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v[1] = 1; for(n = 2, N, my(i = n); v[i] = -(1 - x)*v[i - 1] - deriv(v[i - 1], x)); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i, v[i])))};\nT(10)","reading":{"first_row":1,"offset":1,"reversed":false,"trim_zeros":"none","regular_triangle":false}},{"oeis_id":"A159834","target":"triangle","first_row":1,"oeis_offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":true,"rows_shown":10,"polytool_commit":"c48629374597092cc41ef4d6273f37991516f984","triangle_example":"Triangle begins:\n  0:    1;\n  1:   -1,     1;\n  2:    0,    -2,    1;\n  3:    2,     0,   -3,    1;\n  4:   -2,     8,    0,   -4,    1;\n  5:   -6,   -10,   20,    0,   -5,    1;\n  6:   16,   -36,  -30,   40,    0,   -6,   1;\n  7:   20,   112, -126,  -70,   70,    0,  -7,  1;\n  8: -132,   160,  448, -336, -140,  112,   0, -8,  1;\n  9:  -28, -1188,  720, 1344, -756, -252, 168,  0, -9, 1;\n","recurrence_sentence":"The row polynomials satisfy P(n,x) = -(1-x)*P(n-1,x) - d/dx P(n-1,x) for n >= 1, with P(0,x) = 1.","mathematica":"P[0, x_] := 1;\nP[n_, x_] := P[n, x] = Expand[-(1 - x)*P[n - 1, x] - D[P[n - 1, x], x]];\nTable[PadRight[CoefficientList[P[n, x], x], n + 1], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); 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