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483385147392, 2537772023808, 8882202083328, 20725138194432, 31087707291648, 27201743880192, 10578455953408;\n","recurrence_sentence":"The row polynomials satisfy (1+x)*P(n,x) = (8+36*x+28*x^2)*P(n-1,x) for n >= 1, with P(0,x) = 1.","mathematica":"P[0, x_] := 1;\nP[n_, x_] := P[n, x] = Expand[Together[((8 + 36*x + 28*x^2)*P[n - 1, x])/(1 + x)]];\nTable[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = ((8 + 36*x + 28*x^2)*v[i - 1])/(1 + x)); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false}}],"derivation":{"root":"n-c44f7114310405ad","steps":["basis A013611","x \u21a6 x/(x+1)"],"edges":["e-96f2019a633e1196","e-7f720102102753d9"],"text":"A013622 \u2192 basis A013611 \u2192 x \u21a6 x/(x+1)"},"headline":"A013622 \u2192 basis A013611 \u2192 x \u21a6 x/(x+1)","chain":null}