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110075314176,      807218970624,     2589827530752,      4748017139712,      5440436305920,      3989653291008,      1828591091712,       478916714496,        54875873536;\n  7:    2641807540224,    21794912206848,    79914678091776,    170928617029632,    235026848415744,    215441277714432,    131658558603264,     51723005165568,     11853188683776,     1207269217792;\n  8:   63403380965376,   581197658849280,  2397440342753280,   5860409726730240,   9401073936629760,  10341181330292736,   7899513516195840,   4137840413245440,   1422382642053120,   289744612270080,   26559922791424;\n  9: 1521681143169024, 15343618193620992, 70324916720762880, 193393520982097920, 354554788467179520, 455011978532880384, 417094313655140352, 273097467274199040, 125169672500674560, 38246288819650560, 7011819616935936, 584318301411328;\n","recurrence_sentence":"The row polynomials satisfy P(n,x) = (24+22*x)*P(n-1,x) for n >= 1, with P(0,x) = 576 + 1056*x + 484*x^2.","mathematica":"P[0, x_] := 576 + 1056*x + 484*x^2;\nP[n_, x_] := P[n, x] = Expand[(24 + 22*x)*P[n - 1, x]];\nTable[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); v[1] = 576 + 1056*x + 484*x^2; for(n = 1, N, my(i = n + 1); v[i] = (24 + 22*x)*v[i - 1]); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false}}],"derivation":{"root":"n-29d7c5a1e19b9d74","steps":["basis A013609","reverse"],"edges":["e-61350e73fec19600","e-30873dcc984978cd"],"text":"A038314 \u2192 basis A013609 \u2192 reverse"},"headline":"A038314 \u2192 basis A013609 \u2192 reverse","chain":null}