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(f(k))_(k >= 0) is a multiplier sequence, so x^k -> f(k) x^k maps every real-rooted polynomial to a real-rooted polynomial or zero (Laguerre; see T. Craven and G. Csordas, Multiplier sequences for fields, Illinois J. Math. 21 (1977); Polya--Schur, Theorem 40 of P. Branden, arXiv:1410.6601: sum_k f(k) x^k / k! = f(theta) e^x = C e^x x^m prod (1 + x/a_j), a_j > 0); f(k) has one sign for k >= 0, so coefficients of one sign stay of one sign; applied to f(n, .) for each n","lean_route":null,"lean_declarations":["RealRooted.isMultiplierSequence_eval_of_roots_nonpos","RealRooted.isPFMultiplierSequence_eval_of_roots_nonpos","RealRooted.isMultiplierSequence_iff_preserves"],"certificate_hash":"bb07934d990d7d62f405b9b7efe3ae5dcd6b351eb08f5251d15572ebe98690c9","verification_polytool":"replayed","verification_lean":"not_attempted","claims":[{"claim":"real_rooted","from_index":0,"region":{"upper":{"closed":true,"value":"0"}}},{"claim":"interlacing","from_index":1,"kind":"weak","orientation":"unordered"}],"premises":[{"position":0,"node_id":"n-b8a3f88eab200094","role":"sequence","name":"basis_map_A013611 of Triangle whose (i,j)-th entry is binomial(i,j)*10^(i-j)*3^j.","uses":{"claim":"real_rooted","from_index":0,"region":{"upper":{"closed":true,"value":"0"}}},"uses_text":"Every row P_n, n >= 0, is zero or real-rooted with all roots in (-inf, 0]"}]}],"used_by":[],"used_by_total":0,"links":[],"oeis":[],"bfiles":[],"oeis_texts":[{"oeis_id":"","target":"node","first_row":0,"oeis_offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false,"rows_shown":10,"polytool_commit":"c48629374597092cc41ef4d6273f37991516f984","triangle_example":"Triangle begins:\n  0:           169,           1248,            1296;\n  1:          2197,          24336,           50544,            27648;\n  2:         28561,         421824,         1314144,          1437696,            518400;\n  3:        371293,        6854640,        28473120,         46725120,          33696000,           8957952;\n  4:       4826809,      106932384,       555225840,       1214853120,        1314144000,         698720256,         146313216;\n  5:      62748517,     1621807824,     10105110288,      27637908480,       39862368000,       31791771648,       13314502656,        2293235712;\n  6:     815730721,    24095430528,    175155244992,     574868496384,     1036421568000,     1102114750464,      692354138112,      238496514048,       34828517376;\n  7:   10604499373,   352395671472,   2927594809152,   11209935679488,    24252264691200,    32236856451072,    27001811386368,    13952046071808,     4074936532992,     515978035200;\n  8:  137858491849,  5090159699040,  47573415648720,  208184519761920,   525465734976000,   838158267727872,   877558870056960,   604588663111680,   264870874644480,   67077144576000,    7492001071104;\n  9: 1792160394037, 72789283696272, 755888715307440, 3721298290744320, 10734514300224000, 19976105380847616, 25098183683629056, 21614044706242560, 12625511691386880, 4796015837184000, 1071356153167872, 106993205379072;\n","recurrence_sentence":"The row polynomials satisfy (169+(468*n+780)*x+(144*n^2+576*n+576)*x^2)*P(n,x) = (2197+(6084*n+18252)*x+(1872*n^2+16848*n+31824)*x^2+(1728*n^2+10368*n+15552)*x^3)*P(n-1,x) for n >= 1, with P(0,x) = 169 + 1248*x + 1296*x^2.","mathematica":"P[0, x_] := 169 + 1248*x + 1296*x^2;\nP[n_, x_] := P[n, x] = Expand[Together[((2197 + (6084*n + 18252)*x + (1872*n^2 + 16848*n + 31824)*x^2 + (1728*n^2 + 10368*n + 15552)*x^3)*P[n - 1, x])/(169 + (468*n + 780)*x + (144*n^2 + 576*n + 576)*x^2)]];\nTable[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); v[1] = 169 + 1248*x + 1296*x^2; for(n = 1, N, my(i = n + 1); v[i] = ((2197 + (6084*n + 18252)*x + (1872*n^2 + 16848*n + 31824)*x^2 + (1728*n^2 + 10368*n + 15552)*x^3)*v[i - 1])/(169 + (468*n + 780)*x + (144*n^2 + 576*n + 576)*x^2)); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false}}],"derivation":{"root":"n-4397e742863fdbe2","steps":["basis A013611","(\u03b8+1)\u00b2"],"edges":["e-7b93be005ec5b750","e-9dd814c9d2d83b42"],"text":"A038305 \u2192 basis A013611 \u2192 (\u03b8+1)\u00b2"},"headline":"A038305 \u2192 basis A013611 \u2192 (\u03b8+1)\u00b2","chain":null}
