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begins:\n  0: 1;\n  1: 2;\n  2: 2,  2;\n  3: 2,  6;\n  4: 2, 12,   2;\n  5: 2, 20,  10;\n  6: 2, 30,  30,   2;\n  7: 2, 42,  70,  14;\n  8: 2, 56, 140,  56,  2;\n  9: 2, 72, 252, 168, 18;\n","recurrence_sentence":"The row polynomials satisfy (n-2)*P(n,x) = (2*n-4)*P(n-1,x) - (n-2-(n-2)*x)*P(n-2,x) for n >= 3, with P(0,x) = 1, P(1,x) = 2, P(2,x) = 2 + 2*x.","mathematica":"P[0, x_] := 1;\nP[1, x_] := 2;\nP[2, x_] := 2 + 2*x;\nP[n_, x_] := P[n, x] = Expand[Together[((2*n - 4)*P[n - 1, x] - (n - 2 - (n - 2)*x)*P[n - 2, x])/(n - 2)]];\nTable[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); v[1] = 1; v[2] = 2; v[3] = 2 + 2*x; for(n = 3, N, my(i = n + 1); v[i] = ((2*n - 4)*v[i - 1] - (n - 2 - (n - 2)*x)*v[i - 2])/(n - 2)); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, 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v[2] = 2; v[3] = 2 + 2*x; for(n = 3, N, my(i = n + 1); v[i] = ((2*n - 4)*v[i - 1] - (n - 2 - (n - 2)*x)*v[i - 2])/(n - 2)); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false}}],"derivation":{"root":"n-ced86a7ce48c966e","steps":[],"edges":[],"text":"A119462"},"headline":"A119462: Triangle read by rows: T(n,k) is the number of circular binary words of length n having k occurrences of 01 (0 <= k <= floor(n/2)).","chain":null}
