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55640825856,     85006817280,      77922915840,      42857603712,     13095378912,      1714871048;\n  7:   42568187904,   312166711296,   1001534865408,   1836147253248,    2103918727680,    1542873733632,    707150461248,    185206073184,     21221529219;\n  8:  567575838720,  4682500669440,  17169169121280,  36722945064960,   50494049464320,   46286212008960,  28286018449920,  11112364391040,   2546583506280,   259374246010;\n  9: 7492001071104, 68676676485120, 283291290501120, 692489821224960, 1110869088215040, 1221955997036544, 933438608847360, 488944033205760, 168074511414480, 34237400473320, 3138428376721;\n","recurrence_sentence":"The row polynomials satisfy (n+1)*P(n,x) = (12*n+24+(11*n+22)*x)*P(n-1,x) for n >= 1, with P(0,x) = 264 + 242*x.","mathematica":"P[0, x_] := 264 + 242*x;\nP[n_, x_] := P[n, x] = Expand[Together[((12*n + 24 + (11*n + 22)*x)*P[n - 1, x])/(n + 1)]];\nTable[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); v[1] = 264 + 242*x; for(n = 1, N, my(i = n + 1); v[i] = ((12*n + 24 + (11*n + 22)*x)*v[i - 1])/(n + 1)); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false}}],"derivation":{"root":"n-344e4bfa9933088a","steps":["D"],"edges":["e-552f58accfe91872"],"text":"A038337 \u2192 D"},"headline":"A038337 \u2192 D","chain":null}