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Branden, arXiv:1410.6601: sum_k f(k) x^k / k! = f(theta) e^x = C e^x x^m prod (1 + x/a_j), a_j > 0); f(k) has one sign for k >= 0, so coefficients of one sign stay of one sign; applied to f(n, .) for each n","lean_route":null,"lean_declarations":["RealRooted.isMultiplierSequence_eval_of_roots_nonpos","RealRooted.isPFMultiplierSequence_eval_of_roots_nonpos","RealRooted.isMultiplierSequence_iff_preserves"],"certificate_hash":"be51b288c1c58c79ca2c2ce1c8bf03d6fe1a1726c6eee2dc2124f74ccb232dec","verification_polytool":"replayed","verification_lean":"not_attempted","claims":[{"claim":"real_rooted","from_index":0,"region":{"upper":{"closed":true,"value":"0"}}},{"claim":"interlacing","from_index":1,"kind":"weak","orientation":"unordered"}],"premises":[{"position":0,"node_id":"n-3deb3ea1ada5b4a1","role":"sequence","name":"basis_map_A013611 of Triangle of coefficients in expansion of (1+4x)^n.","uses":{"claim":"real_rooted","from_index":0,"region":{"upper":{"closed":true,"value":"0"}}},"uses_text":"Every row P_n, n >= 0, is zero or real-rooted with all roots in (-inf, 0]"}]}],"used_by":[],"used_by_total":0,"links":[],"oeis":[],"bfiles":[],"oeis_texts":[{"oeis_id":"","target":"node","first_row":0,"oeis_offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false,"rows_shown":10,"polytool_commit":"c48629374597092cc41ef4d6273f37991516f984","triangle_example":"Triangle begins:\n  0:       1;\n  1:       5,        64;\n  2:      25,       640,       2304;\n  3:     125,      4800,      34560,       65536;\n  4:     625,     32000,     345600,     1310720,      1638400;\n  5:    3125,    200000,    2880000,    16384000,     40960000,      37748736;\n  6:   15625,   1200000,   21600000,   163840000,    614400000,    1132462080,     822083584;\n  7:   78125,   7000000,  151200000,  1433600000,   7168000000,   19818086400,   28772925440,    17179869184;\n  8:  390625,  40000000, 1008000000, 11468800000,  71680000000,  264241152000,  575458508800,   687194767360,   347892350976;\n  9: 1953125, 225000000, 6480000000, 86016000000, 645120000000, 2972712960000, 8631877632000, 15461882265600, 15655155793920, 6871947673600;\n","recurrence_sentence":"The row polynomials satisfy (25+(240*n-80)*x+256*n^2*x^2)*P(n,x) = (125+(1200*n+1200)*x+(1280*n^2+6400*n+3840)*x^2+(4096*n^2+8192*n+4096)*x^3)*P(n-1,x) for n >= 1, with P(0,x) = 1.","mathematica":"P[0, x_] := 1;\nP[n_, x_] := P[n, x] = Expand[Together[((125 + (1200*n + 1200)*x + (1280*n^2 + 6400*n + 3840)*x^2 + (4096*n^2 + 8192*n + 4096)*x^3)*P[n - 1, x])/(25 + (240*n - 80)*x + 256*n^2*x^2)]];\nTable[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = ((125 + (1200*n + 1200)*x + (1280*n^2 + 6400*n + 3840)*x^2 + (4096*n^2 + 8192*n + 4096)*x^3)*v[i - 1])/(25 + (240*n - 80)*x + 256*n^2*x^2)); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false}}],"derivation":{"root":"n-2e0409c0014ec240","steps":["basis A013611","(\u03b8+1)\u00b2"],"edges":["e-189a8da608edbb49","e-7a4c53b34be22b52"],"text":"A013611 \u2192 basis A013611 \u2192 (\u03b8+1)\u00b2"},"headline":"A013611 \u2192 basis A013611 \u2192 (\u03b8+1)\u00b2","chain":null}
