A081577 → basis A013611 → basis A007318
nonnegative coefficients
Proved for all n all roots real, in (−∞, 0]coefficients of one signHadamard kernelinterlacing (weak)
Recurrence
\(P_{n}(x) = \left(10 + 8\,x\right)\,P_{n-2}(x) + \left(6 + 4\,x\right)\,P_{n-1}(x)\)
\(P_{0}(x) = 1\)
\(P_{1}(x) = 6 + 4\,x\)
Rows ?
| n | x0 | x1 | x2 | x3 | x4 | x5 | x6 | x7 | Pn(1) |
|---|---|---|---|---|---|---|---|---|---|
| 0 | 1 | 1 | |||||||
| 1 | 6 | 4 | 10 | ||||||
| 2 | 46 | 56 | 16 | 118 | |||||
| 3 | 336 | 608 | 352 | 64 | 1360 | ||||
| 4 | 2476 | 5920 | 5152 | 1920 | 256 | 15724 | |||
| 5 | 18216 | 54192 | 62976 | 35584 | 9728 | 1024 | 181720 | ||
| 6 | 134056 | 477024 | 693504 | 525824 | 218624 | 47104 | 4096 | 2100232 | |
| 7 | 986496 | 4086016 | 7132416 | 6788608 | 3796992 | 1245184 | 221184 | 16384 | 24273280 |
Compute more
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Technical details
- Node id
n-1fa3228c923a928a· revision 0 · JSON- Definition source
derived:basis_map_A007318- Fingerprint
f6-346585d9f129010f
Observed on the stored rows ?
- Degrees: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 (affine: slope 1, intercept 0)
- Palindromic rows: no
- γ-positive (gamma_positive): no
- Nonnegative coefficients (
nonn): yes - Only rational roots (
rr_by_factors: every nonzero row is a product of linear factors over ℚ): no
Matches ?
No OEIS matches.
Submission text ?
Atlas rows n = 0, …, ascending powers of x
%e ExampleTriangle begins: 0: 1; 1: 6, 4; 2: 46, 56, 16; 3: 336, 608, 352, 64; 4: 2476, 5920, 5152, 1920, 256; 5: 18216, 54192, 62976, 35584, 9728, 1024; 6: 134056, 477024, 693504, 525824, 218624, 47104, 4096; 7: 986496, 4086016, 7132416, 6788608, 3796992, 1245184, 221184, 16384; 8: 7259536, 34304768, 69889792, 80067584, 56329216, 24879104, 6725632, 1015808, 65536; 9: 53422176, 283618880, 660570112, 884910080, 750524416, 417419264, 152043520, 34930688, 4587520, 262144;
%F FormulaThe row polynomials satisfy P(n,x) = (10+8*x)*P(n-2,x) + (6+4*x)*P(n-1,x) for n >= 2, with P(0,x) = 1, P(1,x) = 6 + 4*x.
%t MathematicaP[0, x_] := 1;
P[1, x_] := 6 + 4*x;
P[n_, x_] := P[n, x] = Expand[(10 + 8*x)*P[n - 2, x] + (6 + 4*x)*P[n - 1, x]];
Table[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten%o PARI/GPP(N) = {my(v = vector(N + 1)); v[1] = 1; v[2] = 6 + 4*x; for(n = 2, N, my(i = n + 1); v[i] = (10 + 8*x)*v[i - 2] + (6 + 4*x)*v[i - 1]); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};
T(9)polytool c48629374597
Properties
- Real-rooted? Every row P_n, n ≥ 0, is zero or real-rooted with all roots in (−∞, 0]
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Coefficients of one sign?
Every nonzero row, n ≥ 0: the coefficients of P_n have one sign
derived from Geometric basis map (elementary)
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Hadamard kernel (Malo)?
Rows P_n, n ≥ 0, are Hadamard kernels (preserve real-rootedness)
derived from Geometric basis map (elementary)
- Interlacing of consecutive rows? Rows P_(m-1), P_m interlace (weak, unordered) for every m ≥ 1
Proof chains ? JSON
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Geometric basis map (elementary) polytool ? step ›
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from
basis_map_A013611 of Pascal-(1,2,1) array read by antidiagonals.?
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Geometric basis map (elementary) polytool ? step ›
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from
Pascal-(1,2,1) array read by antidiagonals.?
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Liu–Wang theorem with a lag row [LW07, Thm 2.1] RealRooted ? step › direct check
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Affine, reversal and Möbius substitutions (elementary) polytool ? step ›
- ↑ Affine, reversal and Möbius substitutions (elementary) (above)
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from
Pascal-(1,2,1) array read by antidiagonals.?
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from
basis_map_A013611 of Pascal-(1,2,1) array read by antidiagonals.?
Related ?
Candidate equalities ?
- A081577 → basis A013611 → x ↦ x+1 15 rows; no all-index equality certificate was found
References
- [LW07] Lily L. Liu and Yi Wang. A unified approach to polynomial sequences with only real zeros. Advances in Applied Mathematics, 38(4):542–560, May 2007. doi:10.1016/j.aam.2006.02.003