis_map_A013609- Fingerprint
f6-93cb1c672285184d
Observed on the stored rows ?
- Degrees: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 (affine: slope 1, intercept -1)
- Palindromic rows: no
- γ-positive (gamma_positive): no
- Nonnegative coefficients (
nonn): yes - Only rational roots (
rr_by_factors: every nonzero row is a product of linear factors over ℚ): no
Matches ?
No OEIS matches.
Submission text ?
Atlas rows n = 1, …, ascending powers of x
%e ExampleTriangle begins: 1: 1; 2: 7, 6; 3: 41, 78, 36; 4: 239, 708, 684, 216; 5: 1393, 5604, 8316, 5400, 1296; 6: 8119, 41274, 82836, 82080, 40176, 7776; 7: 47321, 290754, 736344, 984096, 732240, 287712, 46656; 8: 275807, 1987176, 6079752, 10240560, 10257840, 6111936, 2006208, 279936; 9: 1607521, 13287144, 47665224, 96937776, 122258160, 97930944, 48662208, 13716864, 1679616; 10: 9369319, 87380814, 359634456, 857377440, 1304917776, 1315022688, 877552704, 373994496, 92378880, 10077696;
%F FormulaThe row polynomials satisfy P(n,x) = -P(n-2,x) + (6+6*x)*P(n-1,x) for n >= 3, with P(1,x) = 1, P(2,x) = 7 + 6*x.
%t MathematicaP[1, x_] := 1;
P[2, x_] := 7 + 6*x;
P[n_, x_] := P[n, x] = Expand[-P[n - 2, x] + (6 + 6*x)*P[n - 1, x]];
Table[CoefficientList[P[n, x], x], {n, 1, 10}] // Flatten%o PARI/GPP(N) = {my(v = vector(N)); v[1] = 1; v[2] = 7 + 6*x; for(n = 3, N, my(i = n); v[i] = -v[i - 2] + (6 + 6*x)*v[i - 1]); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i, v[i])))};
T(10)polytool c48629374597
Properties
- Real-rooted? Every row P_n, n ≥ 1, is zero or real-rooted with all roots in (−∞, 0]
-
Coefficients of one sign?
Every nonzero row, n ≥ 1: the coefficients of P_n have one sign
derived from Geometric basis map (elementary)
-
Hadamard kernel (Malo)?
Rows P_n, n ≥ 1, are Hadamard kernels (preserve real-rootedness)
derived from Geometric basis map (elementary)
- Interlacing of consecutive rows? Rows P_(m-1), P_m interlace (weak, unordered) for every m ≥ 2
Proof chains ? JSON
-
Geometric basis map (elementary) polytool ? step ›
-
from
basis_map_A013610 of Triangle read by rows: T(k,s) = ((2*k+1)/(2*s+1))*binomial(k+s,2*s), 0 <= s <= k.?
-
Geometric basis map (elementary) polytool ? step ›
-
from
Triangle read by rows: T(k,s) = ((2*k+1)/(2*s+1))*binomial(k+s,2*s), 0 <= s <= k.?
-
Affine, reversal and Möbius substitutions (elementary) polytool ? step ›
-
from
Triangle read by rows: T(k,s) = ((2*k+1)/(2*s+1))*binomial(k+s,2*s), 0 <= s <= k.?
-
-
from
basis_map_A013610 of Triangle read by rows: T(k,s) = ((2*k+1)/(2*s+1))*binomial(k+s,2*s), 0 <= s <= k.?
References
- [Fav35] Jean Favard. Sur les polynômes de tchebicheff. C. R. Acad. Sci. Paris, 200:2052–2053, 1935.
- [LW07] Lily L. Liu and Yi Wang. A unified approach to polynomial sequences with only real zeros. Advances in Applied Mathematics, 38(4):542–560, May 2007. doi:10.1016/j.aam.2006.02.003
- [Sze39] G. Szegő. Orthogonal Polynomials. Colloquium publications, American Mathematical Society, 1939. doi:10.1090/coll/023