A086645 → basis A013609 → reverse
nonnegative coefficients
Proved for all n all roots real, in (−∞, 0]coefficients of one signHadamard kernel
Recurrence
\(\left(-2 + n\right)\,P_{n}(x) = \left(-4 - 4\,x + 2\,n + 2\,n x\right)\,P_{n-1}(x) + \left(4\,x + 2\,x^{2}\right)\,P_{n-1}'(x)\)
\(P_{1}(x) = 1\)
\(P_{2}(x) = 2 + 2\,x\)
Rows ?
| n | x0 | x1 | x2 | x3 | x4 | x5 | x6 | x7 | Pn(1) |
|---|---|---|---|---|---|---|---|---|---|
| 1 | 1 | 1 | |||||||
| 2 | 2 | 2 | 4 | ||||||
| 3 | 4 | 16 | 8 | 28 | |||||
| 4 | 8 | 72 | 96 | 32 | 208 | ||||
| 5 | 16 | 256 | 640 | 512 | 128 | 1552 | |||
| 6 | 32 | 800 | 3200 | 4480 | 2560 | 512 | 11584 | ||
| 7 | 64 | 2304 | 13440 | 28672 | 27648 | 12288 | 2048 | 86464 | |
| 8 | 128 | 6272 | 50176 | 150528 | 215040 | 157696 | 57344 | 8192 | 645376 |
Compute more
?
Technical details
- Node id
n-180b0ec0ce696564· revision 0 · JSON- Definition source
derived:reversal- Fingerprint
f6-d44a70ca53ce7ac3
Observed on the stored rows ?
- Degrees: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 (affine: slope 1, intercept -1)
- Palindromic rows: no
- γ-positive (gamma_positive): no
- Nonnegative coefficients (
nonn): yes - Only rational roots (
rr_by_factors: every nonzero row is a product of linear factors over ℚ): no
Matches ?
No OEIS matches.
Submission text ?
Atlas rows n = 1, …, ascending powers of x
%e ExampleTriangle begins: 1: 1; 2: 2, 2; 3: 4, 16, 8; 4: 8, 72, 96, 32; 5: 16, 256, 640, 512, 128; 6: 32, 800, 3200, 4480, 2560, 512; 7: 64, 2304, 13440, 28672, 27648, 12288, 2048; 8: 128, 6272, 50176, 150528, 215040, 157696, 57344, 8192; 9: 256, 16384, 172032, 688128, 1351680, 1441792, 851968, 262144, 32768; 10: 512, 41472, 552960, 2838528, 7299072, 10543104, 8945664, 4423680, 1179648, 131072;
%F FormulaThe row polynomials satisfy (n-2)*P(n,x) = (2*n-4+(2*n-4)*x)*P(n-1,x) + (4*x+2*x^2)*d/dx P(n-1,x) for n >= 3, with P(1,x) = 1, P(2,x) = 2 + 2*x.
%t MathematicaP[1, x_] := 1;
P[2, x_] := 2 + 2*x;
P[n_, x_] := P[n, x] = Expand[Together[((2*n - 4 + (2*n - 4)*x)*P[n - 1, x] + (4*x + 2*x^2)*D[P[n - 1, x], x])/(n - 2)]];
Table[CoefficientList[P[n, x], x], {n, 1, 10}] // Flatten%o PARI/GPP(N) = {my(v = vector(N)); v[1] = 1; v[2] = 2 + 2*x; for(n = 3, N, my(i = n); v[i] = ((2*n - 4 + (2*n - 4)*x)*v[i - 1] + (4*x + 2*x^2)*deriv(v[i - 1], x))/(n - 2)); v};
row(n, p) = {my(c = Vecrev(p)); c};
T(N) = {my(v = P(N)); concat(vector(#v, i, row(i, v[i])))};
T(10)polytool c48629374597
Properties
- Real-rooted? Every row P_n, n ≥ 1, is zero or real-rooted with all roots in (−∞, 0]
- Coefficients of one sign? Every nonzero row, n ≥ 1: the coefficients of P_n have one sign
- Hadamard kernel (Malo)? Rows P_n, n ≥ 1, are Hadamard kernels (preserve real-rootedness)
Proof chains ? JSON
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Affine, reversal and Möbius substitutions (elementary) polytool ? step ›
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from
basis_map_A013609 of Triangle read by rows: T(n, k) = binomial(2n, 2k).?
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Geometric basis map (elementary) polytool ? step ›
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from
Triangle read by rows: T(n, k) = binomial(2n, 2k).?
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Affine, reversal and Möbius substitutions (elementary) polytool ? step ›
- ↑ Affine, reversal and Möbius substitutions (elementary) (above)
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from
Triangle read by rows: T(n, k) = binomial(2n, 2k).?
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from
basis_map_A013609 of Triangle read by rows: T(n, k) = binomial(2n, 2k).?
Related ?
Same fingerprint ?
- Hadamard-factor parent of A155495 → basis A013609
- A086645 → basis A013609
- chebyshev_t → x ↦ x+1 → reverse
- A034870 → Veronese 2 → basis A013609
- chebyshev_t → x ↦ x+1
References
- [Fav35] Jean Favard. Sur les polynômes de tchebicheff. C. R. Acad. Sci. Paris, 200:2052–2053, 1935.
- [LW07] Lily L. Liu and Yi Wang. A unified approach to polynomial sequences with only real zeros. Advances in Applied Mathematics, 38(4):542–560, May 2007. doi:10.1016/j.aam.2006.02.003
- [Sze39] G. Szegő. Orthogonal Polynomials. Colloquium publications, American Mathematical Society, 1939. doi:10.1090/coll/023