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Branden, arXiv:1410.6601: sum_k f(k) x^k / k! = f(theta) e^x = C e^x x^m prod (1 + x/a_j), a_j > 0); f(k) has one sign for k >= 0, so coefficients of one sign stay of one sign; applied to f(n, .) for each n","lean_route":null,"lean_declarations":["RealRooted.isMultiplierSequence_eval_of_roots_nonpos","RealRooted.isPFMultiplierSequence_eval_of_roots_nonpos","RealRooted.isMultiplierSequence_iff_preserves"],"certificate_hash":"454a609f40a29b9e459ebbf79c7d6e84db840bc545d790e851a774f262f37f74","verification_polytool":"replayed","verification_lean":"not_attempted","claims":[{"claim":"real_rooted","from_index":0,"region":{"upper":{"closed":true,"value":"0"}}}],"premises":[{"position":0,"node_id":"n-fabb0a68e001a863","role":"sequence","name":"Triangle of cubed binomial coefficients, T(n,k) = C(n,k)^3, read by rows.","uses":{"claim":"real_rooted","from_index":0,"region":{"upper":{"closed":true,"value":"0"}}},"uses_text":"Every row P_n, n >= 0, is zero or real-rooted with all roots in (-inf, 0]"}]}],"used_by":[],"used_by_total":0,"links":[],"oeis":[],"bfiles":[],"oeis_texts":[{"oeis_id":"","target":"node","first_row":0,"oeis_offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false,"rows_shown":10,"polytool_commit":"c48629374597092cc41ef4d6273f37991516f984","triangle_example":"Triangle begins:\n  0: 1;\n  1: 1,    2;\n  2: 1,   16,      3;\n  3: 1,   54,     81,       4;\n  4: 1,  128,    648,     256,        5;\n  5: 1,  250,   3000,    4000,      625,        6;\n  6: 1,  432,  10125,   32000,    16875,     1296,       7;\n  7: 1,  686,  27783,  171500,   214375,    55566,    2401,      8;\n  8: 1, 1024,  65856,  702464,  1715000,  1053696,  153664,   4096,    9;\n  9: 1, 1458, 139968, 2370816, 10001880, 12002256, 4148928, 373248, 6561, 10;\n","recurrence_sentence":"The row polynomials satisfy (n^2+n^5*x)*P(n,x) = (n^2+(n^5+20*n^2-30*n+12)*x+(10*n^5-18*n^3+10*n^2)*x^2)*P(n-1,x) + ((3*n+6)*x+(3*n^4+6*n^3-15*n+24)*x^2-(15*n^4+6*n^3-30*n^2)*x^3)*d/dx P(n-1,x) + (6*x^2+(6*n^3+10*n^2+6)*x^3+(6*n^3+10*n^2)*x^4)*d^2/dx^2 P(n-1,x) for n >= 1, with P(0,x) = 1.","mathematica":"P[0, x_] := 1;\nP[n_, x_] := P[n, x] = Expand[Together[((n^2 + (n^5 + 20*n^2 - 30*n + 12)*x + (10*n^5 - 18*n^3 + 10*n^2)*x^2)*P[n - 1, x] + ((3*n + 6)*x + (3*n^4 + 6*n^3 - 15*n + 24)*x^2 - (15*n^4 + 6*n^3 - 30*n^2)*x^3)*D[P[n - 1, x], x] + (6*x^2 + (6*n^3 + 10*n^2 + 6)*x^3 + (6*n^3 + 10*n^2)*x^4)*D[P[n - 1, x], {x, 2}])/(n^2 + n^5*x)]];\nTable[CoefficientList[P[n, x], x], {n, 0, 9}] // Flatten","pari":"P(N) = {my(v = vector(N + 1)); v[1] = 1; for(n = 1, N, my(i = n + 1); v[i] = ((n^2 + (n^5 + 20*n^2 - 30*n + 12)*x + (10*n^5 - 18*n^3 + 10*n^2)*x^2)*v[i - 1] + ((3*n + 6)*x + (3*n^4 + 6*n^3 - 15*n + 24)*x^2 - (15*n^4 + 6*n^3 - 30*n^2)*x^3)*deriv(v[i - 1], x) + (6*x^2 + (6*n^3 + 10*n^2 + 6)*x^3 + (6*n^3 + 10*n^2)*x^4)*deriv(deriv(v[i - 1], x), x))/(n^2 + n^5*x)); v};\nrow(n, p) = {my(c = Vecrev(p)); c};\nT(N) = {my(v = P(N)); concat(vector(#v, i, row(i - 1, v[i])))};\nT(9)","reading":{"first_row":0,"offset":0,"reversed":false,"trim_zeros":"none","regular_triangle":false}}],"derivation":{"root":"n-fabb0a68e001a863","steps":["\u03b8+1"],"edges":["e-21dc18e24ad527f8"],"text":"A181543 \u2192 \u03b8+1"},"headline":"A181543 \u2192 \u03b8+1","chain":null}
