A169803 → basis A013610 → basis A007318

nonnegative coefficients

Proved for all n all roots real, in (−∞, −1]coefficients of one signHadamard kernelinterlacing (weak)

Recurrence

\(\left(3 + 3\,n\right)\,P_{n}(x) = \left(3 + 27\,n + 18\,n x\right)\,P_{n-1}(x) + \left(-68 - 99\,x - 36\,x^{2}\right)\,P_{n-1}'(x)\)
\(P_{0}(x) = 1\)

Rows ?

nx0x1x2x3x4x5x6x7Pn(1)
011
1538
29615
32933971
4658427176
518130316227673
64418345221081905
7116525892079702816616
8292972486669270040519951
97589210992275211745283524366263
1019305588787117242552125551458205920
11496611660412254771577885913010935729669761
121268814594686867995415122370065443251032111201
133255251272615208683018490959468902755624082421876799528
14833049349113062124306075540351945012043082245321749621577935

Other recurrences

Image under the basis map A007318 · proved equal for all n (proof step)

\(P_{n}(x) = \left(4 + 3\,x\right)\,P_{n-2}(x) + \left(1\right)\,P_{n-1}(x)\)
\(P_{0}(x) = 1\)
\(P_{1}(x) = 5 + 3\,x\)
Technical details
Node id
n-21cdf036c9ed34ac · revision 0 · JSON
Definition source
derived:shift_x_plus_one
derived:basis_map_A007318 (equal by e-82b3fcfa534d7ca0)
Fingerprint
f6-00069c0543dd4341

Observed on the stored rows ?

  • Degrees: 0, 1, 1, 2, 2, 3, 3, 4, 4, 5, 5, 6, 6, 7, 7 (half affine: slope 1, intercept 1)
  • Palindromic rows: no
  • γ-positive (gamma_positive): no
  • Nonnegative coefficients (nonn): yes
  • Only rational roots (rr_by_factors: every nonzero row is a product of linear factors over ℚ): no

Matches ?

No OEIS matches.

Submission text ?

Atlas rows n = 0, …, ascending powers of x
%e Example
Triangle begins:
  0:    1;
  1:    5,     3;
  2:    9,     6;
  3:   29,    33,     9;
  4:   65,    84,    27;
  5:  181,   303,   162,    27;
  6:  441,   834,   522,   108;
  7: 1165,  2589,  2079,   702,   81;
  8: 2929,  7248,  6669,  2700,  405;
  9: 7589, 21099, 22752, 11745, 2835, 243;
%F Formula
The row polynomials satisfy (3*n+3)*P(n,x) = (27*n+3+18*n*x)*P(n-1,x) - (68+99*x+36*x^2)*d/dx P(n-1,x) for n >= 1, with P(0,x) = 1.
%t Mathematica
P[0, x_] := 1;
P[n_, x_] := P[n, x] = Expand[Together[((27*n + 3 + 18*n*x)*P[n - 1, x] - (68 + 99*x + 36*x^2)*D[P[n - 1, x], x])/(3*n + 3)]];
Table[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten
%o PARI/GP
P(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = ((27*n + 3 + 18*n*x)*v[i - 1] - (68 + 99*x + 36*x^2)*deriv(v[i - 1], x))/(3*n + 3)); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)

polytool c48629374597

Properties

Proof chains ? JSON

Same fingerprint ?

References

  1. [LW07] Lily L. Liu and Yi Wang. A unified approach to polynomial sequences with only real zeros. Advances in Applied Mathematics, 38(4):542–560, May 2007. doi:10.1016/j.aam.2006.02.003
  2. [MW08] Shi-Mei Ma and Yi Wang. q-Eulerian polynomials and polynomials with only real zeros. The Electronic Journal of Combinatorics, 15(1):Research Paper 17, January 2008. doi:10.37236/741