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78364164096;\n  6:     377801998336,      3885963411456,     17486835351552,      44966148046848,      72267023646720,       74331795750912,       47784725839872,       17553572757504,        2821109907456;\n  7:   10578455953408,    122407847460864,    629526072655872,    1888578217967616,    3642257991794688,     4682903132307456,     4013916970549248,     2211750167445504,      710919696678912,     101559956668416;\n  8:  296196766695424,   3808244143226880,  22033412542955520,   75543128718704640,  169972039617085440,   262242575409217536,   280974187938447360,   206430015628247040,    99528757535047680,   28436787867156480,    3656158440062976;\n  9: 8293509467471872, 117293919611387904, 754032340358922240, 2908410455670128640, 7478769743151759360, 13461785537673166848, 17308009977008357376, 15895111203375022080, 10218285773598228480, 4379265331542097920, 1126096799539396608, 131621703842267136;\n","recurrence_sentence":"The row polynomials satisfy P(n,x) = (28+36*x)*P(n-1,x) for n >= 1, with P(0,x) = 784 + 2016*x + 1296*x^2.","mathematica":"P[0, x_] := 784 + 2016*x + 1296*x^2;\nP[n_, x_] := P[n, x] = Expand[(28 + 36*x)*P[n - 1, x]];\nTable[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); v[1] = 784 + 2016*x + 1296*x^2; for(n = 1, N, my(i = n + 1); v[i] = (28 + 36*x)*v[i - 1]); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false}}],"derivation":{"root":"n-a93042cd70c4761e","steps":["basis A013610","basis A013610"],"edges":["e-77aaa200c8a95097","e-9dfa1f1d35351bc0"],"text":"A038330 \u2192 basis A013610 \u2192 basis A013610"},"headline":"A038330 \u2192 basis A013610 \u2192 basis A013610","chain":null}