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row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":true}},{"oeis_id":"A257618","target":"reversed_triangle","first_row":0,"oeis_offset":0,"reversed":true,"trim_zeros":"none","regular_triangle":true,"rows_shown":10,"polytool_commit":"c48629374597092cc41ef4d6273f37991516f984","triangle_example":"Triangle begins:\n  0:   1;\n  1:   2,         2;\n  2:   4,        40,           4;\n  3:   8,       472,         472,             8;\n  4:  16,      4928,       16992,          4928,            16;\n  5:  32,     49824,      433984,        433984,         49824,            32;\n  6:  64,    499584,     9505728,      22567168,       9505728,        499584,            64;\n  7: 128,   4999040,   192085632,     909941120,     909941120,     192085632,       4999040,         128;\n  8: 256,  49997824,  3707493376,   31726065664,   61875996160,   31726065664,    3707493376,    49997824,       256;\n  9: 512, 499995136, 69634754560, 1010252376064, 3436278627328, 3436278627328, 1010252376064, 69634754560, 499995136, 512;\n","recurrence_sentence":"Row n lists the coefficients of P(n,x) in descending powers of x, where P(n,x) = (2+(8*n-6)*x)*P(n-1,x) + (8*x-8*x^2)*d/dx P(n-1,x) for n >= 1, with P(0,x) = 1.","mathematica":"P[0, x_] := 1;\nP[n_, x_] := P[n, x] = Expand[(2 + (8*n - 6)*x)*P[n - 1, x] + (8*x - 8*x^2)*D[P[n - 1, x], x]];\nTable[Reverse[PadRight[CoefficientList[P[n, x], x], n + 1]], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = (2 + (8*n - 6)*x)*v[i - 1] + (8*x - 8*x^2)*deriv(v[i - 1], x)); v};\nrow(n, p) = {my(c = Vecrev(p)); c = concat(c, vector(n + 1 - #c)); c = Vecrev(c); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, 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