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  8639649091584,    23519044749312,    36585180721152,    35568925701120,    22131775991808,     8606801774592,     1912622616576,     185949421056;\n  8:  27770300651520,  194392104560640,   604775436410880,  1097555421634560,  1280481325240320,   995929919631360,   516408106475520,   172136035491840,   33470895790080,   2892546549760;\n  9: 549851952900096, 4276626300334080, 14968192051169280, 31045139069091840, 42255883732930560, 39438824817401856, 25562201270538240, 11360978342461440, 3313618683217920, 572724216852480, 44545216866304;\n","recurrence_sentence":"The row polynomials satisfy (n+1)*P(n,x) = (18*n+36+(14*n+28)*x)*P(n-1,x) for n >= 1, with P(0,x) = 504 + 392*x.","mathematica":"P[0, x_] := 504 + 392*x;\nP[n_, x_] := P[n, x] = Expand[Together[((18*n + 36 + (14*n + 28)*x)*P[n - 1, x])/(n + 1)]];\nTable[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); v[1] = 504 + 392*x; for(n = 1, N, my(i = n + 1); v[i] = ((18*n + 36 + (14*n + 28)*x)*v[i - 1])/(n + 1)); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false}}],"derivation":{"root":"n-7dcf11eddf2b9a8a","steps":["basis A013609","D"],"edges":["e-322a2e4c0bbd3231","e-49464b0b3f306e05"],"text":"A038321 \u2192 basis A013609 \u2192 D"},"headline":"A038321 \u2192 basis A013609 \u2192 D","chain":null}