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the step is Ma and Wang, EJC 15 (2008) R17, Theorem 2)","lean_route":null,"lean_declarations":[],"certificate_hash":"9792a39decb8dd17d33238eda2a10e9ef5ce58cf9ed1b2deafb326453f312cd3","verification_polytool":"replayed","verification_lean":"not_attempted","claims":[{"claim":"real_rooted","from_index":0,"region":{"upper":{"closed":true,"value":"0"}}}],"premises":[{"position":0,"node_id":"n-b636fb6adf08770c","role":"sequence","name":"The (1,2)-Pascal triangle (or Lucas triangle) read by rows.","uses":{"claim":"real_rooted","from_index":0,"region":{"upper":{"closed":true,"value":"0"}}},"uses_text":"Every row P_n, n >= 0, is zero or real-rooted with all roots in (-inf, 0]"}]}],"used_by":[],"used_by_total":0,"links":[],"oeis":[],"bfiles":[],"oeis_texts":[{"oeis_id":"","target":"node","first_row":0,"oeis_offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false,"rows_shown":10,"polytool_commit":"c48629374597092cc41ef4d6273f37991516f984","triangle_example":"Triangle begins:\n  0:   2;\n  1:   3,     2;\n  2:   6,     9,      2;\n  3:  12,    33,     17,      2;\n  4:  24,   111,    101,     27,      2;\n  5:  48,   357,    515,    236,     39,      2;\n  6:  96,  1119,   2417,   1695,    470,     53,     2;\n  7: 192,  3453,  10787,  10892,   4515,    841,    69,    2;\n  8: 384, 10551,  46601,  65247,  37982,  10402,  1393,   87,   2;\n  9: 768, 32037, 196955, 372836, 293139, 110796, 21546, 2176, 107, 2;\n","recurrence_sentence":"The row polynomials satisfy (n-1)*P(n,x) = (2*n-2+(n-1)*x)*P(n-1,x) + (n-1)*x*d/dx P(n-1,x) for n >= 2, with P(0,x) = 2, P(1,x) = 3 + 2*x.","mathematica":"P[0, x_] := 2;\nP[1, x_] := 3 + 2*x;\nP[n_, x_] := P[n, x] = Expand[Together[((2*n - 2 + (n - 1)*x)*P[n - 1, x] + (n - 1)*x*D[P[n - 1, x], x])/(n - 1)]];\nTable[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); v[1] = 2; v[2] = 3 + 2*x; for(n = 2, N, my(i = n + 1); v[i] = ((2*n - 2 + (n - 1)*x)*v[i - 1] + (n - 1)*x*deriv(v[i - 1], x))/(n - 1)); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false}}],"derivation":{"root":"n-b636fb6adf08770c","steps":["basis A008277"],"edges":["e-85f08c5fc83cf41e"],"text":"A029635 \u2192 basis A008277"},"headline":"A029635 \u2192 basis A008277","chain":null}
