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Branden, arXiv:1410.6601: sum_k f(k) x^k / k! = f(theta) e^x = C e^x x^m prod (1 + x/a_j), a_j > 0); f(k) has one sign for k >= 0, so coefficients of one sign stay of one sign; applied to f(n, .) for each n","lean_route":null,"lean_declarations":["RealRooted.isMultiplierSequence_eval_of_roots_nonpos","RealRooted.isPFMultiplierSequence_eval_of_roots_nonpos","RealRooted.isMultiplierSequence_iff_preserves"],"certificate_hash":"21c6ac35c4c40a441b4cec5dce82350ba63cece19b05a82e73d8e70cec027e6b","verification_polytool":"replayed","verification_lean":"not_attempted","claims":[{"claim":"real_rooted","from_index":0,"region":{"upper":{"closed":true,"value":"0"}}},{"claim":"interlacing","from_index":1,"kind":"weak","orientation":"unordered"}],"premises":[{"position":0,"node_id":"n-ff0214c333bfdcca","role":"sequence","name":"Triangle whose (n,k)-th entry is 15^(n-k)*binomial(n,k).","uses":{"claim":"real_rooted","from_index":0,"region":{"upper":{"closed":true,"value":"0"}}},"uses_text":"Every row P_n, n >= 0, is zero or real-rooted with all roots in (-inf, 0]"}]}],"used_by":[],"used_by_total":0,"links":[],"oeis":[],"bfiles":[],"oeis_texts":[{"oeis_id":"","target":"node","first_row":0,"oeis_offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false,"rows_shown":10,"polytool_commit":"c48629374597092cc41ef4d6273f37991516f984","triangle_example":"Triangle begins:\n  0:           1;\n  1:          15,           2;\n  2:         225,          60,           3;\n  3:        3375,        1350,         135,          4;\n  4:       50625,       27000,        4050,        240,         5;\n  5:      759375,      506250,      101250,       9000,       375,        6;\n  6:    11390625,     9112500,     2278125,     270000,     16875,      540,       7;\n  7:   170859375,   159468750,    47840625,    7087500,    590625,    28350,     735,     8;\n  8:  2562890625,  2733750000,   956812500,  170100000,  17718750,  1134000,   44100,   960,    9;\n  9: 38443359375, 46132031250, 18452812500, 3827250000, 478406250, 38272500, 1984500, 64800, 1215, 10;\n","recurrence_sentence":"The row polynomials satisfy (15+n*x)*P(n,x) = (225+(15*n+30)*x+(n+1)*x^2)*P(n-1,x) for n >= 1, with P(0,x) = 1.","mathematica":"P[0, x_] := 1;\nP[n_, x_] := P[n, x] = Expand[Together[((225 + (15*n + 30)*x + (n + 1)*x^2)*P[n - 1, x])/(15 + n*x)]];\nTable[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = ((225 + (15*n + 30)*x + (n + 1)*x^2)*v[i - 1])/(15 + n*x)); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false}}],"derivation":{"root":"n-ff0214c333bfdcca","steps":["\u03b8+1"],"edges":["e-2f785a440f745a98"],"text":"A027467 \u2192 \u03b8+1"},"headline":"A027467 \u2192 \u03b8+1","chain":null}
