A008278 → x ↦ x/(x+1)

nonnegative coefficients

Proved for all n: all roots real, in [−1, 0] · coefficients of one sign · Hadamard kernel what this means

Recurrence
\(\left(1 + 2\,x + x^{2}\right)\,P_{n}(x) = \left(1 + 2\,x - x^{2} - 4\,x^{3} - 2\,x^{4} + n x + 3\,n x^{2} + 3\,n x^{3} + n x^{4}\right)\,P_{n-1}(x) + \left(-x^{2} - 3\,x^{3} - 3\,x^{4} - x^{5}\right)\,P_{n-1}'(x)\)
\(P_{1}(x) = 1\)

Rows ?

nx0x1x2x3x4x5x6x7x8x9x10x11x12x13x14Pn(1)
111
2123
315511
419221547
5114619952227
61201353854712031215
71272601140241623868777107
8135455283591561547012867414044959
9144742623028441725901022157368121147305091
10154114612474765032743865789297003114466201159752206399
11165169523220184317884751260776046925004984651285645767857016913987
1217724204075540685725218279906919247628153887819136872561192172434213597136823263
13190335568145836187650958032929534109242210236989676330314776283342060135610448276444371163490499
1411044537109395161933215484755982052504182455421199262350229846388228828746442259923016100115990119089932210366252031
151119600616962429819793439135726762678814259708325232663436132027735842266996968625868151764186894758977714225057138295854596491364675

Generated b-files: A126350, A137597 (reversed triangle) ?

Computed in your browser ?

Technical details
Node id
n-185306a9f278f7c5 · revision 1 · JSON
Definition source
derived:mobius_x_over_x_plus_one
Fingerprint
f6-1090d35600282d8c

Observed on the stored rows ?

  • Degrees: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 (affine: slope 1, intercept -1)
  • Palindromic rows: no
  • γ-positive (gamma_positive): no
  • Nonnegative coefficients (nonn): yes
  • Only rational roots (rr_by_factors: every nonzero row is a product of linear factors over ℚ): no

OEIS matches ?

A generated b-file is computed from the node's definition along the row alignment of its OEIS link and starts at the entry's offset. It is an identification on a finite prefix, not a proof that the node and the OEIS entry agree for every n.

OEIS submission text ?

Fields to paste into an OEIS submission: the example %e, the formula %F and programs %t (Mathematica) and %o (PARI/GP) that list the same rows. For an OEIS link the row numbers, the offset and the orientation are those of the entry, as matched; the matched terms were compared with the published ones, which identifies the node with the entry on a finite prefix, not for every n. The PARI/GP program is not machine-checked here.

The atlas's own rows: n = 1, …, ascending powers of x
%e Example
Triangle begins:
   1: 1;
   2: 1,  2;
   3: 1,  5,    5;
   4: 1,  9,   22,    15;
   5: 1, 14,   61,    99,    52;
   6: 1, 20,  135,   385,   471,    203;
   7: 1, 27,  260,  1140,  2416,   2386,    877;
   8: 1, 35,  455,  2835,  9156,  15470,  12867,   4140;
   9: 1, 44,  742,  6230, 28441,  72590, 102215,  73681,  21147;
  10: 1, 54, 1146, 12474, 76503, 274386, 578929, 700311, 446620, 115975;
%F Formula
The row polynomials satisfy (1+2*x+x^2)*P(n,x) = (1+(n+2)*x+(3*n-1)*x^2+(3*n-4)*x^3+(n-2)*x^4)*P(n-1,x) - (x^2+3*x^3+3*x^4+x^5)*d/dx P(n-1,x) for n >= 2, with P(1,x) = 1.
%t Mathematica
P[1, x_] := 1;
P[n_, x_] := P[n, x] = Expand[Together[((1 + (n + 2)*x + (3*n - 1)*x^2 + (3*n - 4)*x^3 + (n - 2)*x^4)*P[n - 1, x] - (x^2 + 3*x^3 + 3*x^4 + x^5)*D[P[n - 1, x], x])/(1 + 2*x + x^2)]];
Table[CoefficientList[P[n, x], x], {n, 1, 10}] // Flatten
%o PARI/GP
P(N) = {my(v = vector(N)); v[1] = 1; for(n = 2, N, my(i = n); v[i] = ((1 + (n + 2)*x + (3*n - 1)*x^2 + (3*n - 4)*x^3 + (n - 2)*x^4)*v[i - 1] - (x^2 + 3*x^3 + 3*x^4 + x^5)*deriv(v[i - 1], x))/(1 + 2*x + x^2)); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i, v[i])))};
T(10)

Generated with polytool c48629374597.

