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48945364992, 22939435008, 8001552384, 2027225088, 357826560, 40894464, 2621440, 65536;\n 9: 191476224, 3204707328, 24730665984, 116740030464, 377147695104, 884149862400, 1556354580480, 2100317257728, 2199822188544, 1799210631168, 1150320476160, 572671918080, 219906441216, 64061964288, 13780647936, 2095054848, 208797696, 11796480, 262144;\n","recurrence_sentence":"The row polynomials satisfy (6*n-3+(4*n+2)*x+2*x^2)*P(n,x) = (36*n+18+(96*n+72)*x+(72*n+96)*x^2+(16*n+48)*x^3+8*x^4)*P(n-1,x) for n >= 1, with P(0,x) = 1.","mathematica":"P[0, x_] := 1;\nP[n_, x_] := P[n, x] = Expand[Together[((36*n + 18 + (96*n + 72)*x + (72*n + 96)*x^2 + (16*n + 48)*x^3 + 8*x^4)*P[n - 1, x])/(6*n - 3 + (4*n + 2)*x + 2*x^2)]];\nTable[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = ((36*n + 18 + (96*n + 72)*x + (72*n + 96)*x^2 + (16*n + 48)*x^3 + 8*x^4)*v[i - 1])/(6*n - 3 + (4*n + 2)*x + 2*x^2)); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false}}],"derivation":{"root":"n-d3c3090977105807","steps":["basis A013609","D+1"],"edges":["e-e79851ce4a3e511f","e-d04045d7a505d10f"],"text":"A272867 \u2192 basis A013609 \u2192 D+1"},"headline":"A272867 \u2192 basis A013609 \u2192 D+1","chain":null}