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809238528,     66060288,     2359296;\n  8:   826441871360,  2125136240640,  2428727132160,  1619151421440,   693922037760,  198263439360,   37764464640,   4624220160,   330301440,   10485760;\n  9: 12727204818944, 36363442339840, 46752997294080, 35621331271680, 17810665635840, 6106513932288, 1453931888640, 237376634880, 25433210880, 1614807040, 46137344;\n","recurrence_sentence":"The row polynomials satisfy (n+1)*P(n,x) = (14*n+28+(4*n+8)*x)*P(n-1,x) for n >= 1, with P(0,x) = 112 + 32*x.","mathematica":"P[0, x_] := 112 + 32*x;\nP[n_, x_] := P[n, x] = Expand[Together[((14*n + 28 + (4*n + 8)*x)*P[n - 1, x])/(n + 1)]];\nTable[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); v[1] = 112 + 32*x; for(n = 1, N, my(i = n + 1); v[i] = ((14*n + 28 + (4*n + 8)*x)*v[i - 1])/(n + 1)); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false}}],"derivation":{"root":"n-ea9b82d727693fb6","steps":["basis A013609","D"],"edges":["e-ccf7b0982517b62a","e-9ffb1eb7f95ae355"],"text":"A038328 \u2192 basis A013609 \u2192 D"},"headline":"A038328 \u2192 basis A013609 \u2192 D","chain":null}