A126350: triangle, offset 1, from the row P1
%e Example
Triangle begins:
   1: 1;
   2: 1,  2;
   3: 1,  5,    5;
   4: 1,  9,   22,    15;
   5: 1, 14,   61,    99,    52;
   6: 1, 20,  135,   385,   471,    203;
   7: 1, 27,  260,  1140,  2416,   2386,    877;
   8: 1, 35,  455,  2835,  9156,  15470,  12867,   4140;
   9: 1, 44,  742,  6230, 28441,  72590, 102215,  73681,  21147;
  10: 1, 54, 1146, 12474, 76503, 274386, 578929, 700311, 446620, 115975;
%F Formula
The row polynomials satisfy (1+2*x+x^2)*P(n,x) = (1+(n+2)*x+(3*n-1)*x^2+(3*n-4)*x^3+(n-2)*x^4)*P(n-1,x) - (x^2+3*x^3+3*x^4+x^5)*d/dx P(n-1,x) for n >= 2, with P(1,x) = 1.
%t Mathematica
P[1, x_] := 1;
P[n_, x_] := P[n, x] = Expand[Together[((1 + (n + 2)*x + (3*n - 1)*x^2 + (3*n - 4)*x^3 + (n - 2)*x^4)*P[n - 1, x] - (x^2 + 3*x^3 + 3*x^4 + x^5)*D[P[n - 1, x], x])/(1 + 2*x + x^2)]];
Table[PadRight[CoefficientList[P[n, x], x], n], {n, 1, 10}] // Flatten
%o PARI/GP
P(N) = {my(v = vector(N)); v[1] = 1; for(n = 2, N, my(i = n); v[i] = ((1 + (n + 2)*x + (3*n - 1)*x^2 + (3*n - 4)*x^3 + (n - 2)*x^4)*v[i - 1] - (x^2 + 3*x^3 + 3*x^4 + x^5)*deriv(v[i - 1], x))/(1 + 2*x + x^2)); v};
row(n, p) = {my(c = Vecrev(p)); c = concat(c, vector(n - #c)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i, v[i])))};
T(10)

Generated with polytool c48629374597.

A137597: reversed triangle, offset 1, from the row P1
%e Example
Triangle begins:
   1:      1;
   2:      2,      1;
   3:      5,      5,      1;
   4:     15,     22,      9,      1;
   5:     52,     99,     61,     14,      1;
   6:    203,    471,    385,    135,     20,     1;
   7:    877,   2386,   2416,   1140,    260,    27,     1;
   8:   4140,  12867,  15470,   9156,   2835,   455,    35,    1;
   9:  21147,  73681, 102215,  72590,  28441,  6230,   742,   44,  1;
  10: 115975, 446620, 700311, 578929, 274386, 76503, 12474, 1146, 54, 1;
%F Formula
Row n lists the coefficients of P(n,x) in descending powers of x, where (1+2*x+x^2)*P(n,x) = (1+(n+2)*x+(3*n-1)*x^2+(3*n-4)*x^3+(n-2)*x^4)*P(n-1,x) - (x^2+3*x^3+3*x^4+x^5)*d/dx P(n-1,x) for n >= 2, with P(1,x) = 1.
%t Mathematica
P[1, x_] := 1;
P[n_, x_] := P[n, x] = Expand[Together[((1 + (n + 2)*x + (3*n - 1)*x^2 + (3*n - 4)*x^3 + (n - 2)*x^4)*P[n - 1, x] - (x^2 + 3*x^3 + 3*x^4 + x^5)*D[P[n - 1, x], x])/(1 + 2*x + x^2)]];
Table[Reverse[PadRight[CoefficientList[P[n, x], x], n]], {n, 1, 10}] // Flatten
%o PARI/GP
P(N) = {my(v = vector(N)); v[1] = 1; for(n = 2, N, my(i = n); v[i] = ((1 + (n + 2)*x + (3*n - 1)*x^2 + (3*n - 4)*x^3 + (n - 2)*x^4)*v[i - 1] - (x^2 + 3*x^3 + 3*x^4 + x^5)*deriv(v[i - 1], x))/(1 + 2*x + x^2)); v};
row(n, p) = {my(c = Vecrev(p)); c = concat(c, vector(n - #c)); c = Vecrev(c); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i, v[i])))};
T(10)

Generated with polytool c48629374597.

Proved properties

  • Real-rooted. Every row P_n, n >= 1, is zero or real-rooted with all roots in [-1, 0]
    Every polynomial of the sequence has only real roots, inside the stated interval.
    by the cited steps: e-e3742f5d3c2b56cd
  • Coefficients of one sign. Every nonzero row, n >= 1: the coefficients of P_n have one sign
    All coefficients of each polynomial have the same sign (after x -> -x when alternating).
    derived from the cited steps by a stated theorem: e-e3742f5d3c2b56cd
  • Hadamard kernel (Malo). Rows P_n, n >= 1, are Hadamard kernels (preserve real-rootedness)
    Multiplying the coefficients of any real-rooted polynomial termwise by those of a row (Hadamard product) gives a real-rooted polynomial again.
    derived from the cited steps by a stated theorem: e-e3742f5d3c2b56cd

Proof chains

1 incoming proof step. Each step is expanded back to the roots of the proof DAG, the theorem checks of a node's own rule. JSON

Same fingerprint (3)

Equal up to content, sign, reversal and a small index shift.

References

  1. [LW07] Lily L. Liu and Yi Wang. A unified approach to polynomial sequences with only real zeros. Advances in Applied Mathematics, 38(4):542–560, May 2007. doi:10.1016/j.aam.2006.02.003
  2. [MW08] Shi-Mei Ma and Yi Wang. q-Eulerian polynomials and polynomials with only real zeros. The Electronic Journal of Combinatorics, 15(1):Research Paper 17, January 2008. doi:10.37236/741