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2380855680;\n  9: 26940211200, 326069452800, 1730676326400, 5267275776000, 10073664921600, 12443939020800, 9777380659200, 4571242905600, 1071385056000, 71425670400;\n","recurrence_sentence":"The row polynomials satisfy (3*n-1+3*x)*P(n,x) = (6*n^2+10*n+4+(9*n^2+21*n+12)*x+(9*n+9)*x^2)*P(n-1,x) for n >= 1, with P(0,x) = 1.","mathematica":"P[0, x_] := 1;\nP[n_, x_] := P[n, x] = Expand[Together[((6*n^2 + 10*n + 4 + (9*n^2 + 21*n + 12)*x + (9*n + 9)*x^2)*P[n - 1, x])/(3*n - 1 + 3*x)]];\nTable[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = ((6*n^2 + 10*n + 4 + (9*n^2 + 21*n + 12)*x + (9*n + 9)*x^2)*v[i - 1])/(3*n - 1 + 3*x)); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false}}],"derivation":{"root":"n-75a6475b3e851dc5","steps":["basis A013610","D+1"],"edges":["e-1eb90284df2d6b2d","e-e84daa17ad2ecf03"],"text":"A156992 \u2192 basis A013610 \u2192 D+1"},"headline":"A156992 \u2192 basis A013610 \u2192 D+1","chain":null}